From 92cca121f959c6616e3da431c1e2d23c4fa5e886 Mon Sep 17 00:00:00 2001
From: hardythe1
Date: Tue, 7 Apr 2015 15:58:05 +0530
Subject: added books

---
 Fundamentals_Of_Thermodynamics/Chapter16.ipynb | 128 +++++++++++++++++++++++++
 1 file changed, 128 insertions(+)
 create mode 100755 Fundamentals_Of_Thermodynamics/Chapter16.ipynb

(limited to 'Fundamentals_Of_Thermodynamics/Chapter16.ipynb')

diff --git a/Fundamentals_Of_Thermodynamics/Chapter16.ipynb b/Fundamentals_Of_Thermodynamics/Chapter16.ipynb
new file mode 100755
index 00000000..6a07737d
--- /dev/null
+++ b/Fundamentals_Of_Thermodynamics/Chapter16.ipynb
@@ -0,0 +1,128 @@
+{
+ "metadata": {
+  "name": "",
+  "signature": "sha256:7c7e50fa2880e870c4aa1630bafd7d049a3cb3c4e646a0d88068a55be4a3d00f"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+  {
+   "cells": [
+    {
+     "cell_type": "heading",
+     "level": 1,
+     "metadata": {},
+     "source": [
+      "Chapter 16:INTRODUCTION TO PHASE AND CHEMICAL EQUILIBRIUM"
+     ]
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex16.2:PG-681"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#ques2\n",
+      "#to determine change in gibbs free energy\n",
+      "\n",
+      "#1-H2\n",
+      "#2-O2\n",
+      "#3-H2O\n",
+      "\n",
+      "#at T=298 K\n",
+      "T1=298.0;#K\n",
+      "Hf1=0;#Enthalpy of formation of H2 at 298 K\n",
+      "Hf2=0;#Enthalpy of formation of O2 at 298 K\n",
+      "Hf3=-241826;#enthalpy of formation of H2O at 298 K in kJ\n",
+      "dH=2*Hf1+Hf2-2*Hf3;#Change in enthalpy in kJ\n",
+      "Sf1=130.678;#Entropy of H2 at 298 K n kJ/K\n",
+      "Sf2=205.148;#Entropy of O2 at 298 K in kJ/K\n",
+      "Sf3=188.834;#entropy of H2O at 298 K in kJ/K\n",
+      "dS=2*Sf1+Sf2-2*Sf3;#Change in entropy in kJ/K\n",
+      "dG1=dH-T1*dS;#change n gibbs free energy in kJ\n",
+      "print\" Change in gibbs free energy at\",T1,\"kelvin is\",round(dG1),\"kJ \"\n",
+      "#at T=2000 K\n",
+      "T2=2000.0;#K\n",
+      "Hf1=52942-0;#Enthalpy of formation of H2 at 2000 K\n",
+      "Hf2=59176-0;#Enthalpy of formation of O2 at 2000 K\n",
+      "Hf3=-241826+72788;#enthalpy of formation of H2O at 2000 K in kJ\n",
+      "dH=2*Hf1+Hf2-2*Hf3;#Change in enthalpy in kJ\n",
+      "Sf1=188.419;#Entropy of H2 at 2000 K n kJ/K\n",
+      "Sf2=268.748;#Entropy of O2 at 2000 K in kJ/K\n",
+      "Sf3=264.769;#entropy of H2O at 2000 K in kJ/K\n",
+      "dS=2*Sf1+Sf2-2*Sf3;#Change in entropy in kJ/K\n",
+      "dG2=dH-(T2*dS);#change n gibbs free energy in kJ\n",
+      "print\" Change in gibbs free energy at\",T2,\"kelvin is\",round(dG2),\" kJ \""
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Change in gibbs free energy at 298.0 kelvin is 457179.0 kJ \n",
+        " Change in gibbs free energy at 2000.0 kelvin is 271040.0  kJ \n"
+       ]
+      }
+     ],
+     "prompt_number": 21
+    },
+    {
+     "cell_type": "heading",
+     "level": 2,
+     "metadata": {},
+     "source": [
+      "Ex16.3:PG-683"
+     ]
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [
+      "#ques3\n",
+      "#calculating equilibrium constant \n",
+      "\n",
+      "dG1=-457.166;#change in gibbs free energy at temp 298 K from example2 in kJ\n",
+      "dG2=-271.040;#change in gibbs free energy at temp 2000 K from example2 n kJ\n",
+      "T1=298;#K\n",
+      "T2=2000;#K\n",
+      "R=8.3145;#gas constant\n",
+      "K1=dG1*1000/(R*T1);\n",
+      "K2=dG2*1000/(R*T2);\n",
+      "print\" Equilibrium constant at \",T1,\"K = \",round(K1,2)\n",
+      "print\" Equilibrium constant at \",T2,\"K = \",round(K2,3)"
+     ],
+     "language": "python",
+     "metadata": {},
+     "outputs": [
+      {
+       "output_type": "stream",
+       "stream": "stdout",
+       "text": [
+        " Equilibrium constant at  298 K =  -184.51\n",
+        " Equilibrium constant at  2000 K =  -16.299\n"
+       ]
+      }
+     ],
+     "prompt_number": 6
+    },
+    {
+     "cell_type": "code",
+     "collapsed": false,
+     "input": [],
+     "language": "python",
+     "metadata": {},
+     "outputs": []
+    }
+   ],
+   "metadata": {}
+  }
+ ]
+}
\ No newline at end of file
-- 
cgit