From 41f1f72e9502f5c3de6ca16b303803dfcf1df594 Mon Sep 17 00:00:00 2001
From: Thomas Stephen Lee
Date: Fri, 4 Sep 2015 22:04:10 +0530
Subject: add/remove/update books

---
 Thermodynamics_Demystified/Chapter1.ipynb | 209 ------------------------------
 1 file changed, 209 deletions(-)
 delete mode 100755 Thermodynamics_Demystified/Chapter1.ipynb

(limited to 'Thermodynamics_Demystified/Chapter1.ipynb')

diff --git a/Thermodynamics_Demystified/Chapter1.ipynb b/Thermodynamics_Demystified/Chapter1.ipynb
deleted file mode 100755
index 68c66861..00000000
--- a/Thermodynamics_Demystified/Chapter1.ipynb
+++ /dev/null
@@ -1,209 +0,0 @@
-{
- "metadata": {
-  "name": "",
-  "signature": "sha256:2622b864e241f67942d9af83d84aabbbf519132ac138f1180d8869df35c708b4"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
-  {
-   "cells": [
-    {
-     "cell_type": "heading",
-     "level": 1,
-     "metadata": {},
-     "source": [
-      "CHAPTER 1 : Basic Principles"
-     ]
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1.2 : PG-9 "
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "# initialization of variables\n",
-      "m=10 # mass in Kg\n",
-      "V=5 # velocity in m/s\n",
-      "\n",
-      "KE=m*V**2/2 # kinetic energy in N-m \n",
-      "print \"The Kinetic Energy is \",round(KE),\" N.m\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "The Kinetic Energy is  125.0  N.m\n"
-       ]
-      }
-     ],
-     "prompt_number": 77
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1.3 : PG-10"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "# initialization of variables\n",
-      "V= 3*5*20; # Volume of air in m^3 from dimensions\n",
-      "m= 350.0; # mass in kg\n",
-      "g= 9.81; # gavitational acceleration in m/s^2\n",
-      "\n",
-      "rho=m/V;# density\n",
-      "print \" The Density is \",round(rho,3),\"kg/m^3 \\n\"\n",
-      "\n",
-      "v= 1/rho # specific volume of air\n",
-      "print \" The specific volume  is\", round(v,3),\"m^3/kg \\n\"\n",
-      "\n",
-      "gama= rho*g # specific weight of air\n",
-      "print \" The specific weight is\", round(gama,2),\" N/m^3\"\n",
-      "\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        " The Density is  1.167 kg/m^3 \n",
-        "\n",
-        " The specific volume  is 0.857 m^3/kg \n",
-        "\n",
-        " The specific weight is 11.45  N/m^3\n"
-       ]
-      }
-     ],
-     "prompt_number": 78
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1.4 : PG-13"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "# initialization of variables\n",
-      "h=0.020 # height of mercury in m\n",
-      "gammawater=9810 # specific weight of water in N/m^3\n",
-      "Patm=0.7846*101.3 # atmospheric pressure in kPa from table B.1\n",
-      "\n",
-      "Pgauge=13.6*gammawater*h/1000 # pressure in Pascal from condition gammaHg=13.6*gammawater\n",
-      "\n",
-      "P=(Pgauge+Patm)# absolute pressure in KPa\n",
-      "#result\n",
-      "print \"The Pressure is\",round(P,2),\" kPa\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "The Pressure is 82.15  kPa\n"
-       ]
-      }
-     ],
-     "prompt_number": 79
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1.5 : PG-13"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "import math\n",
-      "# initialization of variables\n",
-      "d=10.0/100 # diameter of cylinder in 'm'\n",
-      "P=600 # pressure in KPa\n",
-      "Patm=100 # atmospheric pressure in Kpa\n",
-      "K=4.8*1000 # spring constant in N/m \n",
-      "\n",
-      "deltax=(P-Patm)*(math.pi*1000*d**2)/(4*K) # by balancing forces on piston\n",
-      "#result\n",
-      "print \"The Compression in spring is\",round(deltax,3),\" m\""
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "The Compression in spring is 0.818  m\n"
-       ]
-      }
-     ],
-     "prompt_number": 80
-    },
-    {
-     "cell_type": "heading",
-     "level": 2,
-     "metadata": {},
-     "source": [
-      "Ex1.6 : PG-16"
-     ]
-    },
-    {
-     "cell_type": "code",
-     "collapsed": false,
-     "input": [
-      "# initialization of variables\n",
-      "ma=2200 # mass of Automobile 'a' in kg\n",
-      "va=25 #velocity of Automobile 'a' in m/s before collision\n",
-      "va1=13.89 # velocity of Automobile 'a' after collision in m/s\n",
-      "mb=1000 # mass of Automobile 'b' in kg\n",
-      "vb=24.44 #velocity of Automobile 'b' after collision in m/s\n",
-      "\n",
-      "KE1=(ma*va**2)/2 # kinetic energy before collision\n",
-      "KE2=(ma*va1**2)/2+(mb*vb**2)/2 # kinetic energy after collision\n",
-      "U=(KE1-KE2)/1000 # internal energy from conservation of energy principle in kJ\n",
-      "#result\n",
-      "print \"The increase in kinetic energy is of\",round(U,1),\" kJ\"\n"
-     ],
-     "language": "python",
-     "metadata": {},
-     "outputs": [
-      {
-       "output_type": "stream",
-       "stream": "stdout",
-       "text": [
-        "The increase in kinetic energy is of 176.6  kJ\n"
-       ]
-      }
-     ],
-     "prompt_number": 81
-    }
-   ],
-   "metadata": {}
-  }
- ]
-}
\ No newline at end of file
-- 
cgit