{ "metadata": { "name": "", "signature": "sha256:47a0669d4632eab71f162a005cd6d69531f951e47ad9f34d928b679209ff2467" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 09: Thin plates" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.1 Pg.No.310" ] }, { "cell_type": "code", "collapsed": false, "input": [ "from __future__ import division\n", "import math\n", "\n", "h=400 #height of structure (mm)\n", "l1=300 #length of small section (mm)\n", "L=1200 #length of whole structure (mm)\n", "E=70000 #youngs modulus (N/mm^2)\n", "A_f=350 #area of flange (mm^2)\n", "A_s=300 # area of stiffeners (mm^2)\n", "t=2 #thickness (mm)\n", "I=2000 #second moment of area (mm^4)\n", "w=5\n", "#eqn 9.29 tan(a)^4=(1+td/2A_F)/(1+td/2A_S)\n", "alpha=math.atan(((1+t*h/2/A_f)/(1+t*l1/A_s))**0.25)\n", "\n", "#eqn 9.19\n", "F_T=w*L/h+w/2/math.tan((alpha))\n", "\n", "#eqn 9.25 M_max=w*b^2*tan(a)/12/d\n", "M_max=w*10**3*l1**2*math.tan(alpha)/12/h\n", "print \"maximum value of bending moment = %1.1e N.mm \\n\"%(M_max)\n", "\n", "#eqn 9.23 P=w*b*tan(a)/d\n", "P=w*l1*math.tan(alpha)/h\n", "print \"compressive load in stiffener = %1.1f kN \\n\"%(P)\n", "\n", "#eqn 9.24 le=d/(4-2b/d)^0.5\n", "le=h/(4-2*l1/h)**0.5\n", "print \"equivalent length of stiffener = %3.1f mm\\n\"%(le)\n", "\n", "#eqn 8.7 Pcr=pi^2*E*I/le^2\n", "P_CR=math.pi**2*E*I/le**2\n", "print \"buckling load of a stiffener = %2.1f kN \\n\"%(P_CR) #approx. value in book" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "maximum value of bending moment = 8.6e+04 N.mm \n", "\n", "compressive load in stiffener = 3.4 kN \n", "\n", "equivalent length of stiffener = 253.0 mm\n", "\n", "buckling load of a stiffener = 21589.8 kN \n", "\n" ] } ], "prompt_number": 13 }, { "cell_type": "code", "collapsed": false, "input": [], "language": "python", "metadata": {}, "outputs": [] } ], "metadata": {} } ] }