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  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter 25: Laminated Composite Structures"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 25.1 Pg.No.653"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "import math\n",
      "\n",
      "#variable declaration\n",
      "Ee=5000               #youngs modulus of epoxy (N/mm^2)\n",
      "Ec=200000             #youngs modulus of carbon (N/mm^2)\n",
      "\n",
      "# E1=Ef*Af/A+Em+Am/A        equation 25.4\n",
      "A=50*80               #total area (mm^2)\n",
      "Ae=40*80              #area of epoxy (mm^2)\n",
      "Ac=10*80              #area of carbon(mm^2)\n",
      "L=500                  #length of bar(mm)\n",
      "vc=0.3                 #poisson ratio\n",
      "ve=0.2\n",
      "\n",
      "#effective youngs modulus\n",
      "E1=(Ee*Ae+Ec*Ac)/A\n",
      "\n",
      "load=100*10**3\n",
      "sigma1=load/A\n",
      "epsilon1=sigma1/E1\n",
      "\n",
      "delta1=epsilon1*L\n",
      "v1t=(ve*Ae+vc*Ac)/A\n",
      "epsilon_t=-v1t*epsilon1\n",
      "\n",
      "thickness=L\n",
      "delta_t=-epsilon_t*(thickness)\n",
      "\n",
      "\n",
      "sigma_m=Ee*epsilon1\n",
      "sigma_f=Ec*epsilon1\n",
      "print \"stresses in epoxy = %2.2f N/mm^2\\n\"%(sigma_m)\n",
      "print \"stresses in carbon = %2.2f N/mm^2\\n\"%(sigma_f)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "stresses in epoxy = 2.84 N/mm^2\n",
        "\n",
        "stresses in carbon = 113.64 N/mm^2\n",
        "\n"
       ]
      }
     ],
     "prompt_number": 10
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 25.2 Pg.No.657"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "import math\n",
      "\n",
      "tau=40            #shear stress(N/mm^2)\n",
      "G=5000            #shear modulus(N/mm^2)\n",
      "v1t=0.3            #poisson ratio \n",
      "Et=80000            #youngs modulus in transverse direction(N/mm^2)\n",
      "E1=120000           #youngs modulus in longitudinal direction(N/mm^2)\n",
      "sigma_x=50          #direction stress in x direciton\n",
      "sigma_y=25                           #in y direction\n",
      "\n",
      "\n",
      "vt1=v1t*Et/E1 #minor poisson ratio\n",
      "\n",
      "epsilon1=sigma_x/E1-vt1*sigma_y/Et\n",
      "epsilont=sigma_y/Et-v1t*sigma_x/E1\n",
      "print \"direct strain in x direction = %2.2e \\n\"%(epsilon1)\n",
      "print \"direct strain in y direction = %2.2e \\n\"%(epsilont)\n",
      "\n",
      "gama1t=tau/G\n",
      "print \"shear strain in the ply = %2.2e \\n\"%(gama1t)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "direct strain in x direction = 3.54e-04 \n",
        "\n",
        "direct strain in y direction = 1.88e-04 \n",
        "\n",
        "shear strain in the ply = 8.00e-03 \n",
        "\n"
       ]
      }
     ],
     "prompt_number": 12
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 25.3 Pg.No.661"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "import math\n",
      "import numpy as np\n",
      "\n",
      "El=150000          #youngs modulus(N/mm^2)\n",
      "Et=90000          #youngs modulus(N/mm^2)\n",
      "Glt=5000          #shear modulus(N/mm^2)\n",
      "vlt=0.3            #poisson ratio\n",
      "theta=45             #longitudinal plane inclination\n",
      "\n",
      "s11=1/El\n",
      "s22=1/Et\n",
      "s12=-vlt/El\n",
      "s33=1/Glt\n",
      "\n",
      "a=np.array([[53.45,-46.55,1],[-46.55,53.45,0],[-2.2,-2.2,0]])\n",
      "b=np.array([60,40,0])\n",
      "x=np.dot(a,b)\n",
      "print \"strain in the x direction = %4.4e\\n\"%(x[0]*10**-6)\n",
      "print \"strain in the y direction = %4.4e\\n\"%(x[1]*10**-6)\n",
      "print \"shear strain in the xy plane = %4.4e\\n\"%(x[2]*10**-6)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "strain in the x direction = 1.3450e-03\n",
        "\n",
        "strain in the y direction = -6.5500e-04\n",
        "\n",
        "shear strain in the xy plane = -2.2000e-04\n",
        "\n"
       ]
      }
     ],
     "prompt_number": 23
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 25.4 Pg.No.664"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "import math\n",
      "import numpy as np\n",
      "\n",
      "l1=150\n",
      "t1=1\n",
      "l2=100            #dimensions shown in Fig 25.10 (mm)\n",
      "t2=2\n",
      "Ef=60000            #youngs modulus of flanges(N/mm^2)\n",
      "Ew=20000            #youngs modulus of web(N/mm^2)\n",
      "P=40*10**3          #axial load(N)\n",
      "\n",
      "#sum of b*t*E \n",
      "sum_btE=2*l2*t2*Ef+l1*t1*Ew\n",
      "\n",
      "epsilon_z=P/sum_btE           #equ 25.37\n",
      "P_flange=epsilon_z*l2*t2*Ef\n",
      "P_web=epsilon_z*l1*t1*Ew\n",
      "print \"axial load in flange = %2.2f kN\\n\"%(P_flange/1000)\n",
      "print \"axial load in web = %2.2f kN\\n\"%(P_web/1000)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "axial load in flange = 17.78 kN\n",
        "\n",
        "axial load in web = 4.44 kN\n",
        "\n"
       ]
      }
     ],
     "prompt_number": 28
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 25.5 Pg.No.666"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "import math\n",
      "import numpy as np\n",
      "\n",
      "l1=100\n",
      "l2=50\n",
      "t1=1         #dimension shown in Fig 25.11 (mm)\n",
      "t2=2\n",
      "Ef=50000         #youngs modulus of flange(N/mm^2)\n",
      "Ew=15000          #youngs modulus of web(N/mm^2)\n",
      "Mx=10**6           #bending moment (N.mm)\n",
      "My=0\n",
      "\n",
      "Ixx=2*Ef*l2*t2*l2**2+Ew*t1*l1**3/12\n",
      "Iyy=Ef*t2*l1**3/12\n",
      "Ixy=Ef*l2*t2*(50)*(50)+Ef*l2*t2*(-50)*(-50)\n",
      "\n",
      "x=50\n",
      "y=50      #point 1\n",
      "Ez=50000\n",
      "\n",
      "sigma_z=Ez*((My*Ixx-Mx*Ixy)/(Ixx*Iyy-Ixy**2)*x + (Mx*Iyy-My*Ixy)/(Ixx*Iyy-Ixy**2)*y)\n",
      "print \"direct stress at point 1 = %3.1f N/mm^2\\n\"%(sigma_z)\n",
      "x=0\n",
      "y=50\n",
      "sigma_z=Ez*((My*Ixx-Mx*Ixy)/(Ixx*Iyy-Ixy**2)*x + (Mx*Iyy-My*Ixy)/(Ixx*Iyy-Ixy**2)*y)\n",
      "print \"direct stress at point 2 = %3.1f N/mm^2\\n\"%(sigma_z)\n",
      "\n",
      "x=0\n",
      "y=50\n",
      "Ez=15000\n",
      "sigma_z=Ez*((My*Ixx-Mx*Ixy)/(Ixx*Iyy-Ixy**2)*x + (Mx*Iyy-My*Ixy)/(Ixx*Iyy-Ixy**2)*y)\n",
      "print \"direct stress at point 2 in the web = %3.1f N/mm^2\\n\"%(sigma_z)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "direct stress at point 1 = 102.6 N/mm^2\n",
        "\n",
        "direct stress at point 2 = -51.3 N/mm^2\n",
        "\n",
        "direct stress at point 2 in the web = -15.4 N/mm^2\n",
        "\n"
       ]
      }
     ],
     "prompt_number": 39
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 25.6 Pg.No.668"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "import math\n",
      "import numpy as np\n",
      "from sympy import symbols, integrate\n",
      "\n",
      "s=symbols('s')\n",
      "\n",
      "l12=250\n",
      "l23=300\n",
      "t31=t12=2                 #dimensions shown in Fig 25.12 (mm)\n",
      "t23=1.5\n",
      "\n",
      "P=2*10**3             #shear load(N)\n",
      "E12=E31=45000          #youngs modulus of sides given in name(N/mm^2)\n",
      "E23=20000\n",
      "\n",
      "Ixx=2*E12*t12*l12**3*(l23/2/l12)**2/12+E23*t23*l23**3/12\n",
      "alpha=math.asin(l23/2/l12)\n",
      "\n",
      "Sx=0\n",
      "Sy=2*10**3\n",
      "q12=-E12*Sy/Ixx*integrate(-2*s,(s,0,250))*math.sin(alpha)\n",
      "print \"shear flow at point 2 in the flange 12 = %2.2f N/mm\\n\"%(q12)\n",
      "\n",
      "q23=-E23*Sy/Ixx*integrate(-225+1.5*s,(s,0,300))+22.2\n",
      "print \"shear flow at point 3 in the flange 23 = %2.2f N/mm\\n\"%(q23)\n",
      "q0=14.2\n",
      "\n",
      "q12=-E12*Sy/Ixx*integrate(-2*s,s)*math.sin(alpha)-q0\n",
      "print \"shear flow in the flange 12 and 31 \"\n",
      "print q12\n",
      "\n",
      "q23=-E23*Sy/Ixx*integrate(-225+1.5*s,s,)+22.2-q0\n",
      "print \"\\nshear flow in the web 23\"\n",
      "print q23"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "shear flow at point 2 in the flange 12 = 22.22 N/mm\n",
        "\n",
        "shear flow at point 3 in the flange 23 = 22.20 N/mm\n",
        "\n",
        "shear flow in the flange 12 and 31 \n",
        "0.000355555555555556*s**2 - 14.2\n",
        "\n",
        "shear flow in the web 23\n",
        "-0.000197530864197531*s**2 + 0.0592592592592593*s + 8.0\n"
       ]
      }
     ],
     "prompt_number": 57
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 25.7 Pg.No.671"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "import math\n",
      "import numpy as np\n",
      "from sympy import symbols, integrate\n",
      "\n",
      "\n",
      "l1=200\n",
      "t1=2\n",
      "l2=100         #dimensions shown in Fig 25.13 (mm)\n",
      "t2=1\n",
      "T=10*10**6       #torque applied (N.mm)\n",
      "Gl=20000          #laminate shear modulus(N/mm^2)\n",
      "Gw=35000            #web shear modulus(N/mm^2)\n",
      "A=l1*l2\n",
      "\n",
      "q=T/2/A\n",
      "\n",
      "#from eqn 25.47\n",
      "int_ds_by_Gt=2*l1/Gl/t1+2*l2/Gw/t2\n",
      "\n",
      "#Let's say we want to calculate warping at point 1\n",
      "#warping at mid of web is zero (W0=0) integrate eqn 25.47 from\n",
      "#mid of web to point 1\n",
      "W0=0\n",
      "A0s=50*100\n",
      "W1=W0+q*(l2/2/Gw/t2-int_ds_by_Gt/A*A0s)\n",
      "print \"warping at point 1 is = %2.2f mm\\n\"%(W1)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "warping at point 1 is = -0.63 mm\n",
        "\n"
       ]
      }
     ],
     "prompt_number": 66
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 25.8 Pg.No.673"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "import math\n",
      "import numpy as np\n",
      "from sympy import symbols, integrate\n",
      "\n",
      "l1=50\n",
      "t1=2.5\n",
      "l2=25             #dimension shown in Fig 18.12(mm)\n",
      "t2=1.5\n",
      "\n",
      "Gl=20000\n",
      "Gw=15000           #shear modulus (N/mm^2)\n",
      "T=10*10**3         #torque applied (N.mm)\n",
      "AR=25*25/2\n",
      "GJ=2*Gl*l2*t2**3/3+Gw*l1*t1**3/3\n",
      "#eqn 25.49\n",
      "dO_dz=T/GJ\n",
      "\n",
      "t_max12=2*Gl*(t2/2)*dO_dz\n",
      "t_max23=2*Gw*(t1/2)*dO_dz\n",
      "print \"maximum shear stress in the web = %2.2f N/mm^2\\n\"%(t_max12)\n",
      "print \"maximum shear stress in the laminate = %2.2f N/mm^2\\n\"%(t_max23)\n",
      "\n",
      "W1=-2*AR*dO_dz\n",
      "print \"warping at point 1 = %2.2f mm\\n\"%(W1)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "maximum shear stress in the web = 59.63 N/mm^2\n",
        "\n",
        "maximum shear stress in the laminate = 74.53 N/mm^2\n",
        "\n",
        "warping at point 1 = -1.24 mm\n",
        "\n"
       ]
      }
     ],
     "prompt_number": 74
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [],
     "language": "python",
     "metadata": {},
     "outputs": []
    }
   ],
   "metadata": {}
  }
 ]
}