{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "APPENDIX A-3: APPLICABLE SECTIONS OF THE NATIONAL ELECTRIC CODE(NEC)" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1, Page number 594" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Variable declaration\n", "hp = 5.0 #Power rating of motor(hp)\n", "V = 220.0 #Voltage rating of motor(V)\n", "Va_a = 180.0 #Armature voltage(V)\n", "Va_b = 240.0 #Armature voltage(V)\n", "\n", "#Calculation\n", "I1 = 27.0 #Current(A). From Appendix A-3 table for 180V\n", "I_L1 = I1*(Va_a/V) #Full load current(A)\n", "I2 = 20.0 #Current(A). From Appendix A-3 table for 240V\n", "I_L2 = I2*(Va_b/V) #Full load current(A)\n", "\n", "#Result\n", "print('Case(a): Full-load current for armature voltage of 180 V , I_L1 = %.f A' %I_L1)\n", "print('Case(b): Full-load current for armature voltage of 240 V , I_L2 = %.f A' %I_L2)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Case(a): Full-load current for armature voltage of 180 V , I_L1 = 22 A\n", "Case(b): Full-load current for armature voltage of 240 V , I_L2 = 22 A\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 2, Page number 594" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Variable declaration\n", "hp = 10.0 #Power rating of motor(hp)\n", "V = 600.0 #Voltage rating of motor(V)\n", "Va = 550.0 #Armature voltage(V)\n", "\n", "#Calculation\n", "I = 16.0 #Current(A). From Appendix A-3 table for 550 V\n", "I_L = I*(Va/V) #Full load current(A)\n", "\n", "#Result\n", "print('Line current at rated load , I_L = %.1f A' %I_L)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Line current at rated load , I_L = 14.7 A\n" ] } ], "prompt_number": 1 } ], "metadata": {} } ] }