{
"metadata": {
"name": "",
"signature": "sha256:c5ab44aeefcd14a70c068db0add65ea39fa6bef29922dd16383e688b74325b23"
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"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter No 11:Integrated Circuit Technologies"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-1, Page NO:456"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"print'The propogation delay times,tphl and tlph,are indicated in part (B) of the figure.In this case,the delays are measured between the 50% points of the corresponding edges of the input and output pulses.The values of tphl and tplh are not necessarily equal but in many cases they are the same.'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The propogation delay times,tphl and tlph,are indicated in part (B) of the figure.In this case,the delays are measured between the 50% points of the corresponding edges of the input and output pulses.The values of tphl and tplh are not necessarily equal but in many cases they are the same.\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-2, Page NO:457"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#variable:\n",
"V=5 #Vcc\n",
"I=1*10**-3 #Icch\n",
"K=2.5*10**-3 #Iccl\n",
"\n",
"#Equation:\n",
"P=V*(I+K)/2\n",
"S=5*10**-9*P\n",
"\n",
"#Solutions:\n",
"print\"Pd=\",P,\"W\"\n",
"print\"SPP=\",S,\"J\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Pd= 0.00875 W\n",
"SPP= 4.375e-11 J\n"
]
}
],
"prompt_number": 19
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-3, Page NO:465"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"print'(a) For 5V CMOS:'\n",
"#variable declaration\n",
"Vih=3.5\n",
"Vil=1.5\n",
"Voh=4.4\n",
"Vol=0.33\n",
"\n",
"#Formula\n",
"Vnh=Voh-Vih\n",
"Vnl=Vil-Vol\n",
"\n",
"\n",
"#Solutions:\n",
"print'Vnh=',Vnh,'V'\n",
"print'Vnl=',Vnl,'V'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a) For 5V CMOS:\n",
"Vnh= 0.9 V\n",
"Vnl= 1.17 V\n"
]
}
],
"prompt_number": 22
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"print'(b) For TTL:'\n",
"#variable declaration\n",
"Vih=2\n",
"Vil=0.8\n",
"Voh=2.4\n",
"Vol=0.4\n",
"\n",
"#Formula\n",
"Vnh=Voh-Vih\n",
"Vnl=Vil-Vol\n",
"\n",
"\n",
"#Solutions:\n",
"print'Vnh=',Vnh,'V'\n",
"print'Vnl=',Vnl,'V'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(b) For TTL:\n",
"Vnh= 0.4 V\n",
"Vnl= 0.4 V\n"
]
}
],
"prompt_number": 23
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-4,Page NO:516"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#variable declaration\n",
"Vcc=5\n",
"Icch=2*10**-6\n",
"Iccl=3.6*10**-6\n",
"\n",
"#Formula\n",
"Icc=(Icch+Iccl)/2\n",
"Pd=Vcc*Icc\n",
"\n",
"\n",
"#Solutions:\n",
"print'Average Icc=',Icc,'A'\n",
"print'Average Power dissipation Pd=',Pd,'W'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Average Icc= 2.8e-06 A\n",
"Average Power dissipation Pd= 1.4e-05 W\n"
]
}
],
"prompt_number": 25
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-5, Page NO:481"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"print'Total source current(in HIGH output state):'\n",
"print'Iih(max)=40*10**-6 A per input.'\n",
"print'It(source)=5inputs*40*10**-6/input= 200*10**-6 A'\n",
"print'Total source current(in LOW output state):'\n",
"print'Iil(max)=-1.6*10**-6 A per input.'\n",
"print'It(source)=5inputs*-1.6*10**-6/input=-8*10**-6 A'\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Total source current(in HIGH output state):\n",
"Iih(max)=40*10**-6 A per input.\n",
"It(source)=5inputs*40*10**-6/input= 200*10**-6 A\n",
"Total source current(in LOW output state):\n",
"Iil(max)=-1.6*10**-6 A per input.\n",
"It(source)=5inputs*-1.6*10**-6/input=-8*10**-6 A\n"
]
}
],
"prompt_number": 29
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-6,Page NO:481"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"print'According to Datasheet, the current parameters are as follows:'\n",
"\n",
"#Variable Declaration\n",
"Iih=40*10**-6\n",
"Ioh=400*10**-6\n",
"Iil=1.6*10**-3\n",
"Iol=16*10**-3\n",
"\n",
"#Formula:\n",
"HF=Ioh/Iih\n",
"LW=Iol/Iil\n",
"\n",
"#Solutions:\n",
"print'Fan-out for the HIGH output state is calculated as follows:Current Ioh(max) is the maximum current that the gate can source to a load..Each load input requires an Iih(max) of 40*10**-6 A.The HIGH-state fan-out is',HF,\n",
"print'\\nFor the LOW output state, fan-out is calculated as follows:Iol(max) is the maximum current that the gate can sink.Each load input produces an Iil(max) of -1.6*10**-3 A.The LOW-state fan-out is:',LW,"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" According to Datasheet, the current parameters are as follows:\n",
"Fan-out for the HIGH output state is calculated as follows:Current Ioh(max) is the maximum current that the gate can source to a load..Each load input requires an Iih(max) of 40*10**-6 A.The HIGH-state fan-out is 10.0 \n",
"For the LOW output state, fan-out is calculated as follows:Iol(max) is the maximum current that the gate can sink.Each load input produces an Iil(max) of -1.6*10**-3 A.The LOW-state fan-out is: 10.0\n"
]
}
],
"prompt_number": 34
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-7, Page NO:483"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"print'The ouput expression is :'\n",
"print'X=ABCDEFGH'\n",
"print'The wired-AND connection of the four 2-input AND gates creates an 8-input AND gate.'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The ouput expression is :\n",
"X=ABCDEFGH\n",
"The wired-AND connection of the four 2-input AND gates creates an 8-input AND gate.\n"
]
}
],
"prompt_number": 35
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-8, Page NO:483"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"print'(a)X=ABCDEFGH'\n",
"print'(b) 4(1.6)mA=6.4mA'\n",
"\n",
"print'Irp=Iol(max)-6.4*10*10**-3=23.6*10**-3 A'\n",
"print'Rp=(Vcc-Vol(max)/Irp)= 195 ohm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)X=ABCDEFGH\n",
"(b) 4(1.6)mA=6.4mA\n",
"Irp=Iol(max)-6.4*10*10**-3=23.6*10**-3 A\n",
"Rp=(Vcc-Vol(max)/Irp)= 195 ohm\n"
]
}
],
"prompt_number": 36
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example NO:11-9, Page NO:485"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"print'Vrl=3.4V'\n",
"print'Rl=Vrl/I=170 ohm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Vrl=3.4V\n",
"Rl=Vrl/I=170 ohm\n"
]
}
],
"prompt_number": 37
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}