From c7fe425ef3c5e8804f2f5de3d8fffedf5e2f1131 Mon Sep 17 00:00:00 2001 From: hardythe1 Date: Tue, 7 Apr 2015 15:58:05 +0530 Subject: added books --- Physical_Chemsitry/Chapter12.ipynb | 348 +++++++++++++++++++++++++++++++++++++ 1 file changed, 348 insertions(+) create mode 100755 Physical_Chemsitry/Chapter12.ipynb (limited to 'Physical_Chemsitry/Chapter12.ipynb') diff --git a/Physical_Chemsitry/Chapter12.ipynb b/Physical_Chemsitry/Chapter12.ipynb new file mode 100755 index 00000000..92f1a058 --- /dev/null +++ b/Physical_Chemsitry/Chapter12.ipynb @@ -0,0 +1,348 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:65a756a76ade1ec4b9387e0db33894444f541be4a142adaa7f77f2e89d036580" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 12 - Physical Equilibria" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 1 - pg 295" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the no of degrees of freedom\n", + "#Initialization of variables\n", + "p=3\n", + "c=2\n", + "#calculations\n", + "f=2-p+c\n", + "#results\n", + "print '%s %d' %(\"no. of degrees of freedom =\",f)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "no. of degrees of freedom = 1\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 2 - pg 301" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the change in temperature\n", + "#Initialization of variables\n", + "T=273.2 #K\n", + "vw=1.0001 #cm^3 /g\n", + "vi=1.0907 #cm^3 /g\n", + "hf=79.7 #cal/g\n", + "P1=76 #cm\n", + "P2=4.6 #cm\n", + "#calculations\n", + "dT=T*(vw-vi)*(P2-P1)*13.6*980.7/(hf*4.184*10**7)\n", + "#results\n", + "print '%s %.4f %s' %(\"change in temperature =\",dT,\"deg\")\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "change in temperature = 0.0071 deg\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 3 - pg 302" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the value of dPbydT\n", + "#Initialization of variables\n", + "V=6.84 #cm^3 /g\n", + "#calculations\n", + "dPbydT=-1.7*4.184*10**7 /(2.19*V*0.06*1.01*10**6)\n", + "#results\n", + "print '%s %d %s' %(\"dPbydT =\",dPbydT,\" atm/deg\")\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "dPbydT = -78 atm/deg\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 4 - pg 303" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the Pressure\n", + "#Initialization of variables\n", + "P=6 #atm\n", + "T=273.2+25 #K\n", + "P=23.8 #mm\n", + "V=0.018 #lt/mol\n", + "R=0.08206 #lt am/deg mol\n", + "#calculations\n", + "dPa=V*P*4536/(R*T*760)\n", + "Pa=dPa+P\n", + "#results\n", + "print '%s %.1f %s' %(\"Pressure =\",Pa,\" mm\")\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Pressure = 23.9 mm\n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 5 - pg 305" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the mole fraction of methanol in vapor\n", + "#Initialization of variables\n", + "x=0.25\n", + "Ps1=96 #mm\n", + "Ps2=43.9 #mm\n", + "#calculations\n", + "P1=x*Ps1\n", + "P2=(1-x)*Ps2\n", + "P=P1+P2\n", + "Xdash=P1/P\n", + "#results\n", + "print '%s %.3f' %(\"mole fraction of methanol in vapor =\",Xdash)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "mole fraction of methanol in vapor = 0.422\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 6 - pg 309" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the Molal elevation constant\n", + "#Initialization of variables\n", + "Hv=539.6 #cal/g\n", + "T=273.2+100 #K\n", + "#calculations\n", + "Kb=1.987*T**2 /(1000*Hv)\n", + "#results\n", + "print '%s %.3f %s' %(\"Molal elevation constant =\",Kb,\" deg /mole /kg\")\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Molal elevation constant = 0.513 deg /mole /kg\n" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 7 - pg 309" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the Molecular weight of solute\n", + "#Initialization of variables\n", + "ms=0.5 #mol/kg\n", + "m=5 #g\n", + "mw=100 #g\n", + "Ws=1000 #g/kg\n", + "#calculations\n", + "Ma=m*Ws/(ms*mw)\n", + "#results\n", + "print '%s %d %s' %(\"Molecular weight of solute =\",Ma,\"g/mol \")\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Molecular weight of solute = 100 g/mol \n" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 8 - pg 311" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the molality of the solution\n", + "#Initialization of variables\n", + "dT=0.23 #C\n", + "Kb=1.86 #deg/mol/kg\n", + "#calculations\n", + "m=dT/Kb\n", + "#results\n", + "print '%s %.2f %s' %(\"molality of solution =\",m,\"m\")\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "molality of solution = 0.12 m\n" + ] + } + ], + "prompt_number": 9 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 9 - pg 313" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#calculate the Osmotic Pressure\n", + "#Initialization of variables\n", + "p=0.1 #m\n", + "T=30+273.2 #K\n", + "R=0.08206 #lt atm /deg/mol\n", + "P1=1 #atm\n", + "#calculations\n", + "w=1000/p\n", + "V=w/1000.\n", + "dP=R*T/V\n", + "P=dP+P1\n", + "#results\n", + "print '%s %.2f %s' %(\"Osmotic Pressure =\",P,\" atm \")\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Osmotic Pressure = 3.49 atm \n" + ] + } + ], + "prompt_number": 10 + } + ], + "metadata": {} + } + ] +} \ No newline at end of file -- cgit