From 37d315828bbfc0f5cabee669d2b9dd8cd17b5154 Mon Sep 17 00:00:00 2001 From: hardythe1 Date: Wed, 17 Jun 2015 11:14:34 +0530 Subject: add books --- sample_notebooks/nemichand /Chapter1_1.ipynb | 227 +++++++++++++++++++++++++++ 1 file changed, 227 insertions(+) create mode 100755 sample_notebooks/nemichand /Chapter1_1.ipynb (limited to 'sample_notebooks/nemichand ') diff --git a/sample_notebooks/nemichand /Chapter1_1.ipynb b/sample_notebooks/nemichand /Chapter1_1.ipynb new file mode 100755 index 00000000..43f5bce4 --- /dev/null +++ b/sample_notebooks/nemichand /Chapter1_1.ipynb @@ -0,0 +1,227 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:60b1203d60983bbbb28528cd720bc31b7ac71ec9fc83b7d2e5e78e90b9f2b472" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter1-Introduction" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex1-pg32" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math\n", + "\n", + "#calculate the steady state\n", + "\n", + "\n", + "##The thickness of the slab(L) is 80mm or .08m\n", + "##The thermal conductivity(k)of the material is .20 W/(m*K)\n", + "T1=40.;\n", + "T2=20.;\n", + "L=.08;\n", + "k=.20;\n", + "##The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L\n", + "print(\"The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L in W/m^2 \")\n", + "q=k*(T1-T2)/L\n", + "print(q)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The steady state heat transfer rate per unit area through the thick slab is given by q=k(T1-T2)/L in W/m^2 \n", + "50.0\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex2-pg32" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math\n", + "#calculate the thickness of masonry wall\n", + "print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 2\")\n", + "##The thermal conductivity(km)of masonry wall is .8 W/(mK)\n", + "##The thermal conductivity(kc)of composite wall is .2 W/(mK)\n", + "##The thickness of composite wall(Lc) is 100 mm or .1 m\n", + "km=.8;\n", + "kc=.2;\n", + "Lc=.1;\n", + "##The thickness of masonry wall(Lm) is to be found. \n", + "##The steady state heat flow(qm)through masonry wall is km(T1-T2)/L\n", + "## The steady state heat flow(qc)through composite wall is kc(T1-T2)/L\n", + "##As the steady rate of heat flow through masonry wall is 80% that through composite wall and both the wall have same surface area and same temp. difference so qm/qc=0.8=(km/kc)*(Lc/Lm)\n", + "##The thickness of masonry wall is Lm.\n", + "print (\"The thickness of masonry wall is Lm in m\")\n", + "Lm=(km/kc)*(Lc/(0.8))\n", + "print(Lm)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Introduction to heat transfer by S.K.Som, Chapter 1, Example 2\n", + "The thickness of masonry wall is Lm in m\n", + "0.5\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex4-pg36" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "## printlay warning for floating point exception\n", + "print(\"Introduction to heat transfer by S.K.Som Chapter 1 Example 4\")\n", + "hbr=200.;\n", + "Tinf=100.;\n", + "Ts=20.;\n", + "##The rate of heat transfer per unit area is q\n", + "print (\"The rate of heat transfer per unit area q=hbr*(Tinf-Ts) in W/m^2\")\n", + "q=hbr*(Tinf-Ts)\n", + "print(q)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Introduction to heat transfer by S.K.Som Chapter 1 Example 4\n", + "The rate of heat transfer per unit area q=hbr*(Tinf-Ts) in W/m^2\n", + "16000.0\n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex5-pg36" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "import math\n", + "#calculat e surface area\n", + "print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 5\")\n", + "\n", + "hbr=800.;\n", + "deltaT=(75.-25.);\n", + "Q=20.;\n", + "print(\"The heat exchanger surface area(A)in m^2 required for 20 MJ/h of heating is \")\n", + "A = (Q*10**6.)/(3600.*hbr*deltaT)\n", + "print round(A,2)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Introduction to heat transfer by S.K.Som, Chapter 1, Example 5\n", + "The heat exchanger surface area(A)in m^2 required for 20 MJ/h of heating is \n", + "0.14\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex6-pg37" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "##The ambient temprature (Tinf) \n", + "print(\"Introduction to heat transfer by S.K.Som, Chapter 1, Example 6\")\n", + "Ts=225.;\n", + "Tinf=25.;\n", + "## |because it is modulus function and it converts negative values to positive value.\n", + "X=0.02;\n", + "A=.1;\n", + "m=4;\n", + "cp=2.8;\n", + "hbr=(m*cp*10**3*X)/(A*(Ts-Tinf))\n", + "print round(hbr,2)" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Introduction to heat transfer by S.K.Som, Chapter 1, Example 6\n", + "11.2\n" + ] + } + ], + "prompt_number": 8 + } + ], + "metadata": {} + } + ] +} \ No newline at end of file -- cgit