{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 11:Intermolecular Forces and Liquids and Solids" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:11.3,Page no:479" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#Variable declaration\n", "atoms=8*1.0/8.0+6*1.0/2.0 #atoms in a cell\n", "d=19.3 #density, g/cc\n", "Au=197.0 #mol mass of Au, g\n", "NA=6.022*10**23 #avogadro no.\n", "\n", "#Calculation\n", "m=atoms*Au/NA #mass of 1 cell, g\n", "V=m/d #volume, cc\n", "a=V**(1/3.0) #edge length, cm\n", "r=a/math.sqrt(8.0)/100.0 #radius in m\n", "\n", "#Result\n", "print\"The atomic radius of Au is :\",round(r*10**12),\"pm\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The atomic radius of Au is : 144.0 pm\n" ] } ], "prompt_number": 31 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:11.4,Page no:481" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#Variable declaration\n", "n=1.0 \n", "lamda=154 #wavelength, pm\n", "theta=19.3 #angle of reflection, degree\n", "\n", "#Calculation\n", "d=n*lamda/(2*math.sin(theta*math.pi/180.0)) #spacing between the planes\n", "\n", "#Result\n", "print\"The spacing between planes is :\",round(d),\"pm\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The spacing between planes is : 233.0 pm\n" ] } ], "prompt_number": 32 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:11.6,Page no:483" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Variable declaration\n", "Na=22.99 #mass of one atom of Na, amu\n", "Cl=35.45 #mass of one atom of Cl, amu\n", "NA=6.022*10**23 #avogadro no.\n", "\n", "#Calculation\n", "mass=4*(Na+Cl)/NA #mass in a unit cell in grams\n", "a=564*10**-10 #edge length, cm\n", "V=a**3 #volume of unit cell, cc\n", "d=mass/V #density in g/cc\n", "\n", "#Result\n", "print\"The density of NaCl is :\",round(d,2),\"g/cm**3\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The density of NaCl is : 2.16 g/cm**3\n" ] } ], "prompt_number": 33 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:11.7,Page no:492" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#Variable declaration\n", "P1=401.0 #vapor pressure at 18C, mm Hg\n", "T1=18.0+273.0 #temperature, K\n", "T2=32.0+273.0 #temperature, K\n", "deltaH=26000.0 #heat of vaporisation, J/mol\n", "R=8.314 #gas constant, J/K.mol\n", "\n", "#Calculation\n", "X=deltaH/R*(T1-T2)/(T1*T2) \n", "P2=401*math.exp(-X) #vapor pressure at 32C, mmHg(from ln(P1/P1)=deltaH/R*((T1-T2)/(T1*T2)))\n", "\n", "#Result\n", "print\"The pressure at 32 C is \",round(P2,1),\"mm Hg\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The pressure at 32 C is 656.7 mm Hg\n" ] } ], "prompt_number": 34 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:11.8,Page no:497" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Variable declaration\n", "m=346 #mass of H2O in g\n", "s=4.184 #specific heat of H2O, J/g C\n", "deltaH=40.79 #heat of vaporisation in kJ\n", "H2O=18.02 #mol mass of H2O, g\n", "s2=1.99 #specific heat of steam, J/g C\n", "\n", "#Calculation\n", "#from 0 to 100 C\n", "deltaT=100.0-0.0 #change in Temp, C\n", "q1=round((m*s*deltaT)/1000.0) #heating H2O, kJ\n", "#for evaporation at 100 C\n", "deltaT2=182-100 #change in temp of steam, kJ\n", "q2=round(m*deltaH/H2O) #heat of vaporising water, kJ\n", "#for steam from 100 to 182 C\n", "q3=round(m*s2*deltaT2/1000.0,1) #heating steam, kJ\n", "q=round(q1)+round(q2)+round(q3,1) #overall energy required, kJ\n", "\n", "\n", "#Result\n", "print\"The overall energy required is :\",round(q),\"kJ\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The overall energy required is : 985.0 kJ\n" ] } ], "prompt_number": 15 } ], "metadata": {} } ] }