From 83c1bfceb1b681b4bb7253b47491be2d8b2014a1 Mon Sep 17 00:00:00 2001
From: debashisdeb
Date: Fri, 20 Jun 2014 15:42:42 +0530
Subject: removing problem statements

---
 .../CH20.ipynb                                              | 13 -------------
 1 file changed, 13 deletions(-)

(limited to 'Materials_science_and_engineering_an_introduction/CH20.ipynb')

diff --git a/Materials_science_and_engineering_an_introduction/CH20.ipynb b/Materials_science_and_engineering_an_introduction/CH20.ipynb
index c410a6ac..b3d2e8d5 100644
--- a/Materials_science_and_engineering_an_introduction/CH20.ipynb
+++ b/Materials_science_and_engineering_an_introduction/CH20.ipynb
@@ -27,9 +27,7 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "# Calculation of saturation magnetisation and flux density for Nickel\n",
       "\n",
-      "#Given\n",
       "b_m=9.27*10**-24   #ampere*m**2  (Bohr Magneton)\n",
       "Na=6.023*10**23    #atoms/mol  (Avogadro's No.)\n",
       "d=8.9*10**6        #g/m**3   (density)\n",
@@ -37,13 +35,9 @@
       "A=58.71             #g/mol  (Atomic weigth of Nickel)\n",
       "N=d*Na/A            #No. of atoms per cubic meter\n",
       "\n",
-      "#Calculation\n",
-      "# M is saturation magnetisation\n",
       "M=0.6*b_m*N  #0.6= Bohr Magneton/atom\n",
-      "#B = Saturation Flux Density\n",
       "B=uo*M\n",
       "\n",
-      "#Result\n",
       "print\"Saturation Magnetisation is \",M,\"A/m\"\n",
       "print\"Saturation Flux Density is \",round(B,2),\"Tesla\"\n"
      ],
@@ -73,14 +67,11 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "# Calculation of saturation magnetisation of Fe3O4\n",
       "\n",
-      "#Given\n",
       "a=0.839*10**-9   #a is edge length in m\n",
       "b_m=9.27*10**-24 #ampere*m**2  (Bohr Magneton)\n",
       "nb=8*4           #8 is no. of Fe++ ions per unit cell\n",
       "                 #4 is Bohr magnetons per Fe++ ion\n",
-      "#Calculation\n",
       "M=nb*b_m/a**3  #M is Saturation magnetisation\n",
       "\n",
       "print\"Saturation Magnetisation is \",round(M,0),\"A/m\"\n",
@@ -111,21 +102,17 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "#Design Example 20.1: Designing a cubic mixed-ferrite magnetic material\n",
       "\n",
-      "#Given\n",
       "Ms_Fe=5.25*10**5   #Required saturation Magnetisation\n",
       "b_m=9.27*10**-24   #ampere*m**2  (Bohr Magneton)\n",
       "a=0.839*10**-9     #a is edge length in m\n",
       "M=5*10**5          #From previous question result\n",
       "\n",
-      "#Calculation\n",
       "nb=Ms_Fe*a**3/b_m\n",
       "i=8             # No of Divalent ions per unit cell\n",
       "j=4             #4 is Bohr magnetons per Mn++ ion\n",
       "n=nb/(i)-j \n",
       "         \n",
-      "#Result\n",
       "print\"Replacing percent of Fe++ with Mn++ would produce the required saturation magnetisation\",round(n*100,2)\n",
       "\n"
      ],
-- 
cgit