From 64d949698432e05f2a372d9edc859c5b9df1f438 Mon Sep 17 00:00:00 2001 From: kinitrupti Date: Fri, 12 May 2017 18:40:35 +0530 Subject: Revised list of TBCs --- ...nciples_of_electronic_Instrumentation_Ch5.ipynb | 446 --------------------- 1 file changed, 446 deletions(-) delete mode 100755 Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb (limited to 'Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb') diff --git a/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb b/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb deleted file mode 100755 index c194e95b..00000000 --- a/Principles_Of_Electronic_Instrumentation/Pinciples_of_electronic_Instrumentation_Ch5.ipynb +++ /dev/null @@ -1,446 +0,0 @@ -{ - "metadata": { - "name": "" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 5: ADC and DAC" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_1,pg 491" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# output voltage\n", - "\n", - "import math\n", - "# Variable declaration\n", - "Vref=12.0 #ref. voltage\n", - "n =4.0 #no. of binary weighted resistors\n", - "n1=3.0 #input-1\n", - "n2=1.0 #input-2\n", - "\n", - "#Calculations\n", - "Vo=-(Vref/2**n)*(2**n1+2**n2)\n", - "\n", - "#Result \n", - "print(\"output voltage:\")\n", - "print(\"Vo = %.1f V\"%Vo) " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "output voltage:\n", - "Vo = -7.5 V\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_2,pg 491" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# voltage division ratio and feedback resistor\n", - "\n", - "import math\n", - "# Variabe declaration \n", - "# serie arm resistance = 10k, since the divider arm resistance Rsh=2Rse \n", - "# therefore for straight binary code, one should have section voltage ratio as Vos/Vis=0.5\n", - "\n", - "#Vo/Vref=0.5\n", - "Rse=10*10**3 #series resistance(Rsh/2)\n", - "\n", - "#Calculation\n", - "Rf=0.5*(16*Rse)/15 #feedback resistor\n", - "\n", - "#Result\n", - "print(\"voltage section ratio = 0.5\")\n", - "print(\"\\nfeedback resistor:\")\n", - "print(\"Rf = %.2f k-ohm\"%(Rf/1000)) " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "voltage section ratio = 0.5\n", - "\n", - "feedback resistor:\n", - "Rf = 5.33 k-ohm\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_3,pg 492" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# output voltage\n", - "\n", - "import math\n", - "#Variable declaration\n", - "Rse = 1*10**3 #series resistance\n", - "Rsh = 2*10**3 #shunt resistance\n", - "Vref= 5.0 #ref. voltage\n", - "n1 = 0 #input-1\n", - "n2 = 3 #input-2\n", - "Ro=0.22*10**3 #load resistance\n", - "\n", - "#Calculations\n", - "Vo=(Vref*(2**n1+2**n2)/16)*(Ro/(Ro+Rsh))\n", - "\n", - "#Result\n", - "print(\"output voltage:\")\n", - "print(\"Vo = %.3f V\"%(math.floor(Vo*1000)/1000)) " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "output voltage:\n", - "Vo = 0.278 V\n" - ] - } - ], - "prompt_number": 4 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_4,pg 492" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# find count\n", - "\n", - "import math\n", - "#Variable declaration\n", - "Vref=5.0 #ref. voltage\n", - "t=1*10**-3 #sawtooth wave time\n", - "f=100*10**3 #clock frequency\n", - "Vi=1 #input voltage\n", - "\n", - "#Calculations\n", - "N=((t*f*Vi)/Vref) #count\n", - "\n", - "#Result\n", - "print(\"count = %d\"%N)" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "count = 20\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_5,pg 492" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# find integrator output voltage\n", - "\n", - "import math\n", - "#Variable declaration\n", - "Tu=1*10**-3 #wave time\n", - "Vi=0.2 #input voltage\n", - "t=4*10**-3 #integration time constant(1/RC)\n", - "\n", - "\n", - "#Calculation\n", - "V1=((Vi*Tu)/t) #integrator output voltage\n", - "\n", - "#Result\n", - "print(\"integrator output voltage:\")\n", - "print(\"V1 = %.2f V\"%V1) " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "integrator output voltage:\n", - "V1 = 0.05 V\n" - ] - } - ], - "prompt_number": 8 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_6,pg 493" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# find rise in output voltage and charging time\n", - "\n", - "import math\n", - "#Variable declaration\n", - "Tz=0.6*10**-3 #discharge time\n", - "Vref=1 #ref. voltage\n", - "t=4*10**-3 #integrator time const.\n", - "Vi=0.2 #input voltage\n", - "#Calculations\n", - "Vk=((Vref*Tz)/t) #rise in output integrator\n", - "Tu=Vref*(Tz/Vi) #charging time\n", - "\n", - "#Result\n", - "print(\"Rise in integrator output:\")\n", - "print(\"Vk = %.2f V\\n\"%Vk)\n", - "print(\"charging time:\")\n", - "print(\"Tu = %.0f msec\"%(Tu*1000)) " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Rise in integrator output:\n", - "Vk = 0.15 V\n", - "\n", - "charging time:\n", - "Tu = 3 msec\n" - ] - } - ], - "prompt_number": 8 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_7,pg 493" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# find count of counter\n", - "\n", - "import math\n", - "#Variable declaration\n", - "Vref=1 #ref. voltage\n", - "Vi=0.2 #input voltage\n", - "n=15 #no. of counts before reset(n+1)\n", - "\n", - "#Calculations\n", - "N=((n+1)*Vi)/Vref #no.of counts over charging time\n", - "\n", - "print(\"No of counts over charging time:\")\n", - "print(\"N = %.1f = %d(approx.) \"%(N,N)) " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "No of counts over charging time:\n", - "N = 3.2 = 3(approx.) \n" - ] - } - ], - "prompt_number": 10 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_8,pg 493" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# find input voltage\n", - "\n", - "import math\n", - "Nx=2**6 #6 bit counteer register\n", - "Vref=2.2 #ref. voltage\n", - "N=32.0 #SAR output\n", - "\n", - "#Calculations\n", - "Vi=(N/(Nx+1)*Vref) #input voltage\n", - "\n", - "#Result\n", - "print(\"Input Voltage:\")\n", - "print(\"Vi = %.2f V\"%Vi) " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Input Voltage:\n", - "Vi = 1.08 V\n" - ] - } - ], - "prompt_number": 14 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_9,pg 493" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# conversion number\n", - "\n", - "import math\n", - "#Variable declaration\n", - "n=3 #3-bit ADC\n", - "Vref=2.2 #ref.voltage\n", - "Vi=1 #input voltage\n", - "\n", - "#Calculations\n", - "N=(((2**n)-1)*Vi)/Vref #SAR output\n", - "\n", - "#Result\n", - "print(\"SAR conversion no.:\")\n", - "print(\"N = %.2f \"%N) " - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "SAR conversion no.:\n", - "N = 3.18 \n" - ] - } - ], - "prompt_number": 15 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example5_10,pg 493" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# signal to noise ratio\n", - "\n", - "import math\n", - "#Variable declaaration\n", - "n = 3.0 #3-bit ADC\n", - "\n", - "#Calculations\n", - "SbyN=(((2**(n-1)*12**0.5)/2**0.5)) #S/N ratio\n", - "\n", - "#Result\n", - "print(\"S/N ratio:\")\n", - "print(\"SbyN = %.3f\\n\"%SbyN) \n", - "print(\"This produces an error due to noise nearly 10%\")" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "S/N ratio:\n", - "SbyN = 9.798\n", - "\n", - "This produces an error due to noise nearly 10%\n" - ] - } - ], - "prompt_number": 14 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit