{
"metadata": {
"name": "",
"signature": "sha256:040e38e52e7b9682cfcedeffe89e523ef70aa22db1a3d6616f3de2ca6dd532ec"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"UNIT-3:Principle of Optics"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.1,Page no:69"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"f=15.0 #focal length in cm\n",
"v=10.0 #image distance in cm\n",
"\n",
"#Calculation\n",
"u=1/((1/v)-(1/f)) #calculating u using (1/f)=(1/v)-(1/u)\n",
"\n",
"#Result\n",
"print\"Object Distance ,u= \",u,\"cm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Object Distance ,u= 30.0 cm\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.2,Page no:70"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration\n",
"f=80.0 #focal length in cm\n",
"f1=20.0 #focallength of first lens in cm\n",
"\n",
"#Calculation\n",
"f2=1/((1/f)-(1/f1)) #using (1/F)=(1/f1)+(1/f2)\n",
"P=(100.0/f) #power in D\n",
"P1=100.0/20 #power of first lens\n",
"P2=P1-P #power in D\n",
"\n",
"#Variable declaration\n",
"print\"Power= \",P2,\"D\" "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Power= 3.75 D\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.3,Page no:71"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"P=2.5 #Power in D\n",
"\n",
"#Calculation\n",
"f=-(1/P) #calculating f in m\n",
"\n",
"#Result\n",
"print\"Focal length =\",f,\"m\" "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Focal length = -0.4 m\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.4,Page no:72"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"m=4 #magnigication\n",
"f=20 #focal length in cm\n",
"\n",
"#Calculation\n",
"u=(20*3)/(4) #on simplifying (1/f)=(1/v)-(1/u)\n",
"v=(4*u) #calculating v in cm\n",
"\n",
"#Result\n",
"print\"Object distance,u= \",u,\"cm\" \n",
"print\"Image distance,v= \",v,\"cm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Object distance,u= 15 cm\n",
"Image distance,v= 60 cm\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.5,Page no:72"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"from scipy.optimize import fsolve \n",
"\n",
"#Variable declaration\n",
"u=14.0 #object distance in cm\n",
"f=-21.0 #focal distance in cm\n",
"\n",
"#Calculation\n",
"v=1/((1/f)-(1/u))\n",
"I=(3.0*v)/(-u) #using m=(1/0)=(v/u) \n",
"\n",
"#Result\n",
"print\"Image distance= \",v,\"cm\" \n",
"print\"I= \",I,\"cm\" "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Image distance= -8.4 cm\n",
"I= 1.8 cm\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.6,Page no:79"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"fe=5 #focal length in cm\n",
"D=25 #distance od distinct vision in cm\n",
"\n",
"#Calculation\n",
"m=1+(D/fe) #calculating magnifying power\n",
"\n",
"#Result\n",
"print\"magnifying Power = \",m "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"magnifying Power = 6\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.7,Page no:80"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"fe=5 #focal length in cm\n",
"D=25 #distance od distinct vision in cm\n",
"\n",
"#Calculation\n",
"mo=30/(1+(D/fe)) #calculating magnification of objective lens\n",
"\n",
"#Result\n",
"print\"Magnification produced by objective lens = \",mo "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Magnification produced by objective lens = 5\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.8,Page no:80"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"u=-6.0 #object distance in cm\n",
"fo=4.0 #focal distance in cm\n",
"fe=6.0 #focal length in cm\n",
"D=25.0 #distance of distinct vision in cm\n",
"\n",
"#Calculation\n",
"v=1/((1/u)+(1/fo)) #using (1/f)=(1/v)-(1/u)\n",
"m=(v/u)*(1+(D/fe)) #calculating m\n",
"\n",
"#Result\n",
"print\"Image distance in cm = \",v,\"cm\" \n",
"print\"Magnifying Power = \",round(-m,2) "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Image distance in cm = 12.0 cm\n",
"Magnifying Power = 10.33\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.9,Page no:81"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"D=25.0 #distance of distinct vision\n",
"u=-9.0 #object distance in cm\n",
"fe=10.0 #focal length in cm\n",
"\n",
"#Calculation\n",
"v=1/((1/fe)+(1/u)) #using (1/f)=(1/v)-(1/u)\n",
"m=(v/u) #calculating m\n",
"M=D/u #calculating Magnifying power of lens\n",
"\n",
"#Result\n",
"print\"Magnification of lens = \",m \n",
"print\"Magnifying Power = \",round(-M,1) "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Magnification of lens = 10.0\n",
"Magnifying Power = 2.8\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.10,Page no:82"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"fo=0.5 #focal length of eye lens\n",
"D=25 #distance of distinct vision\n",
"L=15 #length in cm\n",
"m=375 #magnification\n",
"\n",
"#Calculation\n",
"fe=(-L*D)/(fo*((L/fo)-m)) #calculating fe\n",
"\n",
"#Result\n",
"print\"Focal length of eye lens= \",round(fe,1),\"cm\" "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Focal length of eye lens= 2.2 cm\n"
]
}
],
"prompt_number": 33
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.11,Page no:86"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"m=5 #magnifying power\n",
"L=24 #length in cm\n",
"fe=4 #focal length in cm\n",
"\n",
"#Calculation\n",
"fo=5*fe #calculating fo\n",
"\n",
"#Result\n",
"print\"Focal length of lens = \",fo,\"cm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Focal length of lens = 20 cm\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.12,Page no:87"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"D=25.0 #distance of distinct vision in cm\n",
"fo=140.0 #focal length of eye lens\n",
"fe=5.0 #focal length in cm\n",
"\n",
"#Calculation\n",
"m=-(fo/fe) #calculating magnifying power\n",
"m1=-(fo/fe)*(1+(fe/D)) #calculating magnifying power\n",
"\n",
"#Result\n",
"print\"(a):Magnifying power at normal adjustment = \",m\n",
"print\"(b):Magnifying power atleast distance of distinct vision = \",m1"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a):Magnifying power at normal adjustment = -28.0\n",
"(b):Magnifying power atleast distance of distinct vision = -33.6\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.13,Page no:88"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"M=5 #Magnifying power\n",
"fo=10 #focal length of eye lens\n",
"\n",
"#Calculation\n",
"fe=fo/M #calculating fe\n",
"\n",
"#Result\n",
"print\"Focal length of eye lens= \",fe,\"cm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Focal length of eye lens= 2 cm\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.14,Page no:88"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"#Variable declaration \n",
"fo=75.0 #focal length of eye lens\n",
"D=25.0 #distance of distinct vision\n",
"fe=5.0 #focal of eye lens in cm\n",
"\n",
"#Calculation\n",
"M=-(fo/fe)*(1+(fe/D)) #calculating M\n",
"\n",
"#Result\n",
"print\"Magnifying power = \",M"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Magnifying power = -18.0\n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example no:3.15,Page no:88"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#Variable declaration \n",
"M=7 #magnifying power\n",
"L=40 #length\n",
"\n",
"#Calculation\n",
"fe=(L/(M+1)) #focal length of eye lens in cm\n",
"fo=(M*fe) #calculating focal length\n",
"\n",
"#Result\n",
"print\"Focal Length of lens=\",fo,\"cm\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Focal Length of lens= 35 cm\n"
]
}
],
"prompt_number": 13
}
],
"metadata": {}
}
]
}