From d36fc3b8f88cc3108ffff6151e376b619b9abb01 Mon Sep 17 00:00:00 2001 From: kinitrupti Date: Fri, 12 May 2017 18:40:35 +0530 Subject: Revised list of TBCs --- modern_physics_by_Satish_K._Gupta/chap2.ipynb | 534 -------------------------- 1 file changed, 534 deletions(-) delete mode 100755 modern_physics_by_Satish_K._Gupta/chap2.ipynb (limited to 'modern_physics_by_Satish_K._Gupta/chap2.ipynb') diff --git a/modern_physics_by_Satish_K._Gupta/chap2.ipynb b/modern_physics_by_Satish_K._Gupta/chap2.ipynb deleted file mode 100755 index efbea0a7..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap2.ipynb +++ /dev/null @@ -1,534 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:1e2d45d8326c66f64e42e0f8f482f41d5aabf3a1eabc7e50f07a0c18121fe999" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 2 Electric field" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.1 Page no 39" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "m=10**-7 #Kg\n", - "q=1.6*10**-19 #C\n", - "g=9.8\n", - "\n", - "#Calculation\n", - "E=(m*g)/q\n", - "\n", - "#Result\n", - "print\"Electric field strength required is\", E" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Electric field strenght required is 6.125e+12\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.2 Page no 39" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "m=10.0**-3 #Kg\n", - "q=5*10**-6 #C\n", - "u=20 #m/s\n", - "E=2*10**5 #N/C\n", - "\n", - "#Calculation\n", - "F=q*E\n", - "a=-F/m\n", - "S=-u**2/(2.0*a)\n", - "\n", - "#Result\n", - "print\"Distance travelled is\", S,\"m\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Distance travelled is 0.2 m\n" - ] - } - ], - "prompt_number": 6 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.3 Page no 39" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "E=2.55*10**4 #V/m\n", - "a=1.26*10**3 #Kg/m**4\n", - "g=9.81 #m/s**2\n", - "e=1.6*10**-19\n", - "\n", - "#Calculation\n", - "import math\n", - "q=12*e\n", - "Fe=q*E\n", - "r=((3*Fe)/(4.0*math.pi*a*g))**0.333\n", - "\n", - "#Result\n", - "print\"The radius of the drop is\", round(r*10**4,5)*10**3,\"*10**-4 mm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The radius of the drop is 9.95 *10**-4 mm\n" - ] - } - ], - "prompt_number": 28 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.4 Page no 39" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "m=80.0*10**-6 #Kg\n", - "q=2*10**-8 #C\n", - "E=20000 #V/m\n", - "g=9.8\n", - "\n", - "#Calculation\n", - "import math\n", - "a=(q*E)/(m*g)\n", - "a1=math.atan(a)*180/3.14\n", - "T=(q*E)/(math.sin(a1*3.14/180.0))\n", - "\n", - "#Result\n", - "print\"Tension in the thread of the pendulum is\", round(T*10**4,1),\"*10**-4 N\"\n", - "print\"Angle it make with the vertical is\",round(a1,2),\"Degree C\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Tension in the thread of the pendulum is 8.8 *10**-4 N\n", - "Angle it make with the vertical is 27.04 Degree C\n" - ] - } - ], - "prompt_number": 41 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.5 Page no 40" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "q1=2.0*10**-7 #C\n", - "q2=1.0*10**-7 #C\n", - "r=10.0**-2 #m\n", - "m=9*10**9\n", - "\n", - "#Calculation\n", - "import math\n", - "E1=(m*q1)/r**2\n", - "E2=(m*q2)/r**2\n", - "\n", - "#Result\n", - "print\"Magnitude of field E1 is\", E1*10**-7,\"*10**7 N/C\"\n", - "print\"Magnitude of field E2 is\", E2*10**-6,\"*10**6 N/C\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Magnitude of field E1 is 1.8 *10**7 N/C\n", - "Magnitude of field E2 is 9.0 *10**6 N/C\n" - ] - } - ], - "prompt_number": 50 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.6 Page no 40" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "q1=5.0*10**-19 #c\n", - "q2=20*10**-19\n", - "r=2.0 #m\n", - "\n", - "#Calculation\n", - "import math\n", - "x=-math.sqrt(q2/q1)\n", - "x1=math.sqrt(q2/(q1*3))\n", - "\n", - "#Result\n", - "print\"The point on the line joining is\", round(x,1),\"m and \",round(x1,1),\"m\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The point on the line joining is -2.0 m and 1.2 m\n" - ] - } - ], - "prompt_number": 60 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.7 Page no 40" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "r=0.2\n", - "m=9*10**9\n", - "qa=3*10**-6\n", - "q=1.5*10**-9\n", - "\n", - "#Calculation\n", - "a=r/2.0\n", - "Ea=(m*qa)/a**2\n", - "Eb=(m*qa)/a**2\n", - "E=Ea+Eb\n", - "F=q*E\n", - "\n", - "#Result\n", - "print\"(a) Electric field at the mid point is\", E*10**-6,\"*10**6 N/C (along OB)\"\n", - "print\"(b) Force experienced by the test charge is\",F*10**3,\"*10**-3 N (along OA)\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a) Electric field at the mid point is 5.4 *10**6 N/C (along OB)\n", - "(b) Force experienced by the test charge is 8.1 *10**-3 N (along OA)\n" - ] - } - ], - "prompt_number": 71 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.8 Page no 40" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "qa=16*10**-6 #c\n", - "qb=-9.0*10**-6 #C\n", - "r=0.08 #m\n", - "\n", - "#Calculation\n", - "x=-(qa/qb)*r\n", - "\n", - "#Result\n", - "print\"Position of the point is\", round(x,2),\"m\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Position of the point is 0.14 m\n" - ] - } - ], - "prompt_number": 82 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.9 Page no 41" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "m=9*10**9\n", - "qa=4*10**-6\n", - "r=2.0*10**-2\n", - "r1=10**-2\n", - "qb=2*10**-6\n", - "\n", - "#Calculation\n", - "import math\n", - "Ea=(m*qa)/r**2\n", - "Eb=(m*qb)/r1**2\n", - "a=r1/r\n", - "E=math.sqrt(Ea**2+Eb**2+(2*Ea*Eb*a))\n", - "a11=Ea*(math.sin(60)*180/3.14)/(Ea+Eb*(math.cos(60)*180/3.14))\n", - "\n", - "#Result\n", - "print\"Position is\", round(a11,2)" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Position is 0.16\n" - ] - } - ], - "prompt_number": 33 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.10 Page no 41" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "q=500*10**-6\n", - "r=0.1 #m\n", - "d=0.2\n", - "m=9*10**9\n", - "\n", - "#Calculation\n", - "p=q*r\n", - "a=r/2.0\n", - "R=d+a\n", - "E=(m*2*p*R)/((R**2-a**2)**2)\n", - "\n", - "#Result\n", - "print\"Electric dipole moment of the dipole is\", p,\"Cm\"\n", - "print\"Electric field due to dipole is\",E*10**-7,\"*10**7 N/C\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Electric dipole moment of the dipole is 5e-05 Cm\n", - "Electric field due to dipole is 6.25 *10**7 N/C\n" - ] - } - ], - "prompt_number": 21 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.11 Page no 41" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "q=0.2*10**-12 #C\n", - "w=10**-8 #m\n", - "r=0.1 #m\n", - "e=9*10**9\n", - "\n", - "#Calculation\n", - "p=q*w\n", - "E=(e*2*p)/r**3\n", - "\n", - "#Result\n", - "print\"The electric field at an axical point at a distance of 10cm from there mid point is\", E*10**8,\"*10**-8 N/C\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The electric field at an axical point at a distance of 10cm from there mid point is 3.6 *10**-8 N/C\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.13 Page no 42" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "E=10.0**4\n", - "t=9*10**-26 #Nm\n", - "\n", - "#Calculation\n", - "import math \n", - "p=t/(E*math.sin(30*3.14/180.0))\n", - "\n", - "#Result\n", - "print\"Dipole moment of the dipole is\", round(p*10**29,1),\"*10**-19 Cm\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Dipole moment of the dipole is 1.8 *10**-19 Cm\n" - ] - } - ], - "prompt_number": 10 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2.17 Page no 43" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "p=-10**-7 #Cm\n", - "i=10**5\n", - "\n", - "#Calculation\n", - "F=p*i\n", - "\n", - "#Result\n", - "print\"Force is given by\", F,\"N\"\n", - "print\"Torque is zero\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Force is given by -0.01 N\n", - "Torque is zero\n" - ] - } - ], - "prompt_number": 15 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit