From 6279fa19ac6e2a4087df2e6fe985430ecc2c2d5d Mon Sep 17 00:00:00 2001 From: kinitrupti Date: Fri, 12 May 2017 18:53:46 +0530 Subject: Removed duplicates --- .../Chapter2.ipynb | 333 --------------------- 1 file changed, 333 deletions(-) delete mode 100755 backup/Mass_-_Transfer_Operations_version_backup/Chapter2.ipynb (limited to 'backup/Mass_-_Transfer_Operations_version_backup/Chapter2.ipynb') diff --git a/backup/Mass_-_Transfer_Operations_version_backup/Chapter2.ipynb b/backup/Mass_-_Transfer_Operations_version_backup/Chapter2.ipynb deleted file mode 100755 index 3d3cab36..00000000 --- a/backup/Mass_-_Transfer_Operations_version_backup/Chapter2.ipynb +++ /dev/null @@ -1,333 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:c59a45d9559284ebbfa4c56e2ad9c90a674f6e02433515bc489ee0db922e92e9" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 2:Molecular Diffusion In Fluids" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex2.1: Pg-30" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# Illustration 2.1\n", - "\n", - "# solution\n", - "import math\n", - "\n", - "#***Data***#\n", - "# a = O2 & b = CO\n", - "Dab = 1.87*10**(-5);#[square m/s]\n", - "Pt = 10**5;#[N/square m]\n", - "z = 0.002;#[m]\n", - "R = 8314;#[Nm/kmol]\n", - "T = 273;#[K]\n", - "Pa1 = 13*10.0**(3);#[N/square m]\n", - "Pb1 = 10**(5)-13*10**(3);#[N/square m]\n", - "Pa2 = 6500;#[N/square m]\n", - "Pb2 = 10**(5)-6500.0;#[N/square m]\n", - "#********#\n", - "\n", - "# Calculation from Eqn. 2.30\n", - "Pbm = (Pb1-Pb2)/math.log(Pb1/Pb2);#[N/square m]\n", - "Na = Dab*Pt*(Pa1-Pa2)/(R*T*z*Pbm);#[kmol/square m.s]\n", - "print\" Rate of diffusion of oxygen is\",round(Na,7),\"kmol/square m.sec \"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Rate of diffusion of oxygen is 2.97e-05 kmol/square m.sec \n" - ] - } - ], - "prompt_number": 8 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex2.2:Pg-30" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# Illustration2.2\n", - "\n", - "# solution\n", - "import math\n", - "\n", - "#***Data***#\n", - "Pt = 10**5.0;#[N/square m]\n", - "z = 0.002;#[m]\n", - "R = 8314.0;#[Nm/kmol]\n", - "T = 273;#[K]\n", - "#a = O2 b = CH4 c = H2\n", - "Pa1 = 13*10**(3);#[N/square m]\n", - "Pb1 = 10**(5)-13*10**(3);#[N/square m]\n", - "Pa2 = 6500.0;#[N/square m]\n", - "Pb2 = 10.0**(5)-6500;#[N/square m]\n", - "Dac = 6.99*10**(-5);#[N/square m]\n", - "Dab = 1.86*10.0**(-5);#[N/square m]\n", - "#*******#\n", - "\n", - "# Calculation from Eqn. 2.30\n", - "Pbm = (Pb1-Pb2)/math.log(Pb1/Pb2);#[N/square m]\n", - "Yb_prime = 2.0/(2+1);\n", - "Yc_prime = 1-Yb_prime;\n", - "Dam = 1.0/((Yb_prime/Dab)+(Yc_prime/Dac));#[square m.s]\n", - "Na = Dam*(Pa1-Pa2)*Pt/(R*T*z*Pbm);#[kmol/square m.s]\n", - "print \"Rate of diffusion is\",round(Na,7),\"kmol/square m.sec\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Rate of diffusion is 3.91e-05 kmol/square m.sec\n" - ] - } - ], - "prompt_number": 12 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex2.3:Pg-32" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# Illustration2.3\n", - "\n", - "import math\n", - "\n", - "# solution\n", - "\n", - "#***Data***#\n", - "# a = C2H5OH b = air\n", - "Pt = 101.3*10**(3);#[N/square m]\n", - "T = 273.0 ;#[K]\n", - "#********#\n", - "\n", - "Ma = 46.07;# [kg/kmol]\n", - "Mb = 29.0;# [kg/kmol]\n", - "#For air from Table 2.2 (Pg 33)\n", - "Eb_by_k = 78.6;# [K]\n", - "rb = 0.3711; # [nm]\n", - "# For C2H5OH using Eqn. 2.38 & 2.39\n", - "# From Table 2.3\n", - "Va = (2*0.0148)+(6*0.0037)+(0.0074);# [cubic m/kmol]\n", - "Tba = 351.4;# [K]\n", - "ra = 1.18*(Va**(1/3.0));#[nm]\n", - "Ea_by_k = 1.21*Tba;# [K]\n", - "rab = (ra+rb)/2.0;# [nm]\n", - "Eab_by_k = math.sqrt(Ea_by_k*Eb_by_k);# [K]\n", - "Collision_value = T/Eab_by_k;\n", - "#From Fig. 2.5 (Page: 32) f(collision value)\n", - "Collision_func = 0.595;\n", - "Dab = (10**(-4)*(1.084-(0.249*math.sqrt((1/Ma)+(1/Mb))))*T**(3.0/2)*math.sqrt((1/Ma)+(1/Mb)))/(Pt*(rab**2)*Collision_func);#[square m/s]\n", - "print\" The diffusivity of ethanol through air at 1 atm. & 0 degree C is\",round(Dab,7),\"m^2/s\"\n", - "print\" The observed value from (Table 2.1) is 1.02*10^(-5) square m/s'\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " The diffusivity of ethanol through air at 1 atm. & 0 degree C is 1.05e-05 m^2/s\n", - " The observed value from (Table 2.1) is 1.02*10^(-5) square m/s'\n" - ] - } - ], - "prompt_number": 28 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex2.4:Pg-34" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# Illustration 2.4\n", - "import math\n", - "\n", - "# solution\n", - "\n", - "#***Data****#\n", - "# a = acetic acid b = H2O\n", - "z = 0.001;# [m]\n", - "Dab = 0.95*10**(-9);#[square m/s]\n", - "#************#\n", - "\n", - "Ma = 60.03;# [kg/kmol]\n", - "Mb = 18.02;# [kg/kmol]\n", - "#At 17 C & 9% solution\n", - "density1 = 1012; #[kg/cubic m]\n", - "Xa1 = (0.09/Ma)/((0.09/Ma)+(0.91/Mb));\n", - "Xb1 = 1-Xa1;\n", - "M1 = 1/((0.09/Ma)+(0.91/Mb));# [kg/kmol]\n", - "#At 17 C & 3% solution\n", - "density2 = 1003.2; #[kg/cubic m]\n", - "Xa2 = (0.03/Ma)/((0.03/Ma)+(0.97/Mb));\n", - "Xb2 = 1-Xa2;\n", - "M2 = 1/((0.03/Ma)+(0.97/Mb));# [kg/kmol]\n", - "avg_density_by_M = ((density1/M1)+(density2/M2))/2;#[kmol/cubic m]\n", - "# From Eqn. 2.42\n", - "Xbm = (Xb2-Xb1)/math.log(Xb2/Xb1);\n", - "# From Eqn. 2.41\n", - "Na = Dab*(avg_density_by_M)*(Xa1-Xa2)/(Xbm*z); #[square m/s]\n", - "print\" The rate of diffusion is\",round(Na,9),\"square m/s\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " The rate of diffusion is 1.018e-06 square m/s\n" - ] - } - ], - "prompt_number": 31 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex2.5:Pg-37" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# Illustration 2.5\n", - "\n", - "\n", - "# solution\n", - "\n", - "#***Data****#\n", - "# a = mannitol b = H2O\n", - "T = 293; # [K]\n", - "#*****#\n", - "\n", - "Mb = 18.02;# [kg/kmol]\n", - "# From Table 2.3 (Pg 33)\n", - "Va = (0.0148*6)+(0.0037*14)+(0.0074*6); # [cubic m/kmol]\n", - "viscosity = 0.001005; # [kg/m.s]\n", - "association_factor = 2.26; # [water as a solvent]\n", - "Dab = (117.3*10**(-18))*((association_factor*Mb)**0.5)*T/(viscosity*Va**0.6); # [square m/s]\n", - "print\" Diffusivity of mannitol is\",round(Dab,12),\"square m/s\"\n", - "print\" Observed value is 0.56*10^(-9) square m/s\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Diffusivity of mannitol is 6.01e-10 square m/s\n", - " Observed value is 0.56*10^(-9) square m/s\n" - ] - } - ], - "prompt_number": 48 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex2.6:Pg-37" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "\n", - "# Illustration 2.6\n", - "\n", - "\n", - "# solution\n", - "\n", - "#****Data****#\n", - "T2 = 70+273;# [K]\n", - "#**********#\n", - "\n", - "# a = mannitol b = H2O\n", - "# From Illustration 2.5 at 20 C\n", - "viscosity1 = 1.005*10**(-3); # [kg/m.s]\n", - "Dab1 = 0.56*10**(-9); #[m^2/s]\n", - "T1 = 273+20;# [K]\n", - "# At 70 C\n", - "viscosity2 = 0.4061*10**(-3); # kg/m.s\n", - "# Eqn. 2.44 indicates Dab*viscocity/T = constnt\n", - "Dab2 = Dab1*(T2)*(viscosity1)/(T1*viscosity2);# [square m/s]\n", - "print\" Diffusivity of mannitol at 70 degree C is\",round(Dab2,11),\"square/s \"\n", - "print\" Observed value at 70 degree C is 1.56*10^(-9) square m/s\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Diffusivity of mannitol at 70 degree C is 1.62e-09 square/s \n", - " Observed value at 70 degree C is 1.56*10^(-9) square m/s\n" - ] - } - ], - "prompt_number": 53 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit