{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 7: Solid State"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 1, Page no: 209"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Solution\n",
"print \"Weiss indices \\t\\t\\t1/2, 2/3, infinity \\t2/3, 2, 1/3\"\n",
"print \"Reciprocal of Weiss indices 2, 3/2, 1/infinity \\t3/2, 1/2, 3\"\n",
"print \"Clear fractions\\t\\t\\t4, 3, 0 \\t3, 1, 6\"\n",
"print \"Miller indices \\t\\t\\t (430) \\t (316)\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Weiss indices \t\t\t1/2, 2/3, infinity \t2/3, 2, 1/3\n",
"Reciprocal of Weiss indices 2, 3/2, 1/infinity \t3/2, 1/2, 3\n",
"Clear fractions\t\t\t4, 3, 0 \t3, 1, 6\n",
"Miller indices \t\t\t (430) \t (316)\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 2, Page no: 209"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from math import sqrt\n",
"\n",
"\n",
"# Variable\n",
"a = 450 # pm\n",
"\n",
"# Solution\n",
"d220 = a / sqrt(2 ** 2 + 2 ** 2 + 0)\n",
"print \"Interplanar spacing\", int(d220)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Interplanar spacing 159\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 3, Page no: 209"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Solution\n",
"print \"Intercept \\t(a, b ,c)\\t\\t(a, 2b, c) \\t\\t(a, 2b, 2c) \\t\\t(infi, b, -c)\"\n",
"print \"Weiss indices\\t 1, 1, 1 \\t\\t 1, 2, 1 \\t\\t 1, 2, 2 \\t\\t infi, 1, -1\"\n",
"print \"Reciprocals \\t 1, 1, 1 \\t\\t 1, 1/2, 1 \\t\\t 1, 1/2, 1/2\\t\\t 0, 1, -1\"\n",
"print \"Miller indicec\\t (111) \\t\\t (212) \\t\\t (211) \\t\\t (011)\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Intercept \t(a, b ,c)\t\t(a, 2b, c) \t\t(a, 2b, 2c) \t\t(infi, b, -c)\n",
"Weiss indices\t 1, 1, 1 \t\t 1, 2, 1 \t\t 1, 2, 2 \t\t infi, 1, -1\n",
"Reciprocals \t 1, 1, 1 \t\t 1, 1/2, 1 \t\t 1, 1/2, 1/2\t\t 0, 1, -1\n",
"Miller indicec\t (111) \t\t (212) \t\t (211) \t\t (011)\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 4, Page no: 209"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Variables\n",
"rNa = 0.98 * 10 ** - 10 # m\n",
"rCl = 1.81 * 10 ** - 10 # m\n",
"\n",
"# Solution\n",
"rr = rNa / rCl\n",
"print \"When the radius ration is\", \"{:.2f}\".format(rr),\n",
"print \", the coordination number is 6.\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"When the radius ration is 0.54 , the coordination number is 6.\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 5, Page no: 210"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Variables\n",
"rLi = 68 # pm\n",
"rF = 136. # pm\n",
"\n",
"# Solution\n",
"rr = rLi / rF\n",
"print \"Radius ratio =\", rr\n",
"print \"The structure of LiF is scc and C.N of Li+ = 6\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Radius ratio = 0.5\n",
"The structure of LiF is scc and C.N of Li+ = 6\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 6, Page no: 210"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from math import sin\n",
"\n",
"\n",
"# Variables\n",
"lamda = 2 * 10 ** - 10 # m\n",
"theta = 30 # degrees\n",
"\n",
"# Solution\n",
"print \"For first-order reflection\"\n",
"d = lamda / (2 * sin(theta))\n",
"dist = 2 * d\n",
"print \"Hence, distance between planes is\", \"{:.0e}\".format(abs(dist)), \"m\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"For first-order reflection\n",
"Hence, distance between planes is 2e-10 m\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 7, Page no: 210"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from math import sqrt\n",
"\n",
"\n",
"# Variables\n",
"r = 174.6 # pm\n",
"\n",
"# Solution\n",
"a = r * sqrt(8)\n",
"print \"For 200 plane: h = 2, k = 0, l = 0\"\n",
"d200 = a / sqrt(2 ** 2)\n",
"print \"d200 =\", \"{:.1f}\".format(d200), \"pm\"\n",
"print \"For 200 plane: h = 2, k = 2, l = 0\"\n",
"d220 = a / sqrt(2 ** 2 + 2 ** 2)\n",
"print \"d220 =\", d220, \"pm\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"For 200 plane: h = 2, k = 0, l = 0\n",
"d200 = 246.9 pm\n",
"For 200 plane: h = 2, k = 2, l = 0\n",
"d220 = 174.6 pm\n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 8, Page no: 210"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Constant\n",
"N = 6.023 * 10 ** 23\n",
"\n",
"# Variables\n",
"wt = 55.6\n",
"p = 0.29 # nm\n",
"n = 2\n",
"\n",
"# Solution\n",
"print \"For BCC pattern,\"\n",
"print \"number of atoms per unit cell = 2\"\n",
"d = n * (wt * 10 ** -3) / (N * (p * 10 ** - 9) ** 3)\n",
"print \"Density of the metal is\", \"{:.2e}\".format(d), \"kg / m^3\"\n",
"print \"Number of nearest enighbour for BCC = 8\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"For BCC pattern,\n",
"number of atoms per unit cell = 2\n",
"Density of the metal is 7.57e+03 kg / m^3\n",
"Number of nearest enighbour for BCC = 8\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 9, Page no: 210"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Solution\n",
"print \"Intercept \\t2a/2, 2b, c/3\"\n",
"print \"Weiss indices\\t1, 2, 1/3\"\n",
"print \"Reciprocals \\t1, 1/2, 3\"\n",
"print \"Miller indices\\t (216)\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Intercept \t2a/2, 2b, c/3\n",
"Weiss indices\t1, 2, 1/3\n",
"Reciprocals \t1, 1/2, 3\n",
"Miller indices\t (216)\n"
]
}
],
"prompt_number": 19
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 10, Page no: 211"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Constant\n",
"N = 6.023 * 10 ** 23\n",
"\n",
"# Variables\n",
"D = 0.53 # g / cm ^ 3\n",
"MM = 6.94 # g / mol\n",
"n = 2\n",
"\n",
"# Solution\n",
"print \"For BCC pattern,\"\n",
"print \"number of atoms per unit cell = 2\"\n",
"V = D * N / (n * MM)\n",
"V = 1 / V\n",
"print \"Volume of a unit cell of lithium metal is\", \"{:.2e}\".format(V), \"cc\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"For BCC pattern,\n",
"number of atoms per unit cell = 2\n",
"Volume of a unit cell of lithium metal is 4.35e-23 cc\n"
]
}
],
"prompt_number": 23
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Problem 11, Page no: 211"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from math import sqrt\n",
"\n",
"\n",
"print \"AB remain in BCC structure if the edge length is a then body diagonal\",\n",
"print \"is root(3)a\"\n",
"print \"root(3)a = 2(r+ + r-)\"\n",
"A = (sqrt(3) * 0.4123 - 2 * 0.81) / 2\n",
"print \"A+ =\", \"{:.2f}\".format(A), \"nm\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"AB remain in BCC structure if the edge length is a then body diagonal is root(3)a\n",
"root(3)a = 2(r+ + r-)\n",
"A+ = -0.45 nm\n"
]
}
],
"prompt_number": 25
}
],
"metadata": {}
}
]
}