From c7fe425ef3c5e8804f2f5de3d8fffedf5e2f1131 Mon Sep 17 00:00:00 2001
From: hardythe1
Date: Tue, 7 Apr 2015 15:58:05 +0530
Subject: added books

---
 sample_notebooks/harishsahu/Chapter1_2.ipynb | 134 +++++++++++++++++++++++++++
 1 file changed, 134 insertions(+)
 create mode 100755 sample_notebooks/harishsahu/Chapter1_2.ipynb

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diff --git a/sample_notebooks/harishsahu/Chapter1_2.ipynb b/sample_notebooks/harishsahu/Chapter1_2.ipynb
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+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:c5f8065703fbeb58a71f73144f936d51092395de25fe2bd4b3e4c9b6e159ad53"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter1-Mohrs circle"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex1-pg12"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "##Mohr's circle\n",
+      "#calculate center of the circle and maxi principal stress and pricipal stress and maxi shearing stresss\n",
+      "import numpy\n",
+      "from numpy.linalg import inv\n",
+      "import math\n",
+      "sigma=((40+80)/2.)\n",
+      "print'%s %.2f %s'%(\"center of the circle in MPa = \",sigma,\"\")\n",
+      "\n",
+      "##solution a\n",
+      "x=((80-40)**2.);\n",
+      "y=30**2.;\n",
+      "sigma1=60.+math.sqrt((.25*x)+y)\n",
+      "print'%s %.2f %s'%(\"maxi pricipal stress in MPa = \",sigma1,\"\");## print'%s %.2f %s'%laying result\n",
+      "sigma2=60.-math.sqrt((.25*x)+y)\n",
+      "print'%s %.2f %s'%(\"mini pricipal stress in MPa = \",sigma2,\"\");## print'%s %.2f %s'%laying result\n",
+      "theta1=((math.atan((30./20.))/2)*57.3)\n",
+      "print'%s %.2f %s'%(\"pricipal stresses in degree\",theta1,\"\");## print'%s %.2f %s'%laying result\n",
+      "theta2=(((math.atan(30/20.))+180.)/2.)*57.3\n",
+      "print'%s %.2f %s'%(\"pricipal stresses in degree\",theta2,\"\");## print'%s %.2f %s'%laying result\n",
+      "\n",
+      "##solution b\n",
+      "tau=math.sqrt((.25*x)+y)\n",
+      "print'%s %.2f %s'%(\"maxi shearing stress in MPa = \",tau,\"\");## print'%s %.2f %s'%laying result\n",
+      "theta3=theta1+45.\n",
+      "print'%s %.2f %s'%(\"stress in MPa = \",theta3,\"\");## print'%s %.2f %s'%laying result\n",
+      "theta4=theta2+45\n",
+      "print'%s %.2f %s'%(\"stress in MPa = \",theta4,\"\");## print'%s %.2f %s'%laying result\n",
+      "\n",
+      "##final solution in matrix form\n",
+      "p=([[80 ,30], [30 ,40]])\n",
+      "print(p) \n",
+      "q=([[sigma1, 0 ],[0 ,sigma2]])\n",
+      "print(q)\n",
+      "r=([[sigma ,-tau], [-tau ,sigma]])\n",
+      "print(r)\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "center of the circle in MPa =  60.00 \n",
+        "maxi pricipal stress in MPa =  96.06 \n",
+        "mini pricipal stress in MPa =  23.94 \n",
+        "pricipal stresses in degree 28.16 \n",
+        "pricipal stresses in degree 5185.16 \n",
+        "maxi shearing stress in MPa =  36.06 \n",
+        "stress in MPa =  73.16 \n",
+        "stress in MPa =  5230.16 \n",
+        "[[80, 30], [30, 40]]\n",
+        "[[96.05551275463989, 0], [0, 23.944487245360108]]\n",
+        "[[60.0, -36.05551275463989], [-36.05551275463989, 60.0]]\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex2-pg17"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "##Mohr's circle\n",
+      "#calculate radius of the circle in and orientation of the stress\n",
+      "import math\n",
+      "radius=((14+28)/2.)\n",
+      "print'%s %.2f %s'%(\"radius of the circle in degree = \",radius,\"\")\n",
+      "sigma1=(7+radius *math.cos(60/57.3))\n",
+      "print'%s %.2f %s'%(\" the circle in MPa = \",sigma1,\"\")\n",
+      "sigma2=(7-radius *math.cos(60/57.3))\n",
+      "print'%s %.2f %s'%(\" the circle in MPa = \",sigma2,\"\")\n",
+      "tau1=radius*math.sin(60./57.3)\n",
+      "print'%s %.2f %s'%(\" orientation of the stresses in MPa = \",tau1,\"\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "radius of the circle in degree =  21.00 \n",
+        " the circle in MPa =  17.50 \n",
+        " the circle in MPa =  -3.50 \n",
+        " orientation of the stresses in MPa =  18.19 \n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
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-- 
cgit