From 6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d Mon Sep 17 00:00:00 2001 From: kinitrupti Date: Fri, 12 May 2017 18:53:46 +0530 Subject: Removed duplicates --- backup/temp_version_backup/chapter13.ipynb | 339 ----------------------------- 1 file changed, 339 deletions(-) delete mode 100755 backup/temp_version_backup/chapter13.ipynb (limited to 'backup/temp_version_backup/chapter13.ipynb') diff --git a/backup/temp_version_backup/chapter13.ipynb b/backup/temp_version_backup/chapter13.ipynb deleted file mode 100755 index de1fc475..00000000 --- a/backup/temp_version_backup/chapter13.ipynb +++ /dev/null @@ -1,339 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:4be2df010e0c0a454b43a2b1267f5b9f24594cfd973fe52088cb80f0e511082b" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 13 Transmission lines" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 13.1 Page no 483" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "f= 450.0*10**6\n", - "\n", - "#Calculation\n", - "lamda = 984/f\n", - "len =0.1*lamda\n", - "\n", - "#Result\n", - "print\"feet long conductors would be considered as the transmission line \",round(len*10**6,3),\"ft\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "feet long conductors would be considered as the transmission line 0.219 ft\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 13.2 Page no 484" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "lamda = 2.19\n", - "\n", - "#Calculation\n", - "len = (3/8.0)*lamda\n", - "\n", - "#Result\n", - "print\"The pyhsical length of the transmission line \",round(len,2),\"feet\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The pyhsical length of the transmission line 0.82 feet\n" - ] - } - ], - "prompt_number": 4 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 13.3 Page no 492" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "len = 165\n", - "attn_100ft = 5.3\n", - "pin = 100\n", - "attn_ft = 5.3/100.0\n", - "\n", - "#Calculation\n", - "total_attn = attn_ft * len\n", - "pout = pin *0.1335\n", - "\n", - "#Result\n", - "print\"The total attenuation of the cable is \",total_attn,\"dB\"\n", - "print\"Output power is \",pout,\"W\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The total attenuation of the cable is 8.745 dB\n", - "Output power is 13.35 W\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 13.4 Page no 494" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "len =150\n", - "C =13.5\n", - "Z0 =93\n", - "f =2.5*10**6\n", - "attn_100ft =2.8\n", - "\n", - "#Calculation\n", - "L =C*Z0**2\n", - "td =(L*C)**0.5\n", - "theta = ((360)*188.3)/(1/f)\n", - "attn_ft = attn_100ft/100.0\n", - "total_attn = attn_ft*150\n", - "\n", - "print\"(a) The load impedance required to terminate the the line to avoid the reflections is %d ohm\",Z0\n", - "print\"(b) The equivalent inductance per feet is \",L/10**3,\"nh\"\n", - "print\"(c) The time delay introduced by the cable per feet is \",td/10**3,\"ns\"\n", - "print\"(d) The phase shift occurs in degrees for the 2.5 Mhz sine wave is \",theta/10**9\n", - "print\"(e) The total attenuation is \",total_attn,\"db\"\n", - "\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a) The load impedance required to terminate the the line to avoid the reflections is %d ohm 93\n", - "(b) The equivalent inductance per feet is 116.7615 nh\n", - "(c) The time delay introduced by the cable per feet is 1.2555 ns\n", - "(d) The phase shift occurs in degrees for the 2.5 Mhz sine wave is 169.47\n", - "(e) The total attenuation is 4.2 db\n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 13.5 Page no 501" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "vmax= 52.0\n", - "vmin= 17.0\n", - "Z0 = 75\n", - "\n", - "#calculation\n", - "SWR = vmax/vmin\n", - "ref_coeff = (vmax-vmin)/(vmax+vmin)\n", - "Zl1 = Z0*SWR\n", - "Zl2 = Z0/SWR\n", - "\n", - "#Result\n", - "print\"(a) The standing wave ratio is \",round(SWR,2)\n", - "print\"(b) Reflection coefficient is \",round(ref_coeff,2)\n", - "print\"The value of resistive load is \",round(Zl1,2),\"ohm or\",round(Zl2,2),\"ohm\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(a) The standing wave ratio is 3.06\n", - "(b) Reflection coefficient is 0.51\n", - "The value of resistive load is 229.41 ohm or 24.52 ohm\n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 13.6 Page no 503" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "SWR =3.05\n", - "ref_pwr =0.2562\n", - "pin =30\n", - "\n", - "#calculation\n", - "pout = pin -(pin*((SWR-1)/(SWR+1))**2)\n", - "\n", - "#Result\n", - "print\"The output power of the cable is \",round(pout,3),\"W\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The output power of the cable is 22.314 W\n" - ] - } - ], - "prompt_number": 9 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 13.7 Page no 508" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "C =4*10**-12\n", - "f =800*10**6\n", - "diele = 3.5\n", - "h = 0.0625\n", - "w = 0.13\n", - "t = 0.002\n", - "\n", - "#Calculation\n", - "import math\n", - "Z0 = 38.8*math.log(0.374/0.106)\n", - "Xc = 1/(6.28*f*C)\n", - "\n", - "#Result\n", - "print\"The charecteristics impedance of the transmission line is \",round(Z0,1),\"ohm\"\n", - "print\"The reactance of the capacitor is \",round(Xc,2),\"ohm\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The charecteristics impedance of the transmission line is 48.9 ohm\n", - "The reactance of the capacitor is 49.76 ohm\n" - ] - } - ], - "prompt_number": 13 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 13.8 Page no 508" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Given\n", - "lamda = (984/800.0)\n", - "lamda_8 =lamda/8.0\n", - "\n", - "#Calculation\n", - "len = lamda_8*12*(1/3.6**0.5)\n", - "\n", - "#Result\n", - "print\"The length of the transmission line is \",round(len,3),\"inch\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "The length of the transmission line is 0.972 inch\n" - ] - } - ], - "prompt_number": 1 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit