From d36fc3b8f88cc3108ffff6151e376b619b9abb01 Mon Sep 17 00:00:00 2001
From: kinitrupti
Date: Fri, 12 May 2017 18:40:35 +0530
Subject: Revised list of TBCs

---
 .../Chapter_5.ipynb                                | 199 +++++++++++++++++++++
 1 file changed, 199 insertions(+)
 create mode 100755 backup/Thermodynamics_for_Engineers_version_backup/Chapter_5.ipynb

(limited to 'backup/Thermodynamics_for_Engineers_version_backup/Chapter_5.ipynb')

diff --git a/backup/Thermodynamics_for_Engineers_version_backup/Chapter_5.ipynb b/backup/Thermodynamics_for_Engineers_version_backup/Chapter_5.ipynb
new file mode 100755
index 00000000..60d3de94
--- /dev/null
+++ b/backup/Thermodynamics_for_Engineers_version_backup/Chapter_5.ipynb
@@ -0,0 +1,199 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:86a66a56e6c068c1b5488c8e726c9aecdd48422f90b429aec4b5cc311da3bb32"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 5 - Actual Gases"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1 - Pg 74"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the volume occupied by the gas and also the tabulated volume\n",
+      "#Initialization of variables\n",
+      "m=20. #lbm\n",
+      "P=1000. #psia\n",
+      "T=580. #R\n",
+      "R=35.12\n",
+      "#calculations\n",
+      "print '%s' %(\"From table 5-2,\")\n",
+      "z=0.667\n",
+      "V=z*m*R*T/(P*144.)\n",
+      "vt=0.0935\n",
+      "vtt=vt*m\n",
+      "#results\n",
+      "print '%s %.3f %s' %(\"Volume occupied =\",V,\"cu ft\")\n",
+      "print '%s %.2f %s' %(\"\\n Tablulated value for volume =\",vtt,\" cu ft\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "From table 5-2,\n",
+        "Volume occupied = 1.887 cu ft\n",
+        "\n",
+        " Tablulated value for volume = 1.87  cu ft\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2 - Pg 74"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the pressure obtained and theoretical pressure\n",
+      "#Initialization of variables\n",
+      "m=90 #lbm\n",
+      "T=200+459.7 #R\n",
+      "Tc=232.7+459.7 #R\n",
+      "R0=1545.\n",
+      "M=120.9\n",
+      "V=30. #cu ft\n",
+      "#calculations\n",
+      "R=R0/M\n",
+      "print '%s' %(\"From fig 5.5\")\n",
+      "z=0.883\n",
+      "P=z*R*m*T/V/144.\n",
+      "vc=V/m\n",
+      "P2=156.1 #psia\n",
+      "#results\n",
+      "print '%s %.2f %s' %(\"Pressure obtained =\",P,\"psia\")\n",
+      "print '%s %.1f %s' %(\"\\n Theoretical pressure =\",P2,\"psia\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "From fig 5.5\n",
+        "Pressure obtained = 155.08 psia\n",
+        "\n",
+        " Theoretical pressure = 156.1 psia\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3 - Pg 84"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the heat added in both cases\n",
+      "#Initialization of variables\n",
+      "import math\n",
+      "T1=140+460. #R\n",
+      "T2=240 +460. #R\n",
+      "N=1.\n",
+      "#calculations\n",
+      "Q=N*(9.47*(T2-T1)-3.47*1000. *math.log(T2/T1) -1.16*math.pow(10,6) *(1/T2-1/T1))\n",
+      "Tm=(T1+T2)/2\n",
+      "Cp=9.47-3.47*1000. /Tm +1.16*math.pow(10,6) /Tm/Tm\n",
+      "Q2=N*Cp*(T2-T1)\n",
+      "#results\n",
+      "print '%s %d %s' %(\"Heat added in case 1 =\",Q,\"Btu\")\n",
+      "print '%s %.1f %s' %(\"\\n Heat added in case 2 =\",Q2,\"Btu\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Heat added in case 1 = 688 Btu\n",
+        "\n",
+        " Heat added in case 2 = 687.7 Btu\n"
+       ]
+      }
+     ],
+     "prompt_number": 5
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 4 - Pg 85"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the heat added in both cases\n",
+      "#Initialization of variables\n",
+      "import math\n",
+      "Rj=1.985\n",
+      "N=1\n",
+      "T1=540.+460 #R\n",
+      "T2=3540.+460 #R\n",
+      "#calculations\n",
+      "Q=N*(14.215*(T2-T1)-6.53*1000. *math.log(T2/T1) -1.41*math.pow(10,6) *(1/T2-1/T1))\n",
+      "Tm=(T1+T2)/2\n",
+      "Cv=14.215-6.53*1000. /Tm +1.41*math.pow(10,6) /Tm/Tm\n",
+      "Q2=N*Cv*(T2-T1)\n",
+      "#results\n",
+      "print '%s %.1f %s' %(\"Heat added in case 1 =\",Q,\"Btu\")\n",
+      "print '%s %.1f %s' %(\"\\n Heat added in case 2 =\",Q2,\"Btu\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Heat added in case 1 = 34650.0 Btu\n",
+        "\n",
+        " Heat added in case 2 = 35485.8 Btu\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file
-- 
cgit