From 92cca121f959c6616e3da431c1e2d23c4fa5e886 Mon Sep 17 00:00:00 2001
From: hardythe1
Date: Tue, 7 Apr 2015 15:58:05 +0530
Subject: added books

---
 Thermodynamics_for_Engineers/Chapter_15_2.ipynb | 158 ++++++++++++++++++++++++
 1 file changed, 158 insertions(+)
 create mode 100755 Thermodynamics_for_Engineers/Chapter_15_2.ipynb

(limited to 'Thermodynamics_for_Engineers/Chapter_15_2.ipynb')

diff --git a/Thermodynamics_for_Engineers/Chapter_15_2.ipynb b/Thermodynamics_for_Engineers/Chapter_15_2.ipynb
new file mode 100755
index 00000000..25cf3bae
--- /dev/null
+++ b/Thermodynamics_for_Engineers/Chapter_15_2.ipynb
@@ -0,0 +1,158 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:d798b16416897dedbfd57aff5c233c1f7e9c52a7f0081b45c972d6ab47468c7c"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 15 - Thermodynamics of chemical reactions"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 1 - Pg 318"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the amount of dissociation\n",
+      "#Initalization of variables\n",
+      "import math\n",
+      "import numpy\n",
+      "kp=math.pow(10,(1.45))\n",
+      "#calculations\n",
+      "s=[1-kp*kp , 0, -3, 2]\n",
+      "vec=numpy.roots(s)\n",
+      "X=numpy.real(vec[2])\n",
+      "xper=X*100\n",
+      "#results\n",
+      "print '%s %.1f %s' %(\"Amount of dissociaton =\",xper,\"percent\")\n",
+      "print '%s %.3f %s %.3f %s %.3f %s' %(\"\\n Of each original mole of CO2, there will be\",X,\"mole of CO \",X/2.,\" mol of Oxygen and\",(1-X),\"mol of CO2\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "Amount of dissociaton = 12.7 percent\n",
+        "\n",
+        " Of each original mole of CO2, there will be 0.127 mole of CO  0.063  mol of Oxygen and 0.873 mol of CO2\n"
+       ]
+      }
+     ],
+     "prompt_number": 1
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 2 - Pg 319"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the max. temperature reached\n",
+      "#Initalization of variables\n",
+      "U=121200. #Btu/mol\n",
+      "Uco2=51635. #Btu/mol\n",
+      "Un2=27589. #Btu/mol\n",
+      "Uco22=57875. #Btu/mol\n",
+      "Un22=21036. #Btu/mol\n",
+      "T1=5000. #R\n",
+      "T2=5500. #R\n",
+      "#calculations\n",
+      "Ut1=Uco2+1.88*Un2\n",
+      "Ut2=Uco22 + 1.88*Un22\n",
+      "print '%s' %(\"By extrapolation,\")\n",
+      "Tx=5710 #R\n",
+      "#results\n",
+      "print '%s %d %s' %(\"Max. Temperature reached =\",Tx,\"R\")\n",
+      "print '%s' %(\"The calculation for Ut2 is wrong in textbook. Please use a calculator.\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "By extrapolation,\n",
+        "Max. Temperature reached = 5710 R\n",
+        "The calculation for Ut2 is wrong in textbook. Please use a calculator.\n"
+       ]
+      }
+     ],
+     "prompt_number": 2
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Example 3 - Pg 319"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#calculate the max. obtainable temperature\n",
+      "#Initalization of variables\n",
+      "print '%s' %(\"By trial and error,\")\n",
+      "import math\n",
+      "X=0.201\n",
+      "X1=0.2\n",
+      "R=59.3 #universal gas constant\n",
+      "T=5000 #R\n",
+      "U=121200 #Btu/mol\n",
+      "Uco2=51635. #Btu/mol\n",
+      "Un2=27907. #Btu/mol\n",
+      "U3=29616. #Btu/mol\n",
+      "U4=27589. #Btu/mol\n",
+      "#calculations\n",
+      "kp1=R*(1-X1)/math.pow(X1,1.5) /math.pow(T,0.5)\n",
+      "kp2=R*(1-X)/math.pow(X,1.5) /math.pow(T,0.5)\n",
+      "q=(1-X)*Uco2 + X*Un2+ X/2 *U3 +1.88*U4 + X*U\n",
+      "print '%s' %(\"Interpolating between T=4500 R and T=5000 R, we get\")\n",
+      "T2=4907 #R\n",
+      "#results\n",
+      "print '%s %d %s' %(\"Max. obtainable temperature =\",T2,\" R\")\n"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        "By trial and error,\n",
+        "Interpolating between T=4500 R and T=5000 R, we get\n",
+        "Max. obtainable temperature = 4907  R\n"
+       ]
+      }
+     ],
+     "prompt_number": 3
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file
-- 
cgit