From 206d0358703aa05d5d7315900fe1d054c2817ddc Mon Sep 17 00:00:00 2001 From: Jovina Dsouza Date: Wed, 18 Jun 2014 12:43:07 +0530 Subject: adding book --- Fundamental_of_Electronics_Devices/Ch3.ipynb | 337 +++++++++++++++++++++++++++ 1 file changed, 337 insertions(+) create mode 100644 Fundamental_of_Electronics_Devices/Ch3.ipynb (limited to 'Fundamental_of_Electronics_Devices/Ch3.ipynb') diff --git a/Fundamental_of_Electronics_Devices/Ch3.ipynb b/Fundamental_of_Electronics_Devices/Ch3.ipynb new file mode 100644 index 00000000..fcc2f572 --- /dev/null +++ b/Fundamental_of_Electronics_Devices/Ch3.ipynb @@ -0,0 +1,337 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter3 : Excess Carriers in Semiconductor" + ] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 3.2 Page No 111" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example 3.2\n", + "#What is Minimum required energy \n", + "\n", + "#given data\n", + "l=6000 #in Angstrum\n", + "h=6.6*10**(-34) #Planks constant\n", + "c=3*10**8 #speed of light in m/s\n", + "e=1.602*10**(-19) #Constant\n", + "\n", + "#calculation\n", + "phi=c*h/(e*l*10**(-10))\n", + "\n", + "#result\n", + "print\"Minimum required energy is\",round(phi,2),\"eV \"\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Minimum required energy is 2.06 eV \n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 3.3 Page No 112" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Exa 3.3\n", + "#calculate Work function of the cathode material\n", + "\n", + "#given data\n", + "Emax=2.5 #maximum energy of emitted electrons in eV \n", + "l=2537.0 #in Angstrum\n", + "\n", + "#Calculation\n", + "EeV=12400.0/l #in eV\n", + "phi=EeV-Emax #in eV\n", + "\n", + "#result\n", + "print \"Work function of the cathode material is \",round(phi,2),\"eV\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Work function of the cathode material is 2.39 eV\n" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 3.4 Page No 115" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example 3.4\n", + "#Find (i)The fraction of each photon energy unit which is converted into heat\",f\n", + "#(ii)Energy converted into heat in ,((2-1.43)/2)*0.009,\"J/s\"\n", + "#(iii)Number of photons per second given off from recombination events \",0.009/(e*2)\n", + "\n", + "#given data\n", + "t=0.46*10**-4 #in centi meters\n", + "hf1=2 #in ev\n", + "hf2=1.43\n", + "Pin=10 #in mW\n", + "alpha=50000 # in per cm\n", + "e=1.6*10**-19 #constant\n", + "Io=0.01 #in mW\n", + "\n", + "import math\n", + "\n", + "#Calculation\n", + "It=Io*math.exp(-alpha*t) #in mW\n", + "Iabs=Io-It\n", + "f=(hf1-hf2)/hf1\n", + "E=f*Iabs\n", + "N=Iabs/(e*hf1)\n", + "\n", + "#result\n", + "print\"(i)Thus power absorbed is \",round(Iabs,3),\"J/s\"\n", + "print\"(ii)Energy converted into heat is\",round(E,4),\"J/s\"\n", + "print\"(iii)Number of photons per second given off from recombination events \",round(N,-14)\n", + "#In book there is calculation mistake in Number of photons." + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "(i)Thus power absorbed is 0.009 J/s\n", + "(ii)Energy converted into heat is 0.0026 J/s\n", + "(iii)Number of photons per second given off from recombination events 2.81e+16\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 3.5 Page No 123" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example 3.5\n", + "#What is Photoconductor gain \n", + "#Electron transit time.\n", + "\n", + "#given data\n", + "L=100 #in uM\n", + "A=10&-7 #in cm**2\n", + "th=10**-6 #in sec\n", + "V=12 #in Volts\n", + "ue=0.13 #in m**2/V-s\n", + "uh=0.05 #in m**2/V-s\n", + "\n", + "#Calculation\n", + "E=V/(L*10**-6) #in V/m\n", + "tn=(L*10**-6)/(ue*E)\n", + "Gain=(1+uh/ue)*(th/tn)\n", + "\n", + "#result\n", + "print\"Electron transit time in sec is \",round(tn,10),\"s\"\n", + "print\"Photoconductor gain is \",Gain" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Electron transit time in sec is 6.4e-09 s\n", + "Photoconductor gain is 216.0\n" + ] + } + ], + "prompt_number": 29 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 3.6 Page No128" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example3.6\n", + "#Calculate Current flowing through diode .\n", + "\n", + "#given datex\n", + "import math\n", + "Io=0.15 #in uA\n", + "V=0.12 #in mVolt\n", + "Vt=26 #in mVolt\n", + "\n", + "#calculation\n", + "I=Io*10**-6*(math.exp(V/(Vt*10**-3))-1) #in A\n", + "\n", + "#result\n", + "print\"Current flowing through diode is \",round(I*10**6,2),\"micra A\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Current flowing through diode is 15.0 micra A\n" + ] + } + ], + "prompt_number": 30 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 3.7 Page No 128" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Exa 3.7\n", + "#Determine the Forward voltage \n", + "\n", + "#given data\n", + "import math\n", + "Io=2.5 #in uA\n", + "I=10 #in mA\n", + "Vt=26 #in mVolt\n", + "n=2 #for silicon\n", + "\n", + "#Calculation\n", + "V=n*Vt*10**-3*math.log((I*10**-3)/(Io*10**-6))\n", + "\n", + "#Result\n", + "print \"Forward voltage is \",round(V,2),\"V\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Forward voltage is 0.43 V\n" + ] + } + ], + "prompt_number": 31 + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 3.8 Page No 128" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example 3.8\n", + "#What is Reverse saturation current density \n", + "\n", + "#given data\n", + "ND=10**21 #in m**-3\n", + "NA=10**22 #in m**-3\n", + "De=3.4*10**-3 #in m**2-s**-1\n", + "Dh=1.2*10**-3 #in m**2-s**-1\n", + "Le=7.1*10**-4 #in meters\n", + "Lh=3.5*10**-4 #in meters\n", + "ni=1.6*10**16 #in m**-3\n", + "e=1.602*10**-19 #constant\n", + "\n", + "#calculation\n", + "IoA=e*ni**2*(Dh/(Lh*ND)+De/(Le*NA))\n", + "\n", + "#Result\n", + "print\"Reverse saturation current density is \",round(IoA*10**6,2),\"uA \"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Reverse saturation current density is 0.16 uA \n" + ] + } + ], + "prompt_number": 33 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +} \ No newline at end of file -- cgit