From fba055ce5aa0955e22bac2413c33493b10ae6532 Mon Sep 17 00:00:00 2001
From: hardythe1
Date: Tue, 5 May 2015 14:21:39 +0530
Subject: add books

---
 .../Chapter_4__2.ipynb                             | 228 +++++++++++----------
 1 file changed, 125 insertions(+), 103 deletions(-)

(limited to 'Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb')

diff --git a/Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb b/Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb
index af2345df..087b31cb 100755
--- a/Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb
+++ b/Thermodynamics:_From_concepts_to_applications/Chapter_4__2.ipynb
@@ -1,7 +1,7 @@
 {
  "metadata": {
   "name": "",
-  "signature": "sha256:0cf657809abd59a3a86b6df0687d80933981fc0951ab754e85709aa636b8b749"
+  "signature": "sha256:1f455d345757b912d780f8c505ce37e354978864332af7e0ecea71365b71aa92"
  },
  "nbformat": 3,
  "nbformat_minor": 0,
@@ -10,10 +10,10 @@
    "cells": [
     {
      "cell_type": "heading",
-     "level": 2,
+     "level": 1,
      "metadata": {},
      "source": [
-      "Chapter 4-simple systems"
+      "Chapter4-Simple systems"
      ]
     },
     {
@@ -21,7 +21,7 @@
      "level": 2,
      "metadata": {},
      "source": [
-      "Example1-46"
+      "Ex1-pg51"
      ]
     },
     {
@@ -29,6 +29,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
+      "#calculte pressure and mass and specific volume of water vapour\n",
       "##initialisation of variables\n",
       "V= 0.5 ##m**3\n",
       "M= 18.02 ##kg/kmol\n",
@@ -46,7 +47,7 @@
       "##RESULTS\n",
       "print'%s %.2f %s'% ('mass of water vapour =',m,' kg')\n",
       "print'%s %.2f %s' %(' specific volume of water vapour = ',v,' m**3/kg')\n",
-      "print'%s %.2f %s' %(' pressure of water vapour =',p-10,'kPa')\n",
+      "print'%s %.2f %s' %(' pressure of water vapour =',p,'kPa')\n",
       "print'%s %.2f %s' %(' pressure of water vapour = ',P-12,' kPa')\n",
       "print'%s %.2f %s' %(' pressure of water vapour =',P1,' kPa')\n"
      ],
@@ -59,20 +60,20 @@
        "text": [
         "mass of water vapour = 27.03  kg\n",
         " specific volume of water vapour =  0.02  m**3/kg\n",
-        " pressure of water vapour = 15543.51 kPa\n",
+        " pressure of water vapour = 15553.51 kPa\n",
         " pressure of water vapour =  12131.31  kPa\n",
         " pressure of water vapour = 12432.21  kPa\n"
        ]
       }
      ],
-     "prompt_number": 3
+     "prompt_number": 14
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Ex2-pg50"
+      "Ex2-pg52"
      ]
     },
     {
@@ -80,6 +81,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
+      "#calculate heat interaction\n",
       "##initialisation of variables\n",
       "m= 0.3 ##kg\n",
       "T= 25 ##C\n",
@@ -101,14 +103,14 @@
        ]
       }
      ],
-     "prompt_number": 4
+     "prompt_number": 15
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example3-pg53"
+      "Ex3-pg53"
      ]
     },
     {
@@ -116,22 +118,22 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#caluclate the heat interaction and temperature rise\n",
+      "#calculate heat interaction and temperature rise\n",
       "##initialisation of variables\n",
-      "m= 5000. ##kg\n",
+      "m= 5000 ##kg\n",
       "cp= 1.4 ##kJ/kg K\n",
       "T2= 27.6 ##K\n",
-      "T1= 22. ##K\n",
-      "t= 40. ##min\n",
-      "P= 20. ##kW\n",
+      "T1= 22 ##K\n",
+      "t= 40 ##min\n",
+      "P= 20 ##kW\n",
       "##CALCULATIONS\n",
       "H= m*cp*(T2-T1)\n",
       "W= -P*t*60\n",
       "Q= H+W\n",
       "dT= -W/(m*cp)\n",
       "##RESULTS\n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ')\n",
-      "print'%s %.2f %s'%('Temperature rise = ',dT,'C')\n"
+      "print'%s %.2f %s'% ('heat interaction = ',Q,' kJ')\n",
+      "print'%s %.2f %s'% ('\\n temperature rise = ',dT,' C')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -140,19 +142,20 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "heat interaction = -8800 kJ\n",
-        "Temperature rise =  6.86 C\n"
+        "heat interaction =  -8800.00  kJ\n",
+        "\n",
+        " temperature rise =  6.86  C\n"
        ]
       }
      ],
-     "prompt_number": 15
+     "prompt_number": 16
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "example 4-pg 59\n"
+      "Ex4-pg59"
      ]
     },
     {
@@ -160,12 +163,12 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#caluclate the volumes and internal energy and enthaply\n",
       "##initialisation of variables\n",
+      "#calculate volume and internal energy and enthalpy\n",
       "T= 300. ##C\n",
       "p= 2. ##Mpa\n",
       "T1= 300. ##C\n",
-      "p1= 20.##Mpa\n",
+      "p1= 20. ##Mpa\n",
       "T2= 300. ##C\n",
       "p2= 8.501 ##Mpa\n",
       "##CALCULATIONS\n",
@@ -176,12 +179,12 @@
       "h= 3023.5\n",
       "h1= 1333.3\n",
       "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.5f %s'%('volume =',v1,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy = ',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u1,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h,'kJ/kg')\n",
-      "print'%s %.f %s'%('enthalpy = ',h1,'kJ/kg')\n"
+      "print'%s %.2f %s'% ('volume = ',v,' m^3/kg')\n",
+      "print'%s %.2f %s'% ('\\n volume =',v1,' m^3/kg')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',u,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',u1,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n enthalpy = ',h,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n enthalpy = ',h1,' kJ/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -190,12 +193,17 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "volume = 0.12547 m^3/kg\n",
-        "volume = 0.00136 m^3/kg\n",
-        "internal energy =  2772.6 kJ/kg\n",
-        "internal energy = 1306.1 kJ/kg\n",
-        "enthalpy = 3023.5 kJ/kg\n",
-        "enthalpy =  1333 kJ/kg\n"
+        "volume =  0.13  m^3/kg\n",
+        "\n",
+        " volume = 0.00  m^3/kg\n",
+        "\n",
+        " internal energy =  2772.60  kJ/kg\n",
+        "\n",
+        " internal energy =  1306.10  kJ/kg\n",
+        "\n",
+        " enthalpy =  3023.50  kJ/kg\n",
+        "\n",
+        " enthalpy =  1333.30  kJ/kg\n"
        ]
       }
      ],
@@ -206,7 +214,7 @@
      "level": 2,
      "metadata": {},
      "source": [
-      "example5-pg60\n"
+      "Ex5-pg60"
      ]
     },
     {
@@ -214,7 +222,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#calculate the volume and internal energy and enthalpy\n",
+      "#calculate volume and internal energy\n",
       "##initialisation of variables\n",
       "vf= 0.001404 ##m^3/kg\n",
       "x= 0.8\n",
@@ -228,9 +236,9 @@
       "u= uf+x*ug\n",
       "h= hf+x*hg\n",
       "##RESULTS\n",
-      "print'%s %.5f %s'%('volume =',v,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',h, 'kJ/kg')\n"
+      "print'%s %.2f %s'% ('volume = ',v,' m^3/kg')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',u,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n enthalpy = ',h,' kJ/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -239,20 +247,22 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "volume = 0.01762 m^3/kg\n",
-        "internal energy = 2316.8 kJ/kg\n",
-        "enthalpy = 2467.9 kJ/kg\n"
+        "volume =  0.02  m^3/kg\n",
+        "\n",
+        " internal energy =  2316.80  kJ/kg\n",
+        "\n",
+        " enthalpy =  2467.92  kJ/kg\n"
        ]
       }
      ],
-     "prompt_number": 5
+     "prompt_number": 18
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example6-pg 61"
+      "Ex6-pg61"
      ]
     },
     {
@@ -260,7 +270,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#calculate the specific volume and internal energy and enthalpy and entropy\n",
+      "#calculate specific volume and internal energy and enthalpy and entropy\n",
       "##initialisation of variables\n",
       "T= 296. ##K\n",
       "T1= 250. ##K\n",
@@ -275,17 +285,17 @@
       "s2= 6.5433 ##kJ/kg K\n",
       "##CALCULATIONS\n",
       "a1= (T-T1)/(T2-T1)\n",
-      "a2= 1-a1\n",
+      "a2= 1.-a1\n",
       "V= a1*v+a2*v1\n",
       "U= a1*u1+a2*u2\n",
       "H= a1*h1+a2*h2\n",
       "S= a1*s1+a2*s2\n",
       "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 = ',a2,'')\n",
-      "print'%s %.5f %s'%('specific volume =',V,'m^3/kg')\n",
-      "print'%s %.1f %s'%('internal energy =',U,'kJ/kg')\n",
-      "print'%s %.1f %s'%('enthalpy =',H,'kJ/kg')\n",
-      "print'%s %.1f %s'%('Entropy =',S,'kJ/kg')\n"
+      "print'%s %.2f %s'% ('a2 =  ',a2,'')\n",
+      "print'%s %.2f %s'% ('\\n specific volume = ',V,' m^3/kg')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',U,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n enthalpy = ',H,' kJ/kg')\n",
+      "print'%s %.2f %s'% ('\\n Entropy = ',S,' kJ/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -294,22 +304,26 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "a2 =  0.080 \n",
-        "specific volume = 0.12456 m^3/kg\n",
-        "internal energy = 25765.2 kJ/kg\n",
-        "enthalpy = 3013.8 kJ/kg\n",
-        "Entropy = 6.7 kJ/kg\n"
+        "a2 =   0.08 \n",
+        "\n",
+        " specific volume =  0.12  m^3/kg\n",
+        "\n",
+        " internal energy =  25765.16  kJ/kg\n",
+        "\n",
+        " enthalpy =  3013.82  kJ/kg\n",
+        "\n",
+        " Entropy =  6.75  kJ/kg\n"
        ]
       }
      ],
-     "prompt_number": 6
+     "prompt_number": 19
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Exapmle7-pg62"
+      "Ex7-pg62"
      ]
     },
     {
@@ -317,7 +331,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#calculate a2 and internal enerjy\n",
+      "#calculate a2 and internal energy\n",
       "##initialisation of variables\n",
       "v= 0.15 ##m^3/kg\n",
       "v1= 0.13857 ##m^3/kg\n",
@@ -333,8 +347,8 @@
       "x= (v3-vf)/(vg-vf)\n",
       "u= uf+x*ufg\n",
       "##RESULTS\n",
-      "print'%s %.3f %s'%('a2 =',a2,'')\n",
-      "print'%s %.1f %s'%('internal energy =',u,'kJ/kg')\n"
+      "print'%s %.2f %s'% ('a2 =  ',a2,'')\n",
+      "print'%s %.2f %s'% ('\\n internal energy = ',u,' kJ/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -343,19 +357,20 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "a2 = 0.095 \n",
-        "internal energy = 1746.4 kJ/kg\n"
+        "a2 =   0.10 \n",
+        "\n",
+        " internal energy =  1746.40  kJ/kg\n"
        ]
       }
      ],
-     "prompt_number": 7
+     "prompt_number": 20
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example8-pg63"
+      "Ex8-pg63"
      ]
     },
     {
@@ -365,8 +380,8 @@
       "import math\n",
       "#calculate pressure and temperature\n",
       "##initialisation of variables\n",
-      "T= 250.##C\n",
-      "T1= 300. ##C\n",
+      "T= 250. ##C\n",
+      "T2= 300. ##C\n",
       "v300= 0.6548 ##m^3/kg\n",
       "v250= 0.591 ##m^3/kg\n",
       "v= 0.6 ##m^3/kg\n",
@@ -378,13 +393,13 @@
       "p= 0.4 ##Mpa\n",
       "p2= 0.2 ##Mpa\n",
       "##CALCULATIONS\n",
-      "T1= T1+((v-v250)/(v300-v250))*(T2-T)\n",
+      "T1= T+((v-v250)/(v300-v250))*(T2-T)\n",
       "u1= u250+((v-v250)/(v300-v250))*(u300-u250)\n",
       "du= u1-u\n",
       "p1= p+((u-u1)/(u2-u1))*p2\n",
       "##RESULTS\n",
-      "print'%s %.3f %s'%('pressure =',p1,'Mpa')\n",
-      "print'%s %.f %s'%('temperature =',T2,'C')\n"
+      "print'%s %.2f %s'% ('pressure = ',p1,' Mpa')\n",
+      "print'%s %.2f %s'% ('\\n temperature = ',T2,' C')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -393,36 +408,38 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "pressure = 0.529 Mpa\n",
-        "temperature = 510 C\n"
+        "pressure =  0.53  Mpa\n",
+        "\n",
+        " temperature =  510.30  C\n"
        ]
       }
      ],
-     "prompt_number": 8
+     "prompt_number": 21
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Ex10-pg64"
+      "Ex9-pg64"
      ]
     },
     {
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "\n",
+      "import math\n",
+      "#calculate mass and specific volume\n",
       "##initialisation of variables\n",
       "n= 1.5 ##kmol\n",
-      "V= 0.5 ##m**3\n",
+      "V= 0.5 ##m^3\n",
       "M= 18.02 ##kg\n",
       "##CALCULATIONS\n",
       "m= n*M\n",
       "v= V/m\n",
       "##RESULTS\n",
       "print'%s %.2f %s'% ('mass = ',m,' kg')\n",
-      "print'%s %.2f %s'% (' sepcific volume = ',v,' m^3/kg')\n"
+      "print'%s %.2f %s'% ('\\n sepcific volume = ',v,' m^3/kg')\n"
      ],
      "language": "python",
      "metadata": {},
@@ -432,18 +449,19 @@
        "stream": "stdout",
        "text": [
         "mass =  27.03  kg\n",
+        "\n",
         " sepcific volume =  0.02  m^3/kg\n"
        ]
       }
      ],
-     "prompt_number": 5
+     "prompt_number": 22
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example 12-pg66"
+      "Ex12-pg66"
      ]
     },
     {
@@ -459,18 +477,18 @@
       "u1= 2747.7 ##kJ/kg\n",
       "h2= 3092.5 ##kJ/kg\n",
       "h1= 2987.3 ##kJ/kg\n",
-      "p= 4 ##Mpa\n",
+      "p= 4. ##Mpa\n",
       "v2= 0.06645 ##m^3/kg\n",
       "v1= 0.02995 ##m^3/kg\n",
       "##CALCULATIONS\n",
       "m= V/v1\n",
       "U= m*(u2-u1)\n",
       "H= m*(h2-h1)\n",
-      "W= m*p*10*10*10*(v2-v1)\n",
+      "W= m*p*10**3*(v2-v1)\n",
       "Q= U+W\n",
       "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.1f %s'%('heat interaction =',Q,'kJ')\n"
+      "print'%s %.2f %s'% (' work = ',W,' kJ') \n",
+      "print'%s %.2f %s'% ('\\n heat interaction = ',Q,' kJ') \n"
      ],
      "language": "python",
      "metadata": {},
@@ -479,19 +497,20 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "work = 975.0 kJ\n",
-        "heat interaction = 1502.5 kJ\n"
+        " work =  974.96  kJ\n",
+        "\n",
+        " heat interaction =  1502.50  kJ\n"
        ]
       }
      ],
-     "prompt_number": 10
+     "prompt_number": 23
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example13-pg 67"
+      "Ex13-pg67"
      ]
     },
     {
@@ -519,8 +538,8 @@
       "W= m*0.5*((p1+p2)*(v2-v1)+(p2+p3)*(v3-v2)+(p3+p4)*(v4-v3)+(p4+p5)*(v5-v4))\n",
       "Q=U+W\n",
       "##RESULTS\n",
-      "print'%s %.1f %s'%('work =',W,'kJ') \n",
-      "print'%s %.f %s'%('heat interaction =',Q,'kJ') \n"
+      "print'%s %.2f %s'% (' work = ',W,' kJ') \n",
+      "print'%s %.2f %s'% ('\\n heat interaction = ',Q,' kJ') \n"
      ],
      "language": "python",
      "metadata": {},
@@ -529,19 +548,20 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "work = 1361.0 kJ\n",
-        "heat interaction = 1889 kJ\n"
+        " work =  1361.04  kJ\n",
+        "\n",
+        " heat interaction =  1888.61  kJ\n"
        ]
       }
      ],
-     "prompt_number": 12
+     "prompt_number": 24
     },
     {
      "cell_type": "heading",
      "level": 2,
      "metadata": {},
      "source": [
-      "Example 14-pg68\n"
+      "Ex14-pg68"
      ]
     },
     {
@@ -549,7 +569,7 @@
      "collapsed": false,
      "input": [
       "import math\n",
-      "#calculate final pressure and enthalpy and etropy\n",
+      "#calculate final pressure and enthalpy and piston rise\n",
       "##initialisation of variables\n",
       "p0= 100. ##kpa\n",
       "A= 0.1 ##m^2\n",
@@ -561,13 +581,13 @@
       "u2= 2728.7 ##kJ/kg\n",
       "v3= 0.9942 ##m^3/kg\n",
       "##CALCULATIONS\n",
-      "pe= (p0+(F/A))/1000\n",
+      "pe= (p0+(F/A))/1000.\n",
       "h3= (m1*u1-m2*u2)/m3\n",
       "z3= m3*v3/A\n",
       "##RESULTS\n",
-      "print'%s %.1f %s'%('final pressure =',pe,'Mpa') \n",
-      "print'%s %.1f %s'%('enthalpy = ',h3,'kJ/kg') \n",
-      "print'%s %.2f %s'%('piston rise =',z3,'m') \n"
+      "print'%s %.2f %s'% (' final pressure = ',pe,' Mpa') \n",
+      "print'%s %.2f %s'% (' \\n enthalpy = ',h3,' kJ/kg') \n",
+      "print'%s %.2f %s'% ('\\n piston rise = ',z3,' m') \n"
      ],
      "language": "python",
      "metadata": {},
@@ -576,13 +596,15 @@
        "output_type": "stream",
        "stream": "stdout",
        "text": [
-        "final pressure = 0.3 Mpa\n",
-        "enthalpy =  3225.9 kJ/kg\n",
-        "piston rise = 8.82 m\n"
+        " final pressure =  0.30  Mpa\n",
+        " \n",
+        " enthalpy =  3225.86  kJ/kg\n",
+        "\n",
+        " piston rise =  8.82  m\n"
        ]
       }
      ],
-     "prompt_number": 14
+     "prompt_number": 25
     }
    ],
    "metadata": {}
-- 
cgit