From d36fc3b8f88cc3108ffff6151e376b619b9abb01 Mon Sep 17 00:00:00 2001 From: kinitrupti Date: Fri, 12 May 2017 18:40:35 +0530 Subject: Revised list of TBCs --- sample_notebooks/HeminChheda/chapter1.ipynb | 281 ---------------------------- 1 file changed, 281 deletions(-) delete mode 100755 sample_notebooks/HeminChheda/chapter1.ipynb (limited to 'sample_notebooks/HeminChheda/chapter1.ipynb') diff --git a/sample_notebooks/HeminChheda/chapter1.ipynb b/sample_notebooks/HeminChheda/chapter1.ipynb deleted file mode 100755 index af04eee8..00000000 --- a/sample_notebooks/HeminChheda/chapter1.ipynb +++ /dev/null @@ -1,281 +0,0 @@ -{ - "metadata": { - "name": "" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 1:Water" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:1,Page no:1.7" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Variable declaration\n", - "W1=219.0 #amount of Mg(HCO3)2 in water in ppm#\n", - "W2=36.0 #amount of Mg2+ in water in ppm#\n", - "W3=18.3 #amount of (HCO3)- in water in ppm#\n", - "W4=1.5 #amount of H+_in water in ppm#\n", - "M1=100/146.0 #multiplication factor of Mg(HCO3)2#\n", - "M2=100/24.0 #multiplication factor of Mg(HCO3)2#\n", - "M3=100/122.0 #multiplication factor of Mg(HCO3)2#\n", - "M4=100/2.0 #multiplication factor of Mg(HCO3)2#\n", - "\n", - "#Calculation\n", - "P1=W1*M1 #in terms of CaCO3#\n", - "P2=W2*M2 #in terms of CaCO3#\n", - "P3=W3*M3 #in terms of CaCO3#\n", - "P4=W4*M4 #in terms of CaCO3#\n", - "L=0.74*((2*P1)+P2+P3+P4) \n", - "\n", - "R=1.0 #water supply rate in m**3/s#\n", - "D=R*60.0*60.0*24.0*L \n", - "K=D*1000.0 #in lit/day#\n", - "T=K/10.0**9 #in tonnes#\n", - "S=1.06*(P2+P4-P3) \n", - "D2=R*60*60*24*S \n", - "A=D2*1000 #in lit/day#\n", - "B=A/10.0**9 #in tonnes#\n", - "J1=90/100.0 #purity of lime#\n", - "J2=95/100.0 #purity of soda#\n", - "C1=500.0 #cost of one tonne lime#\n", - "C2=7000.0 #cost of one tonne soda#\n", - "CL=round(T,1)*C1/J1 \n", - "print\"\\ncost of lime is\",CL,\"Rs\"\n", - "CS=round(B,1)*C2/J2 \n", - "print\"\\ncost of soda is \",CS,\"Rs\"\n", - "C=CL+CS \n", - "\n", - "#Result\n", - "print\"\\ntotal cost is \",round(C) ,\"Rs\"\n", - "\n", - "\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "\n", - "cost of lime is 19166.6666667 Rs\n", - "\n", - "cost of soda is 141473.684211 Rs\n", - "\n", - "total cost is 160640.0 Rs\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:15,Page no:1.25" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Variable declaration\n", - "W1=40.0 #amount of Ca2+ in water in mg/l#\n", - "W2=24.0 #amount of Mg2+ in water in mg/l#\n", - "W3=8.05 #amount of Na+ in water in mg/l#\n", - "W4=183.0 #amount of (HCO3)- in water in mg/l#\n", - "W5=55.68 #amount of (SO4)2- in water in mg/l#\n", - "W6=6.74 #amount of Cl- in water in mg/l#\n", - "M1=100/40.0 #multiplication factor of Ca2+#\n", - "M2=100/24.0 #multiplication factor of Mg2+#\n", - "M3=100/(23.0*2) #multiplication factor of Na+#\n", - "M4=100/(61.0*2) #multiplication factor of (HCO3)-#\n", - "M5=100/96.0 #multiplication factor of (SO4)2-#\n", - "M6=100/(35.5*2) #multiplication factor of Cl-#\n", - "\n", - "#Calculation\n", - "P1=W1*M1 #in terms of CaCO3#\n", - "P2=W2*M2 #in terms of CaCO3#\n", - "P3=W3*M3 #in terms of CaCO3#\n", - "P4=W4*M4 #in terms of CaCO3#\n", - "P5=W5*M5 #in terms of CaCO3#\n", - "P6=W6*M6 #in terms of CaCO3#\n", - "\n", - "\n", - "#Result\n", - "print\"\\nCalcium alkalinity =\",P1,\"ppm\" \n", - "print\"\\nMagnesium alkalinity =\",P4-P1,\"ppm\"\n", - "print\"\\n total alkalinity = \",P1+P4-P1,\"ppm\"\n", - "print\"\\n total hardness = \",P1+P2,\"ppm\"\n", - "print\"\\nCa temporary hardness = \",P1,\"ppm\"\n", - "print\"\\nMg temporary hardness = \",P4-P1,\"ppm\"\n", - "print\"\\nMg permanant hardness = \",P2-(P4-P1),\"ppm\"\n", - "print\"\\nSalts are:\"\n", - "print\"\\nCa(HCO3)2 salt = \",P1,\"ppm\"\n", - "print\"\\nMg(HCO3)2 salt = \",P4-P1,\"ppm\"\n", - "print\"\\nMgSO4 salt = \",P2-(P4-P1),\"ppm\"\n", - "print\"\\nNaCl salt = \",P6,\"ppm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "\n", - "Calcium alkalinity = 100.0 ppm\n", - "\n", - "Magnesium alkalinity = 50.0 ppm\n", - "\n", - " total alkalinity = 150.0 ppm\n", - "\n", - " total hardness = 200.0 ppm\n", - "\n", - "Ca temporary hardness = 100.0 ppm\n", - "\n", - "Mg temporary hardness = 50.0 ppm\n", - "\n", - "Mg permanant hardness = 50.0 ppm\n", - "\n", - "Salts are:\n", - "\n", - "Ca(HCO3)2 salt = 100.0 ppm\n", - "\n", - "Mg(HCO3)2 salt = 50.0 ppm\n", - "\n", - "MgSO4 salt = 50.0 ppm\n", - "\n", - "NaCl salt = 9.49295774648 ppm\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:19,Page no:1.39" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Variable declaration\n", - "P=4.7 #required HCl in ml using HpH indicator #\n", - "H=10.5 #required HCl im ml using MeOH indicator#\n", - "M=P+H \n", - "N=0.02 #normality of HCl#\n", - "\n", - "print\"\\nSince P<0.5*M sample contain (CO3)2- and (HCO3)- alkalinity\"\n", - "C=50 #equivalent of CaCO3 in mg for 1ml 1N HCl#\n", - "\n", - "#Calculation\n", - "A=C*(2*P)*N #amount of (CO3)2- alkalinity in mg in 100 ml of water#\n", - "B=A*1000/100 \n", - "D=C*(M-2*P)*N #the amount of (HCO3)- alkalinity in mg in 100 ml of water#\n", - "E=D*1000/100 \n", - "T=B+E \n", - "\n", - "#Result\n", - "print\"\\nTotal alkalinity is \",T,\"mg/l or ppm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "\n", - "Since P<0.5*M sample contain (CO3)2- and (HCO3)- alkalinity\n", - "\n", - "Total alkalinity is 152.0 mg/l or ppm\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example no:25,Page no:1.56" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Variable declaration\n", - "W1=160.0 #amount of Ca2+ in ppm#\n", - "W2=88.0 #amount of Mg2+ in ppm#\n", - "W3=72.0 #amount of CO2 in ppm#\n", - "W4=488.0 #amount of (HCO3)- in ppm#\n", - "W5=139.0 #amount of (FeSO4).7H2O in ppm#\n", - "M1=100/40.0 #multiplication factor of Ca2+#\n", - "M2=100/24.0 #multiplication factor of Mg2+#\n", - "M3=100/44.0 #multiplication factor of CO2#\n", - "M4=100/(61.0*2.0) #multiplication factor of (HCO3)-#\n", - "M5=100/278.0 #multiplication factor of (FeSO4).7H2O#\n", - "\n", - "P1=400 #in terms of CaCO3#\n", - "P2=300 #in terms of CaCO3#\n", - "P3=200 #in terms of CaCO3#\n", - "P4=400 #in terms of CaCO3#\n", - "P5=50 #in terms of CaCO3#\n", - "V=100000.0 #volume of water in litres#\n", - "\n", - "\n", - "#Calculation\n", - "L=0.74*(P2+P3+P4+P5)*V #lime required in mg#\n", - "L=L/10.0**6 \n", - "S=1.06*(P1+P2+P5-P4)*V #soda required in mg#\n", - "S=S/10.0**6 \n", - "\n", - "#Result\n", - "print\"Lime required is \",L,\"kg\"\n", - "print\"\\nSoda required is \",S,\"kg\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Lime required is 70.3 kg\n", - "\n", - "Soda required is 37.1 kg\n" - ] - } - ], - "prompt_number": 4 - }, - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit