From fba055ce5aa0955e22bac2413c33493b10ae6532 Mon Sep 17 00:00:00 2001 From: hardythe1 Date: Tue, 5 May 2015 14:21:39 +0530 Subject: add books --- Physical_Chemsitry/Chapter13.ipynb | 401 ------------------------------------- 1 file changed, 401 deletions(-) delete mode 100755 Physical_Chemsitry/Chapter13.ipynb (limited to 'Physical_Chemsitry/Chapter13.ipynb') diff --git a/Physical_Chemsitry/Chapter13.ipynb b/Physical_Chemsitry/Chapter13.ipynb deleted file mode 100755 index 79973f5f..00000000 --- a/Physical_Chemsitry/Chapter13.ipynb +++ /dev/null @@ -1,401 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:b3b8e3a1df1ec221a5596f2fd615d0e7df4ba35a4012aeb734d5820e6983cd64" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter 13 - Thermodynamic changes accompanying chemical reaction" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 1 - pg 320" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the dHp value\n", - "#Initialization of variables\n", - "n1=10 #mol\n", - "n2=12 #mol\n", - "#calculations\n", - "dn=n1-n2\n", - "#results\n", - "print '%s %d %s' %(\"dHp = dEv-\",dn,\"*RT\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "dHp = dEv- -2 *RT\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 2 - pg 322" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the Enthalpy\n", - "#Initialization of variables\n", - "Ht1=-22063 #cal\n", - "T=298.15 #K\n", - "#calculations\n", - "H=Ht1 +0.5293*T + 0.3398*10**-3 *T**2 - 2.039*10**-7 *T**3\n", - "#results\n", - "print '%s %d %s' %(\"Enthalpy =\",H,\"cal\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Enthalpy = -21880 cal\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 3 - pg 326" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the Entropy\n", - "#Initialization of variables\n", - "Cp=0.797 #cal/deg/mol\n", - "#calculations\n", - "S=Cp/3.\n", - "#results\n", - "print '%s %.3f %s' %(\"Entropy =\",S,\" eu/mol\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Entropy = 0.266 eu/mol\n" - ] - } - ], - "prompt_number": 4 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 4 - pg 328" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the Change in entropy\n", - "#Initialization of variables\n", - "T1=77.32 #K\n", - "P=1 #atm\n", - "T2=126 #K\n", - "Pc=33.5 #atm\n", - "#calculations\n", - "dS=27/32. *1.987*P/Pc *(T2/T1)**3\n", - "#results\n", - "print '%s %.2f %s' %(\"Change in entropy =\",dS,\"eu/mol\")" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Change in entropy = 0.22 eu/mol\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 5 - pg 330" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the Change in entropy, enthalpy and free energy\n", - "#Initialization of variables\n", - "S1=57.47\n", - "S2=50.34\n", - "S3=49\n", - "H1=8.09\n", - "H2=21.06\n", - "H3=0\n", - "F1=12.39\n", - "F2=20.72\n", - "F3=0\n", - "#calculations\n", - "dS=S1-S2-0.5*S3\n", - "dH=H1-H2-0.5*H3\n", - "dF=F1-F2-0.5*F3\n", - "#results\n", - "print '%s %.2f %s' %(\"Change in entropy =\",dS,\" eu\")\n", - "print '%s %.2f %s' %(\"\\n Change in enthalpy =\",dH,\" kcal\")\n", - "print '%s %.2f %s' %(\"\\n Change in free energy =\",dF,\"kcal\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Change in entropy = -17.37 eu\n", - "\n", - " Change in enthalpy = -12.97 kcal\n", - "\n", - " Change in free energy = -8.33 kcal\n" - ] - } - ], - "prompt_number": 6 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 6 - pg 334" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the change in free energy\n", - "#Initialization of variables\n", - "import math\n", - "P1=0.01\n", - "P2=0.1\n", - "P3=0.01\n", - "dF0=-54640 #cal\n", - "T=298.15 #K\n", - "R=1.987 #cal/deg\n", - "#calculations\n", - "Qp=P1/(P2*P3**0.5)\n", - "dF=dF0+R*T*math.log(Qp)\n", - "#results\n", - "print '%s %d %s' %(\"change in free energy =\",dF,\"cal\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "change in free energy = -54640 cal\n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 7 - pg 335" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the Equilibrium constant\n", - "#Initialization of variables\n", - "print \"From table 13.4 \"\n", - "logKfwater=40.04724\n", - "logKfH2=0\n", - "logKfO2=0\n", - "#calculations\n", - "logK=logKfwater-logKfH2-0.5*logKfO2\n", - "K=10**logK\n", - "#results\n", - "print '%s %.4e' %(\"Equilibrium constant = \",K)\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "From table 13.4 \n", - "Equilibrium constant = 1.1149e+40\n" - ] - } - ], - "prompt_number": 8 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 8 - pg 339" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the value of Kc\n", - "#Initialization of variables\n", - "Kp=1.1*10**40 #atm**-0.5\n", - "dn=-0.5\n", - "R=0.08206 #lt atm/deg mol\n", - "T=298.15 #K\n", - "#calculations\n", - "Kc=Kp*(R*T)**(-dn)\n", - "#results\n", - "print '%s %.1e %s' %(\"Kc =\",Kc,\" (mol/lt)^-0.5\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Kc = 5.4e+40 (mol/lt)^-0.5\n" - ] - } - ], - "prompt_number": 1 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 9 - pg 339" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the Density of equilibrium mixture\n", - "#Initialization of variables\n", - "import numpy\n", - "Kp=0.141 #atm\n", - "P=1 #atm\n", - "nu=2\n", - "R=0.08206 #lt atm/deg mol\n", - "T=298.15 #K\n", - "M=92.02 #g/mol\n", - "#calculations\n", - "p=([Kp+ 4*P,0, -Kp])\n", - "z=numpy.roots(p)\n", - "alpha=z[0]\n", - "wbyV=P*M/(R*T*(1+(nu-1)*alpha))\n", - "#results\n", - "print '%s %.2f %s' %(\"Density of the equilibrium mixture =\",wbyV,\" g/lt\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Density of the equilibrium mixture = 3.18 g/lt\n" - ] - } - ], - "prompt_number": 11 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example 10 - pg 340" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#calculate the Final pressure after equilibrium\n", - "#Initialization of variables\n", - "x=0.5\n", - "P=0.468 #atm\n", - "#calculations\n", - "P1=x*P\n", - "P2=x*P\n", - "Kp=P1*P2\n", - "#results\n", - "print '%s %.4f %s' %(\"Final pressure after equilibrium =\",Kp,\" atm^2\")\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Final pressure after equilibrium = 0.0548 atm^2\n" - ] - } - ], - "prompt_number": 12 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit