From 92cca121f959c6616e3da431c1e2d23c4fa5e886 Mon Sep 17 00:00:00 2001 From: hardythe1 Date: Tue, 7 Apr 2015 15:58:05 +0530 Subject: added books --- TestContribution/Chapter2.ipynb | 322 ++++++++++++++++++++++++++++++++++++++++ 1 file changed, 322 insertions(+) create mode 100755 TestContribution/Chapter2.ipynb (limited to 'TestContribution/Chapter2.ipynb') diff --git a/TestContribution/Chapter2.ipynb b/TestContribution/Chapter2.ipynb new file mode 100755 index 00000000..f5907f3a --- /dev/null +++ b/TestContribution/Chapter2.ipynb @@ -0,0 +1,322 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:d3b8a40a5268a38ad3fc311ebed2078460c9192ee65f2f5e3922c8f65a52bf49" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 2: Properties of Pure Substances" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex2.1:pg-22" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# initialization of variables\n", + "\n", + "m=1; #mass of saturated water in kg\n", + "\n", + " # All the necessary values are taken from table C-2\n", + " \n", + "# part (a)\n", + "\n", + "P=0.001; # Pressure in MPa\n", + "vf=0.001; #specific volume of saturated liquid at 0.001 Mpa in Kg/m^3\n", + "vg=129.2; # specific volume of saturated vapour at 0.001 Mpa in Kg/m^3\n", + "deltaV=m*(vg-vf) # by properties of pure substance \n", + "# result\n", + "print \"The Volume change at pressure \",(P),\" MPa is\",round(deltaV,1),\" m^3/kg \\n\"\n", + "\n", + "# part (b) \n", + "\n", + "P=0.10; # Pressure in MPa\n", + "vf=0.001; # specific volume of saturated liquid at 0.26 MPa( it is same from at 0.2 and 0.3 MPa upto 4 decimals)\n", + "vg=1.694; # specific volume of saturated vapour at 0.1 Mpa\n", + "deltaV=m*(vg-vf) # by properties of pure substance\n", + "# result\n", + "print \"The Volume change at pressure \",(P),\" MPa is\",round(deltaV,3),\" m^3/kg \\n\"\n", + "\n", + "# part (c) \n", + "P=10; # Pressure in MPa\n", + "vf=0.00145; # specific volume of saturated liquid at 10 MPa\n", + "vg=0.01803; # specific volume of saturated vapour at 10 MPa\n", + "deltaV=m*(vg-vf) # by properties of pure substance \n", + "# result\n", + "print \"The Volume change at pressure \",(P),\" MPa is\",round(deltaV,5),\" m^3/kg \\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The Volume change at pressure 0.001 MPa is 129.2 m^3/kg \n", + "\n", + "The Volume change at pressure 0.1 MPa is 1.693 m^3/kg \n", + "\n", + "The Volume change at pressure 10 MPa is 0.01658 m^3/kg \n", + "\n" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex2.2:pg-23" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# initialization of variables\n", + "m=4.0 # mass of water in kg\n", + "V=1.0 # volume in m^3\n", + "T=150 # temperature of water in degree centigrade\n", + "\n", + "# TABLE C-1 is used for values in wet region\n", + "# Part (a)\n", + "P=475.8 # pressure in KPa in wet region at temperature of 150 *C\n", + "print \" The pressure is\",round(P,1),\" kPa \\n\"\n", + "\n", + "# Part (b)\n", + "#first we determine the dryness fraction\n", + "v=V/m # specific volume of water\n", + "vg=0.3928 # specific volume of saturated vapour @150 degree celsius\n", + "vf=0.00109 # specific volume of saturated liquid @150 degree celsius\n", + "x=(v-vf)/(vg-vf); # dryness fraction\n", + "mg=m*x; # mass of vapour\n", + "print \" The mass of vapour present is\",round(mg,3),\" kg \\n\"\n", + "\n", + "# Part(c) \n", + "Vg=vg*mg; # volume of vapour\n", + "print \" The volume of vapour is\",round(Vg,4),\" m^3\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The pressure is 475.8 kPa \n", + "\n", + " The mass of vapour present is 2.542 kg \n", + "\n", + " The volume of vapour is 0.9984 m^3\n" + ] + } + ], + "prompt_number": 12 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex2.3:pg-23" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# initialization of variables\n", + "m=4 # mass of water in kg\n", + "P=220 # pressure in KPa\n", + "x=0.8 # quality of steam\n", + "\n", + "# Table C-2 is used for values\n", + "\n", + "vg=(P-200)*(0.6058-0.8857)/(300-200)+0.8857 # specific volume of saturated vapour @ given pressure by interpolating\n", + "vf=0.0011 # specific volume of saturated liquid at 220 KPa\n", + "v=vf+x*(vg-vf)# property of pure substance\n", + "V=m*v # total volume\n", + "#result\n", + "print \"The Total volume of the mixture is \",round(V,3),\" m^3\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The Total volume of the mixture is 2.656 m^3\n" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Ex2.4:pg-23" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# initialization of variables\n", + "m=2 # mass of water in lb\n", + "P=540 # pressure in psi\n", + "T=700 # temperature in degree fahrenheit\n", + " # Table C-3E is used for values\n", + "v=1.3040+(P-500)*(1.0727-1.3030)/(600-500) # specific volue by interpolatin between 500 and 600 psi\n", + "V=m*v # final volume\n", + "print \"The Final Volume is\",round(V,3),\" ft^3\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The Final Volume is 2.424 ft^3\n" + ] + } + ], + "prompt_number": 9 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex2.5:pg-25" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# initialization of variables\n", + "V=0.6 # volume of tyre in m^3\n", + "Pgauge=200 # gauge pressure in KPa\n", + "T=20+273 # temperature converted to kelvin\n", + "Patm=100 # atmospheric pressure in KPa\n", + "R=287 # gas constant in Nm/kg.K\n", + "Pabs=(Pgauge+Patm)*1000 # calculating absolute pressue in Pa \n", + "\n", + "m=Pabs*V/(R*T)# mass from ideal gas equation\n", + "print \"The Mass of air is\",round(m,2),\" Kg\"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "The Mass of air is 2.14 Kg\n" + ] + } + ], + "prompt_number": 10 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex2.6:pg-26" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "import math\n", + "# initialization of variables\n", + "T=500+273 # temperature of steam in kelvin\n", + "rho=24.0 # density in Kg/m^3\n", + "R=0.462 # gas constant from Table B-2\n", + "v=1/rho # specific volume and density relation\n", + "# PART (a)\n", + "P=rho*R*T # from Ideal gas equation\n", + "print \" PART (a) The Pressure is \",int(P),\" KPa \\n\"\n", + "# answer is approximated in textbook\n", + "\n", + "# PART (b)\n", + "a=1.703 # van der Waal's constant a value from Table B-8\n", + "b=0.00169 # van der Waal's constant b value from Table B-8\n", + "P=(R*T/(v-b))-(a/v**2) # Pressure from van der Waals equation\n", + "print \" PART (b) The Pressure is \",int(P),\" KPa \\n\"\n", + "# answer is approximated in textbook\n", + "\n", + "# PART (c)\n", + "a=43.9 # van der Waal's constant a value from Table B-8\n", + "b=0.00117 # van der Waal's constant b value from Table B-8\n", + "\n", + "P=(R*T/(v-b))-(a/(v*(v+b)*math.sqrt(T))) # Redlich-Kwong equation\n", + "print \" PART (c) The Pressure is \",int(P),\" KPa \\n\"\n", + "# answer is approximated in textbook\n", + "\n", + "# PART (d)\n", + "Tcr=947.4 # compressibilty temperature from table B-3\n", + "Pcr=22100 # compressibility pressure from table B-3\n", + "\n", + "TR=T/Tcr # reduced temperature\n", + "PR=P/Pcr # reduced pressure\n", + "Z=0.93 # from compressiblility chart\n", + "P=Z*R*T/v # Pressure in KPa\n", + "print \" PART (d) The Pressure is \",int(P),\" KPa \\n\"\n", + "# answer is approximated in textbook\n", + "\n", + "# PART (e)\n", + "P=8000 # pressure from steam table @ 500*c and v= 0.0417 m^3\n", + "print \" PART (e) The Pressure is \",int(P),\" KPa \\n\"\n", + "# answer is approximated in textbook" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " PART (a) The Pressure is 8571 KPa \n", + "\n", + " PART (b) The Pressure is 7952 KPa \n", + "\n", + " PART (c) The Pressure is 7934 KPa \n", + "\n", + " PART (d) The Pressure is 7971 KPa \n", + "\n", + " PART (e) The Pressure is 8000 KPa \n", + "\n" + ] + } + ], + "prompt_number": 13 + } + ], + "metadata": {} + } + ] +} \ No newline at end of file -- cgit