{ "metadata": { "name": "", "signature": "sha256:de8d33c7b9d51e88746e761918ff52cb67c086883ba151d5269fcccdacab917b" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 1 : Purpose, Usefulness, And Definitions of Thermodynamics" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1.1 page : 3" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\t\t\t\n", "# Variables\n", "P = 2050. \t\t\t#kPa\n", "T = 700. \t\t\t#K\n", "E = 10.\t \t\t#J\n", "\t\t\t\n", "# Calculations\n", "Pe = P*10**3 *0.3048**2 /4.4482 /144\n", "Te = T*1.8-460\n", "Ee = E*10**8 /(1055.1)\n", "\t\t\t\n", "# Results\n", "print \"Temperature = %d F\"%(Te)\n", "print \" Pressure = %d lbf/in**2 \"%(Pe)\n", "print \" Energy = %.2e Btu\"%(Ee)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Temperature = 800 F\n", " Pressure = 297 lbf/in**2 \n", " Energy = 9.48e+05 Btu\n" ] } ], "prompt_number": 1 } ], "metadata": {} } ] }