From 64d949698432e05f2a372d9edc859c5b9df1f438 Mon Sep 17 00:00:00 2001 From: kinitrupti Date: Fri, 12 May 2017 18:40:35 +0530 Subject: Revised list of TBCs --- Materials_Science/Chapter08.ipynb | 179 -------------------------------------- 1 file changed, 179 deletions(-) delete mode 100755 Materials_Science/Chapter08.ipynb (limited to 'Materials_Science/Chapter08.ipynb') diff --git a/Materials_Science/Chapter08.ipynb b/Materials_Science/Chapter08.ipynb deleted file mode 100755 index 7ab3ee40..00000000 --- a/Materials_Science/Chapter08.ipynb +++ /dev/null @@ -1,179 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:34ae042b330defbf3a9166ffcdabea3a9847c3ed545aa16f3851917a2138bfe6" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter08:Deformation of Metals" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex8.1:pg-175" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# Example 8.1: critical resolved shear stress of silver\n", - " \n", - "\n", - "Ts=15;#tensile stress in Mpa\n", - "d=[1,1,0];\n", - "d1=[1,1,1];\n", - "csda=((d[0]*d1[0])+(d[1]*d1[1])+(d[2]*d1[2]))/((math.sqrt(d[0]**2+d[1]**2+d[2]**2))*math.sqrt(d1[0]**2+d1[1]**2+d1[2]**2));#angle degree\n", - "d2=[0,1,1];\n", - "csdb=((d[0]*d2[0])+(d[1]*d2[1])+(d[2]*d2[2]))/((math.sqrt(d[0]**2+d[1]**2+d[2]**2))*math.sqrt(d2[0]**2+d2[1]**2+d2[2]**2));#angle degree\n", - "t=Ts*csda*csdb;#critical resolved shear stress in MPa\n", - "print round(t,2),\"= critical resolved shear stress in MPa\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "6.12 = critical resolved shear stress in MPa\n" - ] - } - ], - "prompt_number": 11 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex8.2:pg-186" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# Example 8.2: yield strength of material\n", - " \n", - "import numpy.linalg as lin\n", - "import math\n", - "ys1=115;# yeild strength in MN/mm**2\n", - "ys2=215;# yeild strength in MN/mm**2\n", - "d1=0.04;#diamtere in mm\n", - "d2=0.01;#diamtere in mm\n", - "A=numpy.array([[2 ,10], [1 ,10]]);\n", - "B=numpy.array([230,215]);\n", - "x=lin.solve(A,B)\n", - "si=x[0];# in MN/mm**2\n", - "k=x[1];#\n", - "d3=0.016;#in mm\n", - "sy= si +(k/math.sqrt(d3));#yeild strength for a grain size in MN/mm**2\n", - "print round(sy,2),\"=yeild strength for a grain size in MN/mm**2\"\n", - "\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "173.11 =yeild strength for a grain size in MN/mm**2\n" - ] - } - ], - "prompt_number": 7 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex8.3:pg-186" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "# Example 8.3: yield strength of material\n", - "import numpy.linalg as lin\n", - "import math\n", - "ys1=120;# yeild strength in MN/mm**2\n", - "ys2=220;# yeild strength in MN/mm**2\n", - "d1=0.04;#diamtere in mm\n", - "d2=0.01;#diamtere in mm\n", - "A=numpy.array([[2 ,10], [1 ,10]]);\n", - "B=numpy.array([240,220]);\n", - "x=lin.solve(A,B)\n", - "si=x[0];# in MN/mm**2\n", - "k=x[1];#\n", - "d3=0.025;#in mm\n", - "sy= si +(k/math.sqrt(d3));#yeild strength for a grain size in MN/mm**2\n", - "print round(sy,2),\"= yeild strength for a grain size in MN/mm**2\"\n", - "\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "146.49 = yeild strength for a grain size in MN/mm**2\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex18.4:pg-193" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#Example 8.4 : grain diameter\n", - "import math \n", - "\n", - "#given data :\n", - "N=9; # ASTM number\n", - "m=8*2**N; # no. of grains [er square millimetre\n", - "grain=1/math.sqrt(m);\n", - "print round(grain,4),\"=the grain diameter(mm) \"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "0.0156 =the grain diameter(mm) \n" - ] - } - ], - "prompt_number": 2 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit