From 41f1f72e9502f5c3de6ca16b303803dfcf1df594 Mon Sep 17 00:00:00 2001 From: Thomas Stephen Lee Date: Fri, 4 Sep 2015 22:04:10 +0530 Subject: add/remove/update books --- Fundamentals_Of_Thermodynamics/Chapter15.ipynb | 248 ------------------------- 1 file changed, 248 deletions(-) delete mode 100755 Fundamentals_Of_Thermodynamics/Chapter15.ipynb (limited to 'Fundamentals_Of_Thermodynamics/Chapter15.ipynb') diff --git a/Fundamentals_Of_Thermodynamics/Chapter15.ipynb b/Fundamentals_Of_Thermodynamics/Chapter15.ipynb deleted file mode 100755 index 18f2c842..00000000 --- a/Fundamentals_Of_Thermodynamics/Chapter15.ipynb +++ /dev/null @@ -1,248 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:49d323999697626f705831867b32f6c520c5287d76ed00656f7259e6db65356e" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "Chapter15:CHEMICAL REACTIONS" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex15.1:Pg-621" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#ques1\n", - "#theoratical air-fuel ratio for combustion of octane\n", - "#combustion equation is\n", - "#C8H18 + 12.5O2 + 12.5(3.76) N2 \u2192 8 CO2 + 9H2O + 47.0N2\n", - "rm=(12.5+47.0)/1;#air fuel ratio on mole basis\n", - "rma=rm*28.97/114.2;#air fuel ratio on mass basis;\n", - "print \"Theoratical air fuel ratio on mass basis is\",round(rma),\"kg air/kg fuel\"\n", - "\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Theoratical air fuel ratio on mass basis is 15.0 kg air/kg fuel\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex15.6:Pg-629" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#ques6\n", - "#determining heat transfer per kilomole of fuel entering combustion chamber\n", - "\n", - "#1-CH4\n", - "#2-CO2\n", - "#3-H2O\n", - "#hf-standard enthalpy of given substance\n", - "hf1=-74.873;#kJ\n", - "hf2=-393.522;#kJ\n", - "hf3=-285.830;#kJ\n", - "Qcv=hf2+2*hf3-hf1;#kJ\n", - "print \"Heat transfer per kilomole of fuel entering combustion chamber is\",round(Qcv,3),\"kJ\"\n", - "#the answers in the book is different as they have not printed the decimals in values" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "Heat transfer per kilomole of fuel entering combustion chamber is -890.309 kJ\n" - ] - } - ], - "prompt_number": 5 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex15.7:Pg-631" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#ques7\n", - "#calculating enthalpy of water at given pressure and temperature\n", - "\n", - "#1.Assuming steam to be an ideal gas with value of Cp\n", - "T1=298.15;#Initial temperature in K\n", - "T2=573.15;#final temperature in K\n", - "T=(T1+T2)/2;#average temperature in K\n", - "Cp=1.79+0.107*T/1000+0.586*(T/1000)**2-.20*(T/1000)**3;#specific heat at constant pressure in kj/kg.K\n", - "M=18.015;#mass in kg\n", - "dh=M*Cp*(T2-T1);#enthalpy change in kJ/kmol\n", - "ho=-241.826;#enthalpy at standard temperature and pressure in kJ/mol\n", - "htp1=ho+dh/1000;#enthalpy at given temp and pressure in kJ/kmol\n", - "print \" 1. Enthalpy of water at given pressure and temperature using value of Cp =\",round(htp1,3),\"kJ/kmol\"\n", - "\n", - "#2..Assuming steam to be an ideal gas with value for dh\n", - "dh=9359;#enthalpy change from table A.9 in kJ/mol\n", - "htp2=ho+dh/1000;#enthalpy at given temp and pressure in kJ/kmol\n", - "print \" 2. Enthalpy of water at given pressure and temperature assuming value od dh =\",round(htp2,3),\"kJ/kmol \"\n", - "\n", - "#3. Using steam table\n", - "dh=M*(2977.5-2547.2);#enthalpy change for gases in kJ/mol\n", - "htp3g=dh/1000+ho;\n", - "dh=M*(2977.5-104.9);#enthalpy change for liquid in kJ/mol\n", - "hl=-285.830;#standard enthalpy for liquid in kJ/kmol\n", - "htp31=hl+dh/1000.0;#enthalpy at given temp and pressure in kJ/kmol\n", - "print \" 3.(i) enthalpy at given temp and pressure in kJ/kmol in terms of liquid =\",round(htp31,3),\"kJ/kmol \"\n", - "print \" 3.(ii) enthalpy at given temp and pressure in kJ/kmol in terms of liquid =\",round(htp3g,3),\"kJ/kmol \"\n", - "#4.using generalised charts\n", - "#htp=ho-(h2*-h2)+(h2*-h1*)+(h1*-h1);\n", - "#h2*-h2=Z*R*Tc,\n", - "#h2*-h1*=9539 kJ/mol, from part 2\n", - "#h1*-h1=0 ,as ideal gas \n", - "Z=0.21;#from chart\n", - "R=8.3145;#gas constant in SI units\n", - "Tc=647.3;#critical temperature in K\n", - "htp4=ho+9539/1000-Z*R*Tc/1000;#enthalpy at given temp and pressure in kJ/kmol\n", - "print \" 4. enthalpy at given temp and pressure in kJ/kmol using compressibility chart = \",round(htp4,3),\"kJ/kmol\"\n", - "#the answers in book are different as they have not printed the decimals in values" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " 1. Enthalpy of water at given pressure and temperature using value of Cp = -232.258 kJ/kmol\n", - " 2. Enthalpy of water at given pressure and temperature assuming value od dh = -232.826 kJ/kmol \n", - " 3.(i) enthalpy at given temp and pressure in kJ/kmol in terms of liquid = -234.08 kJ/kmol \n", - " 3.(ii) enthalpy at given temp and pressure in kJ/kmol in terms of liquid = -234.074 kJ/kmol \n", - " 4. enthalpy at given temp and pressure in kJ/kmol using compressibility chart = -233.956 kJ/kmol\n" - ] - } - ], - "prompt_number": 12 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex15.15:Pg-649" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#ques15\n", - "#calculatng reversible elecromotive force \n", - "\n", - "#1-H2O\n", - "#2-H2\n", - "#3-O2\n", - "#hf-standard enthalpy \n", - "#sf-standard entropy\n", - "hf1=-285.830;#kJ\n", - "hf2=0;#kJ\n", - "hf3=0;#kJ\n", - "sf1=69.950;#kJ/K\n", - "sf2=130.678;#kJ/K\n", - "sf3=205.148;#kJ/K\n", - "dH=2*hf1-2*hf2-hf3;#change in enthalpy in kJ\n", - "dS=2*sf1-2*sf2-sf3;#change in entropy in kJ/K\n", - "T=298.15;#temperature in K\n", - "dG=dH-T*dS/1000;#change in gibbs free energy in kJ\n", - "E=-dG*1000/(96485*4);#emf in V\n", - "print\" Reversible electromotive Force =\",round(E,3),\" V\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Reversible electromotive Force = 1.229 V\n" - ] - } - ], - "prompt_number": 15 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Ex15.17:Pg-654" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#ques17\n", - "#efficiency of generator and plant\n", - "\n", - "q=325000*(3398.3-856.0);#heat transferred to H2O/kg fuel in kJ/kg\n", - "qv=26700.0*33250;#higher heating value in kJ/kg\n", - "nst=q/qv*100;#efficiency of steam generator\n", - "w=81000.0*3600;#net work done in kJ/kg\n", - "nth=w/qv*100.0;#thermal efficiency\n", - "print\" Efficiency of generator =\",round(nst,1),\"percent\\n\"\n", - "print\" Thermal Efficiency =\",round(nth,1),\" percent\"\n" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - " Efficiency of generator = 93.1 percent\n", - "\n", - " Thermal Efficiency = 32.8 percent\n" - ] - } - ], - "prompt_number": 20 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit