{ "metadata": { "name": "", "signature": "sha256:5389b8ee7db605c2b6709900953f8acf2763d42f0399c64611452653d4ee8704" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "UNIT-4:Electrostatics" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.1,Page no:103" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "q=1.0 #no of coulomb\n", "e=1.6*10**-19 #charge on an electron\n", "\n", "#Calculation\n", "n=(q/e) #calculating no of electrons\n", "\n", "#Result\n", "print\"No of electrons =\",n\n", "print\"NOTE:Calculation mistake in book\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "No of electrons = 6.25e+18\n", "NOTE:Calculation mistake in book\n" ] } ], "prompt_number": 32 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.2,Page no:103" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "import math \n", "\n", "#Variable declaration\n", "g=9.8\n", "m=4.5 #Massin [kg]\n", "r=0.03 #radius in [m]\n", "\n", "#Calculation\n", "F=m*g #in Newton\n", "q=math.sqrt(((r**2)*m*g)/(9*10**9)) #calculating q using F=(1/4*3.14*eo)*((q1*q2)/(r**2))\n", "\n", "#Result\n", "print\"Charge = \",q,\"C\"\n", "print\"\\nNOTE:Calculation mistake in book\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Charge = 2.1e-06 C\n", "\n", "NOTE:Calculation mistake in book\n" ] } ], "prompt_number": 36 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.3,Page no:103" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "q1=2*10**-7 #charge in C\n", "q2=3*10**-7 #charge in C\n", "r=30*10**-2 #r in m\n", "\n", "#Calculation\n", "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n", "\n", "#Result\n", "print\"Force = %.e\"%F,\"N\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Force = 6e-03 N\n" ] } ], "prompt_number": 70 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.4,Page no:104" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "q1=1 #charge in C\n", "q2=1 #charge in C\n", "r=1 #r in m\n", "\n", "#Calculation\n", "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n", "\n", "#Result\n", "print\"Force = %.e\"%F,\"N\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Force = 9e+09 N\n" ] } ], "prompt_number": 71 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.5,Page no:104" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "m=9*10**-31 #mass of electron in kg\n", "q=-3.2*10**-7 #charge in C\n", "e=-1.6*10**-19 #charge on electron in C\n", "\n", "#Calculation\n", "n=(q/e) #calculating n\n", "M=n*m #calculating mass transfered\n", "\n", "#Result\n", "print\"(a):No. of electrons = \",n\n", "print\"(b):Mass transfered to polythene= \",M,\"kg\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "(a):No. of electrons = 2e+12\n", "(b):Mass transfered to polythene= 1.8e-18 kg\n" ] } ], "prompt_number": 50 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.6,Page no:105" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "q1=1.6*10**-19 #charge in C\n", "q2=-1.6*10**-19 #charge in C\n", "r=10**-9 #r in m\n", "\n", "#Calculation\n", "F=(9*10**9)*((q1*q2)/r**2) #calculating F\n", "\n", "#Result\n", "print\"Force=\",F,\"N\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Force= -2.304e-10 N\n" ] } ], "prompt_number": 54 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.7,Page no:110" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "Va=-10 #voltage in volts\n", "W=100 #work in Joule\n", "q=2 #charge in Coulomb\n", "\n", "#Calculation\n", "v=(Va)+(W/q) #calculating v\n", "\n", "#Result\n", "print\"Voltage = \",v,\"V\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Voltage = 40 V\n" ] } ], "prompt_number": 55 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.8,Page no:111" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "#Variable declaration\n", "eo=(8.854*10**-12) #constant\n", "E=2 #magnitude of electric field in N/C\n", "r=0.5 #r in m\n", "\n", "#Calculation\n", "q=E*4*(math.pi)*(eo)*(r**2) #calculating charge\n", "\n", "#Result\n", "print\"Charge= %.2e\"%q,\"C\"\n", "print\"\\nNOTE:Calcualtion mistake in book\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Charge= 5.56e-11 C\n", "\n", "NOTE:Calcualtion mistake in book\n" ] } ], "prompt_number": 73 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.9,Page no:111" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "e=-1.6*10**-19 #charge on electron in Coulomb\n", "q=20*10**-6 #charge in Coulomb\n", "r1=0.1 #r1 in m\n", "r2=0.05 #r2 in m\n", "\n", "#Calculation\n", "Va=9*10**9*(q/r1) #calculating voltage at A\n", "Vb=9*10**9*(q/r2) #calculating voltage at B\n", "V=Va-Vb #potential difference\n", "W=V*e #calculating work done in joule\n", "\n", "#Result\n", "print\"Work done to take the electron from A to B = \",W,\"Joule\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Work done to take the electron from A to B = 2.88e-13 Joule\n" ] } ], "prompt_number": 69 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.10,Page no:112" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "q1=(2.0*10**-8) #charge in coulomb\n", "q2=(-2.0*10**-8) #charge in coulomb\n", "q3=(3.0*10**-8) #charge in coulomb\n", "q4=(6.0*10**-8) #charge in coulomb\n", "s=1.0 #side in m\n", "\n", "#Calculation\n", "V=(9.0*10**9)*(1.0/s)*(q1+q2+q3+q4) #calculating voltage\n", "\n", "#Result\n", "print\"Voltage in Volts = \",V,\"Volts\"\n", "print\"\\nNOTE:Calculation mistake in book\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Voltage in Volts = 810.0 Volts\n", "\n", "NOTE:Calculation mistake in book\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.11,Page no:123" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "eo=8.85*10**-12 #constant\n", "q=2*10**-6 #charge in coulomb\n", "l=9 #length in cm\n", "\n", "#Calculation\n", "fi=(q/eo) #calcualting flux in (N m square)/c\n", "\n", "#Result\n", "print\"Flux through the surface=%2e\"%fi,\"N m^2/c\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Flux through the surface=2.259887e+05 N m^2/c\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.12,Page no:124" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "import math \n", "\n", "#Variable declaration\n", "eo=8.85*10**-12 #constant\n", "r=1.2 #r in m\n", "t=80*10**-6 #surface sharge density in c/m square\n", "\n", "#Calculation\n", "q=t*4*(math.pi)*(r**2) #calculating charge\n", "fi=q/eo #calculating flux\n", "\n", "#Result\n", "print\"Flux=%g\"%fi,\"N c^-1 m^2\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Flux=1.63576e+08 N c^-1 m^2\n" ] } ], "prompt_number": 12 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.13,Page no:124" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "import math \n", "\n", "#Variable declaration\n", "eo=8.85*10**-12 #constant\n", "E=9*10**4 #Electric field in N/C\n", "r=2*10**-2 #r in m\n", "\n", "#Calculation\n", "L=2*(math.pi)*E*eo*r #calculating linear charge density\n", "\n", "#Result\n", "print\"Linear charge density = \",round(L,7),\"cm^-1\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Linear charge density = 1e-07 cm^-1\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.14,Page no:125" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "o=17*10**-22 #surface charge density in cm**-2\n", "eo=8.85*10**-12 #constant\n", "\n", "#Calculation\n", "E=o/eo #calculating electric intensity in region III\n", "\n", "#Result\n", "print\"Electric Intensity in regions I and II = 0\" \n", "print\"Electric Intensity in region III = \",round(E,12),\"N/C\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Electric Intensity in regions I and II = 0\n", "Electric Intensity in region III = 1.92e-10 N/C\n" ] } ], "prompt_number": 7 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.15,Page no:125" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "import math \n", "\n", "#Variable declaration\n", "r=0.05 # in m\n", "eo=8.85*10**-12 #constant\n", "q=10.0**-9 #charge at point P in Coulomb\n", "\n", "#Calculation\n", "E=q/(4*(math.pi)*eo*(r**2)) #calculating electric field\n", "r1=0.2 #in m\n", "V1=q/(4*(math.pi)*eo*r1) #calculating potential difference\n", "\n", "#Result\n", "print\"Electric field= \",round(E),\"v/m\"\n", "print\"\\nNOTE:Approximate answer is calculated in book\\n\\n\"\n", "print\"Potential difference between two points = \",round(V1),\"V\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Electric field= 3597.0 v/m\n", "\n", "NOTE:Approximate answer is calculated in book\n", "\n", "\n", "Potential difference between two points = 45.0 V\n" ] } ], "prompt_number": 65 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.16,Page no:126" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "#Variable declaration\n", "eo=8.85*10**-12 #constant\n", "o=80.0*10**-6 #surface charge density in c/ square\n", "r=1.2 #in m\n", "\n", "#Calculation\n", "q=o*(math.pi)*(r**2) #calculating charge in Coulomb\n", "fi=q/eo #calculating electric flux\n", "\n", "#Result\n", "print\"Charge= \",q,\"C\"\n", "print\"Electric flux = \",fi,\"N m^2/c\"\n", "print\"\\nNOTE:Wrong answers in book\\n\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Charge= 0.000361911473694 C\n", "Electric flux = 40893951.8298 N m^2/c\n", "\n", "NOTE:Wrong answers in book\n", "\n" ] } ], "prompt_number": 19 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.17,Page no:138" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "V=250 #potential difference in Volt\n", "C=10**-11 #capacitance in farad\n", "\n", "#Calculation\n", "q=C*V #calculating charge\n", "\n", "#Result\n", "print\"Charge = \",q,\"C\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Charge = 2.5e-09 C\n" ] } ], "prompt_number": 68 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.18,Page no:138" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "r=6.4*10**6 #in m\n", "\n", "#Calculation\n", "C=r/(9*10**9) #calculating charge\n", "\n", "#Result\n", "print\"Capacitance = \",round(C*10**6),\"mu F\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Capacitance = 711.0 mu F\n" ] } ], "prompt_number": 67 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.19,Page no:138" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "C=2 #capacitance in Farad\n", "d=0.5*10**-2 #distance in m\n", "eo=8.85*10**-12 #constant\n", "\n", "#Calculation\n", "A=(C*d)/(eo) #calculating area\n", "\n", "#Result\n", "print\"Area=%.2e\"%A,\"m^2\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Area=1.13e+09 m^2\n" ] } ], "prompt_number": 66 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.20,Page no:139" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "import math \n", "\n", "#Variable declaration\n", "A=0.02 #area in m square\n", "r=0.5 #r in m\n", "\n", "#Calculation\n", "d=(A/(4*(math.pi)*r)) #calculating distance\n", "\n", "#Result\n", "print\"Distance between the plates = \",round(d*1000,2),\"mm\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Distance between the plates = 3.18 mm\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.21,Page no:139" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "eo=8.85*10**-12 #constant\n", "A=1 #area in m square\n", "d=2*10**-3 #r in m\n", "K=4 #constant\n", "\n", "#Calculation\n", "C=(K*eo*A)/d #calculating capacitance\n", "\n", "#Result\n", "print\"Capacitance = \",C,\"Farad\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Capacitance = 1.77e-08 Farad\n" ] } ], "prompt_number": 21 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.22,Page no:140" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "cm=10*10**-6 #capacitance in Farad\n", "K=2 #constant\n", "\n", "#Calculation\n", "co=cm/K #calculating co\n", "\n", "#Result\n", "print\"capacity of capacitor with air between the plates= \",co*10**6,\"muF\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "capacity of capacitor with air between the plates= 5.0 muF\n" ] } ], "prompt_number": 37 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.23,Page no:140" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "v=100.0 #v in volt\n", "c1=8.0*10**-6 #capacitance in Farad\n", "c2=12.0*10.0**-6 #capacitance in Farad\n", "c3=24.0*10.0**-6 #capacitance in Farad\n", "cs=4.0/(10.0**6) #calculating series capacitance\n", "\n", "#Calculation\n", "cp=(c1+c2+c3) #calculating parallel capacitance\n", "qs=cs*v #calculating charge\n", "\n", "#Result\n", "print\"Equivalent Series capacitance,C= \",cs*10**6,\"muF\"\n", "print\"Equivalent parallel capacitance,Cp= \",cp*10**6,\"muF\" \n", "print\"charge on plate=%.e\"%qs,\"C\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Equivalent Series capacitance,C= 4.0 muF\n", "Equivalent parallel capacitance,Cp= 44.0 muF\n", "charge on plate=4e-04 C\n" ] } ], "prompt_number": 48 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.24,Page no:141" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "C=9*10**-10 #capacitance in farad\n", "V=100.0 #in volt\n", "\n", "#Calculation\n", "U=(1/2.0)*(C*(V**2)) #calculating energy stored\n", "\n", "#Result\n", "print\"Energy stored = \",U,\"J\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Energy stored = 4.5e-06 J\n" ] } ], "prompt_number": 50 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.25,Page no:141" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "#Variable declaration \n", "eo=8.85*10**-12 #constant\n", "A=90.0*10**-4 #area in m square\n", "d=2.5*10**-3 #distance in m\n", "V=400.0 #in volt\n", "\n", "#Calculation\n", "C=(eo*A)/d #calculating capacitance\n", "W=(1/2.0)*(C*(V**2)) #calculating electrical energy stored\n", "\n", "#Result\n", "print\"Capacitance = \",C,\"Farad\"\n", "print\"Electrical Energy stored in capacitor =%.2e\"%W,\"J\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Capacitance = 3.186e-11 Farad\n", "Electrical Energy stored in capacitor =2.55e-06 J\n" ] } ], "prompt_number": 56 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.26,Page no:142" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "v=100 #v in volt\n", "c1=1*10**-6 #capacitance in Farad\n", "c2=2*10**-6 #capacitance in Farad\n", "c3=3*10**-6 #capacitance in Farad\n", "cs=6/11.0 #calculating series capacitance\n", "\n", "#Calculation\n", "cp=(c1+c2+c3) #calculating parallel capacitance\n", "\n", "#Result\n", "print\"Equivalent Series capacitance = \",cs,\"muF\"\n", "print\"Equivalent parallel capacitance= \",cp*10**6,\"muF\"\n", "print\"Therefore Cp=(11*Cs)\" " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Equivalent Series capacitance = 0.545454545455 muF\n", "Equivalent parallel capacitance= 6.0 muF\n", "Therefore Cp=(11*Cs)\n" ] } ], "prompt_number": 60 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example no:4.27,Page no:143" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "#Variable declaration \n", "eo=8.85*10**-12 #constant\n", "V=6 #v in volt\n", "A=25*10**-4 #area in m square\n", "d=10**-3 #distance in m\n", "\n", "#Calculation\n", "q=(eo*A*V)/d #calculating charge\n", "W=q*V #calculating work done\n", "\n", "#Result\n", "print\"Charge through battery =%.3g\"%q,\"C\"\n", "print\"Work done by Battery=%.e\"%W,\"J\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Charge through battery =1.33e-10 C\n", "Work done by Battery=8e-10 J\n" ] } ], "prompt_number": 63 } ], "metadata": {} } ] }