From 41f1f72e9502f5c3de6ca16b303803dfcf1df594 Mon Sep 17 00:00:00 2001 From: Thomas Stephen Lee Date: Fri, 4 Sep 2015 22:04:10 +0530 Subject: add/remove/update books --- Power_Electronics/chapter4.ipynb | 946 --------------------------------------- 1 file changed, 946 deletions(-) delete mode 100755 Power_Electronics/chapter4.ipynb (limited to 'Power_Electronics/chapter4.ipynb') diff --git a/Power_Electronics/chapter4.ipynb b/Power_Electronics/chapter4.ipynb deleted file mode 100755 index 22311574..00000000 --- a/Power_Electronics/chapter4.ipynb +++ /dev/null @@ -1,946 +0,0 @@ -{ - "metadata": { - "name": "" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 04 : Thyristors" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.3, Page No 149" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "P=.5 #P=V_g*I_g\n", - "s=130 #s=V_g/I_g\n", - "\n", - "#Calculations\n", - "I_g=math.sqrt(P/s)\n", - "V_g=s*I_g\n", - "E=15\n", - "R_s=(E-V_g)/I_g \n", - "\n", - "#Results\n", - "print(\"Gate source resistance=%.2f ohm\" %R_s)\n", - "#Answers have small variations from that in the book due to difference in the rounding off of digits." - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Gate source resistance=111.87 ohm\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.4, Page No 149" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "\n", - "#initialisation of variables\n", - "\n", - "R_s=120 #slope of load line is -120V/A. This gives gate source resistance\n", - "print(\"gate source resistance=%.0f ohm\" %R_s)\n", - "\n", - "P=.4 #P=V_g*I_g\n", - "E_s=15\n", - "\n", - "#Calculations\n", - " #E_s=I_g*R_s+V_g % after solving this\n", - " #120*I_g**2-15*I_g+0.4=0 so\n", - "a=120 \n", - "b=-15\n", - "c=0.4\n", - "D=math.sqrt((b**2)-4*a*c)\n", - "I_g=(-b+D)/(2*a) \n", - "V_g=P/I_g\n", - "\n", - "#Results\n", - "print(\"\\ntrigger current=%.2f mA\" %(I_g*10**3)) \n", - "print(\"\\nthen trigger voltage=%.3f V\" %V_g)\n", - "I_g=(-b-D)/(2*a) \n", - "V_g=P/I_g\n", - "print(\"\\ntrigger current=%.2f mA\" %(I_g*10**3)) \n", - "print(\"\\nthen trigger voltage=%.2f V\" %V_g)" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "gate source resistance=120 ohm\n", - "\n", - "trigger current=86.44 mA\n", - "\n", - "then trigger voltage=4.628 V\n", - "\n", - "trigger current=38.56 mA\n", - "\n", - "then trigger voltage=10.37 V\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.5 Page No 150" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "\n", - "#initialisation of variables\n", - "\n", - "#V_g=1+10*I_g\n", - "P_gm=5 #P_gm=V_g*I_g\n", - "#after solving % eqn becomes 10*I_g**2+I_g-5=0\n", - "a=10.0 \n", - "b=1.0 \n", - "c=-5\n", - "\n", - "#Calculations\n", - "I_g=(-b+math.sqrt(b**2-4*a*c))/(2*a)\n", - "E_s=15\n", - "#using E_s=R_s*I_g+V_g\n", - "R_s=(E_s-1)/I_g-10 \n", - "P_gav=.3 #W\n", - "T=20*10**-6\n", - "f=P_gav/(P_gm*T)\n", - "dl=f*T\n", - "\n", - "#Results\n", - "print(\"Reistance=%.3f ohm\" %R_s)\n", - "print(\"Triggering freq=%.0f kHz\" %(f/1000))\n", - "print(\"Tduty cycle=%.2f\" %dl)" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Reistance=11.248 ohm\n", - "Triggering freq=3 kHz\n", - "Tduty cycle=0.06\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.6, Page No 151" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "I=.1\n", - "E=200.0\n", - "L=0.2\n", - "\n", - "#Calculations\n", - "t=I*L/E \n", - "R=20.0\n", - "t1=(-L/R)*math.log(1-(R*I/E)) \n", - "L=2.0\n", - "t2=(-L/R)*math.log(1-(R*I/E)) \n", - "\n", - "#Results\n", - "print(\"in case load consists of (a)L=.2H\")\n", - "print(\"min gate pulse width=%.0f us\" %(t*10**6))\n", - "print(\"(b)R=20ohm in series with L=.2H\")\n", - "print(\"min gate pulse width=%.3f us\" %(t1*10**6))\n", - "print(\"(c)R=20ohm in series with L=2H\")\n", - "print(\"min gate pulse width=%.2f us\" %(t2*10**6))" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "in case load consists of (a)L=.2H\n", - "min gate pulse width=100 us\n", - "(b)R=20ohm in series with L=.2H\n", - "min gate pulse width=100.503 us\n", - "(c)R=20ohm in series with L=2H\n", - "min gate pulse width=1005.03 us\n" - ] - } - ], - "prompt_number": 4 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.9 Page No 163" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "\n", - "#initialisation of variables\n", - "\n", - "def theta(th):\n", - " I_m=1 #supposition\n", - " I_av=(I_m/(2*math.pi))*(1+math.cos(math.radians(th)))\n", - " I_rms=math.sqrt((I_m/(2*math.pi))*((180-th)*math.pi/360+.25*math.sin(math.radians(2*th))))\n", - " FF=I_rms/I_av\n", - " I_rms=35\n", - " I_TAV=I_rms/FF\n", - " return I_TAV\n", - "\n", - "#Calculations\n", - "print(\"when conduction angle=180\")\n", - "th=0\n", - "I_TAV=theta(th)\n", - "print(\"avg on current rating=%.3f A\" %I_TAV)\n", - "print(\"when conduction angle=90\")\n", - "th=90\n", - "I_TAV=theta(th)\n", - "\n", - "#Results\n", - "print(\"avg on current rating=%.3f A\" %I_TAV)\n", - "print(\"when conduction angle=30\")\n", - "th=150\n", - "I_TAV=theta(th)\n", - "print(\"avg on current rating=%.3f A\" %I_TAV)" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "when conduction angle=180\n", - "avg on current rating=22.282 A\n", - "when conduction angle=90\n", - "avg on current rating=15.756 A\n", - "when conduction angle=30\n", - "avg on current rating=8.790 A\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.10, Page No 164" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "\n", - "def theta(th):\n", - " n=360.0/th\n", - " I=1.0 #supposition\n", - " I_av=I/n\n", - " I_rms=I/math.sqrt(n)\n", - " FF=I_rms/I_av\n", - " I_rms=35\n", - " I_TAV=I_rms/FF\n", - " return I_TAV\n", - "\n", - "#Calculations\n", - "th=180.0\n", - "I_TAV1=theta(th)\n", - "th=90.0\n", - "I_TAV2=theta(th)\n", - "th=30.0\n", - "I_TAV3=theta(th)\n", - "\n", - "#Results\n", - "print(\"when conduction angle=180\")\n", - "print(\"avg on current rating=%.3f A\" %I_TAV)\n", - "print(\"when conduction angle=90\")\n", - "print(\"avg on current rating=%.1f A\" %I_TAV2)\n", - "print(\"when conduction angle=30\")\n", - "print(\"avg on current rating=%.4f A\" %I_TAV3)\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "when conduction angle=180\n", - "avg on current rating=8.790 A\n", - "when conduction angle=90\n", - "avg on current rating=17.5 A\n", - "when conduction angle=30\n", - "avg on current rating=10.1036 A\n" - ] - } - ], - "prompt_number": 6 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.11 Page No 165" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math \n", - "\n", - "#initialisation of variables\n", - "f=50.0 #Hz\n", - "\n", - "#Calculations\n", - "I_sb=3000.0\n", - "t=1/(4*f)\n", - "T=1/(2*f)\n", - "I=math.sqrt(I_sb**2*t/T) \n", - "r=(I_sb/math.sqrt(2))**2*T \n", - "\n", - "#Results\n", - "print(\"surge current rating=%.2f A\" %I)\n", - "print(\"\\nI**2*t rating=%.0f A^2.s\" %r)\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "surge current rating=2121.32 A\n", - "\n", - "I**2*t rating=45000 A^2.s\n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.12 Page No 165" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "\n", - "V_s=300.0 #V\n", - "R=60.0 #ohm\n", - "L=2.0 #H\n", - "\n", - "#Calculations\n", - "t=40*10**-6 #s\n", - "i_T=(V_s/R)*(1-math.exp(-R*t/L))\n", - "i=.036 #A\n", - "R1=V_s/(i-i_T)\n", - "\n", - "#Results\n", - "print(\"maximum value of remedial parameter=%.3f kilo-ohm\" %(R1/1000))\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "maximum value of remedial parameter=9.999 kilo-ohm\n" - ] - } - ], - "prompt_number": 8 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.16 Page No 172" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "\n", - "#initialisation of variables\n", - "V_p=230.0*math.sqrt(2)\n", - "\n", - "#Calculations\n", - "R=1+((1)**-1+(10)**-1)**-1\n", - "A=V_p/R\n", - "s=1 #s\n", - "t_c=20*A**-2*s\n", - "\n", - "#Results\n", - "print(\"fault clearance time=%.4f ms\" %(t_c*10**3))\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "fault clearance time=0.6890 ms\n" - ] - } - ], - "prompt_number": 9 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.17, Page No 176" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "\n", - "#initialisation of variables\n", - "\n", - "V_s=math.sqrt(2)*230 #V\n", - "L=15*10**-6 #H\n", - "I=V_s/L #I=(di/dt)_max\n", - "R_s=10 #ohm\n", - "v=I*R_s #v=(dv/dt)_max\n", - "\n", - "#Calculations\n", - "f=50 #Hz\n", - "X_L=L*2*math.pi*f\n", - "R=2\n", - "I_max=V_s/(R+X_L) \n", - "FF=math.pi/math.sqrt(2)\n", - "I_TAV1=I_max/FF \n", - "FF=3.98184\n", - "I_TAV2=I_max/FF \n", - "\n", - "\n", - "#RESULTS\n", - "print(\"(di/dt)_max=%.3f A/usec\" %(I/10**6))\n", - "print(\"\\n(dv/dt)_max=%.2f V/usec\" %(v/10**6))\n", - "print(\"\\nI_rms=%.3f A\" %I_max)\n", - "print(\"when conduction angle=90\")\n", - "print(\"I_TAV=%.3f A\" %I_TAV1)\n", - "print(\"when conduction angle=30\")\n", - "print(\"I_TAV=%.3f A\" %I_TAV2)\n", - "print(\"\\nvoltage rating=%.3f V\" %(2.75*V_s)) #rating is taken 2.75 times of peak working voltage unlike 2.5 to 3 times as mentioned int book." - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "(di/dt)_max=21.685 A/usec\n", - "\n", - "(dv/dt)_max=216.85 V/usec\n", - "\n", - "I_rms=162.252 A\n", - "when conduction angle=90\n", - "I_TAV=73.039 A\n", - "when conduction angle=30\n", - "I_TAV=40.748 A\n", - "\n", - "voltage rating=894.490 V\n" - ] - } - ], - "prompt_number": 10 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.19, Page No 186" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "\n", - "T_jm=125\n", - "th_jc=.15 #degC/W\n", - "th_cs=0.075 #degC/W\n", - "\n", - "\n", - "#Calculations\n", - "dT=54 #dT=T_s-T_a\n", - "P_av=120\n", - "th_sa=dT/P_av\n", - "T_a=40 #ambient temp\n", - "P_av=(T_jm-T_a)/(th_sa+th_jc+th_cs)\n", - "if (P_av-120)<1 :\n", - " print(\"selection of heat sink is satisfactory\")\n", - "\n", - "dT=58 #dT=T_s-T_a\n", - "P_av=120\n", - "th_sa=dT/P_av\n", - "T_a=40 #ambient temp\n", - "P_av=(T_jm-T_a)/(th_sa+th_jc+th_cs)\n", - "if (P_av-120)<1 :\n", - " print(\"selection of heat sink is satisfactory\")\n", - "\n", - "V_m=math.sqrt(2)*230\n", - "R=2\n", - "I_TAV=V_m/(R*math.pi)\n", - "P_av=90\n", - "th_sa=(T_jm-T_a)/P_av-(th_jc+th_cs)\n", - "dT=P_av*th_sa\n", - "print(\"for heat sink\") \n", - "print(\"T_s-T_a=%.2f degC\" %dT) \n", - "print(\"\\nP_av=%.0f W\" %P_av)\n", - "P=(V_m/2)**2/R\n", - "eff=P/(P+P_av) \n", - "print(\"\\nckt efficiency=%.3f pu\" %eff)\n", - "a=60 #delay angle\n", - "I_TAV=(V_m/(2*math.pi*R))*(1+math.cos(math.radians(a)))\n", - "print(\"\\nI_TAV=%.2f A\" %I_TAV)\n", - "dT=46\n", - "T_s=dT+T_a\n", - "T_c=T_s+P_av*th_cs \n", - "T_j=T_c+P_av*th_jc \n", - "\n", - "#Results\n", - "print(\"\\ncase temp=%.2f degC\" %T_c)\n", - "print(\"\\njunction temp=%.2f degC\" %T_j)\n", - "\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "for heat sink\n", - "T_s-T_a=-20.25 degC\n", - "\n", - "P_av=90 W\n", - "\n", - "ckt efficiency=0.993 pu\n", - "\n", - "I_TAV=38.83 A\n", - "\n", - "case temp=92.75 degC\n", - "\n", - "junction temp=106.25 degC\n" - ] - } - ], - "prompt_number": 11 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.20, Page No 187" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "T_j=125.0 #degC\n", - "T_s=70.0 #degC\n", - "th_jc=.16 #degC/W\n", - "th_cs=.08 #degC/W\n", - "\n", - "#Calculations\n", - "P_av1=(T_j-T_s)/(th_jc+th_cs) \n", - "\n", - "T_s=60 #degC\n", - "P_av2=(T_j-T_s)/(th_jc+th_cs) \n", - "inc=(math.sqrt(P_av2)-math.sqrt(P_av1))*100/math.sqrt(P_av1) \n", - "\n", - "#Results\n", - "print(\"Total avg power loss in thristor sink combination=%.2f W\" %P_av1)\n", - "print(\"Percentage inc in rating=%.2f\" %inc)" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Total avg power loss in thristor sink combination=229.17 W\n", - "Percentage inc in rating=8.71\n" - ] - } - ], - "prompt_number": 12 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.21, Page No 197" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "\n", - "R=25000.0\n", - "I_l1=.021 #I_l=leakage current\n", - "I_l2=.025\n", - "I_l3=.018\n", - "I_l4=.016\n", - " #V1=(I-I_l1)*R\n", - " #V2=(I-I_l2)*R\n", - " #V3=(I-I_l3)*R\n", - " #V4=(I-I_l4)*R\n", - " #V=V1+V2+V3+V4\n", - " \n", - "#Calculations\n", - "V=10000.0\n", - "I_l=I_l1+I_l2+I_l3+I_l4\n", - " #after solving\n", - "I=((V/R)+I_l)/4\n", - "R_c=40.0\n", - "V1=(I-I_l1)*R \n", - "\n", - "#Resluts\n", - "print(\"voltage across SCR1=%.0f V\" %V1)\n", - "V2=(I-I_l2)*R \n", - "print(\"\\nvoltage across SCR2=%.0f V\" %V2)\n", - "V3=(I-I_l3)*R \n", - "print(\"\\nvoltage across SCR3=%.0f V\" %V3)\n", - "V4=(I-I_l4)*R \n", - "print(\"\\nvoltage across SCR4=%.0f V\" %V4)\n", - "\n", - "I1=V1/R_c \n", - "print(\"\\ndischarge current through SCR1=%.3f A\" %I1)\n", - "I2=V2/R_c \n", - "print(\"\\ndischarge current through SCR2=%.3f A\" %I2)\n", - "I3=V3/R_c \n", - "print(\"\\ndischarge current through SCR3=%.3f A\" %I3)\n", - "I4=V4/R_c \n", - "print(\"\\ndischarge current through SCR4=%.3f A\" %I4)\n", - "\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "voltage across SCR1=2475 V\n", - "\n", - "voltage across SCR2=2375 V\n", - "\n", - "voltage across SCR3=2550 V\n", - "\n", - "voltage across SCR4=2600 V\n", - "\n", - "discharge current through SCR1=61.875 A\n", - "\n", - "discharge current through SCR2=59.375 A\n", - "\n", - "discharge current through SCR3=63.750 A\n", - "\n", - "discharge current through SCR4=65.000 A\n" - ] - } - ], - "prompt_number": 13 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.22, Page No 198" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "V_r=1000 #rating of SCR\n", - "I_r=200 #rating of SCR\n", - "V_s=6000 #rating of String\n", - "I_s=1000 #rating of String\n", - "\n", - "#Calculations\n", - "print(\"when DRF=.1\")\n", - "DRF=.1\n", - "n_s=V_s/(V_r*(1-DRF)) \n", - "print(\"number of series units=%.0f\" %math.ceil(n_s))\n", - "n_p=I_s/(I_r*(1-DRF)) \n", - "print(\"\\nnumber of parrallel units=%.0f\" %math.ceil(n_p))\n", - "print(\"when DRF=.2\")\n", - "DRF=.2\n", - "\n", - "#Results\n", - "n_s=V_s/(V_r*(1-DRF)) \n", - "print(\"number of series units=%.0f\" %math.ceil(n_s))\n", - "n_p=I_s/(I_r*(1-DRF)) \n", - "print(\"\\nnumber of parrallel units=%.0f\" %math.ceil(n_p))" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "when DRF=.1\n", - "number of series units=7\n", - "\n", - "number of parrallel units=6\n", - "when DRF=.2\n", - "number of series units=8\n", - "\n", - "number of parrallel units=7\n" - ] - } - ], - "prompt_number": 14 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.23, Page No 198" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "V1=1.6 #on state voltage drop of SCR1\n", - "V2=1.2 #on state voltage drop of SCR2\n", - "I1=250.0 #current rating of SCR1\n", - "I2=350.0 #current rating of SCR2\n", - "\n", - "#Calculations\n", - "R1=V1/I1\n", - "R2=V2/I2\n", - "I=600.0 #current to be shared\n", - " #for SCR1 % I*(R1+R)/(total resistance)=k*I1 (1)\n", - " #for SCR2 % I*(R2+R)/(total resistance)=k*I2 (2)\n", - " #(1)/(2)\n", - "R=(R2*I2-R1*I1)/(I1-I2)\n", - "\n", - "\n", - "#Results\n", - "print(\"RSequired value of resistance=%.3f ohm\" %R)" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "RSequired value of resistance=0.004 ohm\n" - ] - } - ], - "prompt_number": 15 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.25, Page No 223" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "f=2000.0 #Hz\n", - "C=0.04*10**-6\n", - "n=.72\n", - "\n", - "#Calculations\n", - "R=1/(f*C*math.log(1/(1-n))) \n", - "V_p=18\n", - "V_BB=V_p/n\n", - "R2=10**4/(n*V_BB) \n", - "I=4.2*10**-3 #leakage current\n", - "R_BB=5000\n", - "R1=(V_BB/I)-R2-R_BB\n", - "\n", - "#Results\n", - "print(\"R=%.2f kilo-ohm\" %(R/1000))\n", - "print(\"\\nR2=%.2f ohm\" %R2)\n", - "print(\"\\nR1=%.0f ohm\" %R1)\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "R=9.82 kilo-ohm\n", - "\n", - "R2=555.56 ohm\n", - "\n", - "R1=397 ohm\n" - ] - } - ], - "prompt_number": 16 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4.26, Page No 223" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "import math\n", - "#initialisation of variables\n", - "\n", - "V_p=18.0\n", - "n=.72\n", - "V_BB=V_p/n\n", - "I_p=.6*10**-3\n", - "I_v=2.5*10**-3\n", - "V_v=1\n", - "\n", - "#Calculations\n", - "R_max=V_BB*(1-n)/I_p \n", - "print(\"R_max=%.2f kilo-ohm\" %(R_max/1000))\n", - "R_min=(V_BB-V_v)/I_v \n", - "print(\"\\nR_min=%.2f kilo-ohm\" %(R_min/1000))\n", - "\n", - "C=.04*10**-6\n", - "f_min=1/(R_max*C*math.log(1/(1-n))) \n", - "print(\"\\nf_min=%.3f kHz\" %(f_min/1000))\n", - "f_max=1/(R_min*C*math.log(1/(1-n))) \n", - "print(\"\\nf_max=%.2f kHz\" %(f_max/1000))\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "R_max=11.67 kilo-ohm\n", - "\n", - "R_min=9.60 kilo-ohm\n", - "\n", - "f_min=1.683 kHz\n", - "\n", - "f_max=2.05 kHz\n" - ] - } - ], - "prompt_number": 17 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit