From d36fc3b8f88cc3108ffff6151e376b619b9abb01 Mon Sep 17 00:00:00 2001 From: kinitrupti Date: Fri, 12 May 2017 18:40:35 +0530 Subject: Revised list of TBCs --- Thermodynamics_for_Engineers/Chapter_16_2.ipynb | 253 ------------------------ 1 file changed, 253 deletions(-) delete mode 100755 Thermodynamics_for_Engineers/Chapter_16_2.ipynb (limited to 'Thermodynamics_for_Engineers/Chapter_16_2.ipynb') diff --git a/Thermodynamics_for_Engineers/Chapter_16_2.ipynb b/Thermodynamics_for_Engineers/Chapter_16_2.ipynb deleted file mode 100755 index efa01670..00000000 --- a/Thermodynamics_for_Engineers/Chapter_16_2.ipynb +++ /dev/null @@ -1,253 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:dc464f4ef08695f8cec0668d0c21cb89b005d8581737f852d592d0e688b3aa48" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 16 - Gas cycles" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 1 - Pg 330" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the max. pressure, temperature and thermal efficiency\n", - "#Initalization of variables\n", - "import math\n", - "cr=9.\n", - "p1=14. #psia\n", - "t1=80.+460 #R\n", - "n=1.4\n", - "heat=800. #Btu\n", - "c=0.1715\n", - "R=53.35\n", - "J=778.\n", - "#calculations\n", - "p2=p1*math.pow(cr,n)\n", - "t2=t1*math.pow(cr,(n-1))\n", - "t3=heat/c +t2\n", - "p3=p2*t3/t2\n", - "eff=(1-1/math.pow(cr,(n-1)))*100\n", - "t4=t3/math.pow(cr,(n-1))\n", - "Qr=c*(t4-t1)\n", - "cyclework=heat-Qr\n", - "eff2= cyclework/heat *100\n", - "V1=R*t1/(144*p1)\n", - "pd=(1-1/cr)*V1\n", - "mep=cyclework*J/(pd*144)\n", - "#results\n", - "print '%s %d %s' %(\"Max. temperature =\",t3,\"R\")\n", - "print '%s %d %s' %(\"\\n Max. pressure =\",p3,\"psia\")\n", - "print '%s %.1f %s' %(\"\\n In method 1,Thermal efficiency =\",eff,\" percent\")\n", - "print '%s %.1f %s' %(\"\\n In method 2,Thermal efficiency =\",eff2,\" percent\")\n", - "print '%s %.1f %s' %(\"\\n Mean effective pressure mep =\",mep,\" psia\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Max. temperature = 5965 R\n", - "\n", - " Max. pressure = 1391 psia\n", - "\n", - " In method 1,Thermal efficiency = 58.5 percent\n", - "\n", - " In method 2,Thermal efficiency = 58.5 percent\n", - "\n", - " Mean effective pressure mep = 199.0 psia\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2 - Pg 333" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the max temperature, pressure and thermal efficiency\n", - "#Initalization of variables\n", - "import math\n", - "t1=80+460. #R\n", - "p1=14. #psia\n", - "n=1.4\n", - "cr=16.\n", - "heat=800. #Btu\n", - "cp=0.24\n", - "c=0.1715\n", - "#calculations\n", - "t2=t1*math.pow(cr,(n-1))\n", - "p2=p1*math.pow(cr,n)\n", - "t3=t2 +heat/cp\n", - "v32=t3/t2\n", - "v43=cr/v32\n", - "t4=t3/math.pow(v43,(n-1))\n", - "Qr=c*(t4-t1)\n", - "etat=(heat-Qr)/heat *100\n", - "#results\n", - "print '%s %d %s' %(\"Max. Temperature =\",t3,\" R\")\n", - "print '%s %d %s' %(\"\\n Max. Pressure =\",p2,\"psia\")\n", - "print '%s %.1f %s' %(\"\\n Thermal efficiency =\",etat,\" percent\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Max. Temperature = 4970 R\n", - "\n", - " Max. Pressure = 679 psia\n", - "\n", - " Thermal efficiency = 56.8 percent\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 3 - Pg 335" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the Mean effective pressure\n", - "#Initalization of variables\n", - "eff=0.585\n", - "heat=800. #Btu\n", - "t1=80+460. #R\n", - "p1=14. #psia\n", - "n=1.4\n", - "R=53.35\n", - "cr=9.\n", - "cp=0.24\n", - "J=778.\n", - "#calculations\n", - "W=eff*heat\n", - "v1=R*t1/(144*p1)\n", - "v2=v1/cr\n", - "t2=1301 #R\n", - "t3=t2+ heat/cp\n", - "v3=v2*t3/t2\n", - "v4=cr*v3\n", - "mep=W*J/(144*(v4-v2))\n", - "#results\n", - "print '%s %.1f %s' %(\"Mean effective pressure =\",mep,\" psia\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Mean effective pressure = 51.3 psia\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4 - Pg 340" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the max temperature, pressure, thermal efficiency, mean effective pressure\n", - "#Initalization of variables\n", - "import math\n", - "eff=0.585\n", - "heat=500. #Btu\n", - "heat1=300. #Btu\n", - "t1=80+460. #R\n", - "p1=14. #psia\n", - "n=1.4\n", - "R=53.35\n", - "cr=9.\n", - "J=778.\n", - "c=0.1715\n", - "cp=0.24\n", - "t2=1301. #R\n", - "p2=308. #psia\n", - "#calculations\n", - "t3=t2+ heat/c\n", - "p3=p2*t3/t2\n", - "t4=t3+ heat1/cp\n", - "v43=t4/t3\n", - "v54=cr/v43\n", - "t5=t4/math.pow(v54,(n-1))\n", - "Qr=c*(t5-t1)\n", - "etat=(heat+heat1-Qr)/(heat+heat1) *100\n", - "mep=(heat+heat1-Qr)*J/(12.69*144)\n", - "#results\n", - "print '%s %d %s' %(\"Max. Temperature =\",t4,\" R\")\n", - "print '%s %d %s' %(\"\\n Max. Pressure =\",p3,\"psia\")\n", - "print '%s %.1f %s' %(\"\\n Thermal efficiency =\",etat,\"percent\")\n", - "print '%s %.1f %s' %(\"\\n Mean effective pressure =\",mep,\" psia\")\n", - "print '%s' %(\"The calculations are a bit different due to rounding off error in textbook\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Max. Temperature = 5466 R\n", - "\n", - " Max. Pressure = 998 psia\n", - "\n", - " Thermal efficiency = 57.6 percent\n", - "\n", - " Mean effective pressure = 196.2 psia\n", - "The calculations are a bit different due to rounding off error in textbook\n" - ] - } - ], - "prompt_number": 4 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit