From 41f1f72e9502f5c3de6ca16b303803dfcf1df594 Mon Sep 17 00:00:00 2001 From: Thomas Stephen Lee Date: Fri, 4 Sep 2015 22:04:10 +0530 Subject: add/remove/update books --- .../Chapter12.ipynb | 287 +++++++++++++++++++++ .../Chapter12.ipynb.bkup | 287 --------------------- 2 files changed, 287 insertions(+), 287 deletions(-) create mode 100755 Engineering_Physics_by_Uma_Mukherji/Chapter12.ipynb delete mode 100755 Engineering_Physics_by_Uma_Mukherji/Chapter12.ipynb.bkup (limited to 'Engineering_Physics_by_Uma_Mukherji') diff --git a/Engineering_Physics_by_Uma_Mukherji/Chapter12.ipynb b/Engineering_Physics_by_Uma_Mukherji/Chapter12.ipynb new file mode 100755 index 00000000..0efc0c8d --- /dev/null +++ b/Engineering_Physics_by_Uma_Mukherji/Chapter12.ipynb @@ -0,0 +1,287 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:0e9faaea32136a2f476b53b6ab2d5d2eb5330fb68ebd80aaad9bbe7ed1328c93" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "12: Radioactivity" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example number 12.1, Page number 351" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#importing modules\n", + "import math\n", + "from __future__ import division\n", + "\n", + "#Variable declaration\n", + "M7Li3=7.018232; #mass of 7li3(amu)\n", + "Malpha=4.003874; #mass of alpha particle(amu)\n", + "Mpr=1.008145; #mass of proton(amu)\n", + "Ey=9.15; #K.E energy of product nucleus\n", + "\n", + "#Calculation\n", + "#xMy -> x-mass no., M-element, y-atomic no.\n", + "#reaction:- 7li3 + 1H1-> 4He2 + 4He2\n", + "deltaM=M7Li3+Mpr-2*Malpha; #mass defect(amu)\n", + "Q=deltaM*931; #mass defect(MeV)\n", + "Ex=2*Ey-Q; #K.E of incident particle(MeV)\n", + "\n", + "#Result\n", + "print \"kinetic energy of incident proton is\",round(Ex,4),\"MeV\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "kinetic energy of incident proton is 0.9564 MeV\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example number 12.2, Page number 351" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#importing modules\n", + "import math\n", + "from __future__ import division\n", + "\n", + "#Variable declaration\n", + "M235U=235; #atomic mass of 235U\n", + "m=10**-3; #mass of fissions(gm)\n", + "N=6.023*10**23; #avagadro number\n", + "Eperfi=200*10**6; #energy per fission(eV)\n", + "T=10**-6; #time(s)\n", + "\n", + "#Calculation\n", + "E=Eperfi*1.6*10**-19; #energy per fission(J)\n", + "A=M235U; \n", + "P=((m*N)/A)*(E/T); #power explosion(Watt)\n", + "\n", + "#Result\n", + "print \"power of explosion is\",P,\"Watt\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "power of explosion is 8.20153191489e+13 Watt\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example number 12.4, Page number 352" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#importing modules\n", + "import math\n", + "from __future__ import division\n", + "\n", + "#Variable declaration\n", + "n=0.4; #efficiency\n", + "N=6.06*10**26; #avagadro number\n", + "Eperfi=200*10**6; #energy per fission(eV)\n", + "P=100*10**6; #electric power(W)\n", + "A=235;\n", + "\n", + "#Calculation\n", + "E=Eperfi*1.6*10**-19; #energy per fission(J)\n", + "T=24*60*60; #time(sec)\n", + "N235=P*T/(E*n); #number of atoms in 235 kg of U235\n", + "m=(A*N235)/N; #mass of 235U consumed/day(kg)\n", + "\n", + "#Result\n", + "print \"mass of 235U consumed/day is\",int(m*10**3),\"g\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "mass of 235U consumed/day is 261 g\n" + ] + } + ], + "prompt_number": 13 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example number 12.5, Page number 352" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#importing modules\n", + "import math\n", + "from __future__ import division\n", + "\n", + "#Variable declaration\n", + "M2H1=2.01474; #mass of M2H1(amu)\n", + "M3H1=3.01700; #mass of M3H1(amu)\n", + "M1n0=1.008986; #mass of M1n0(amu)\n", + "M4He2=4.003880; #mass of M4He2(amu)\n", + "\n", + "#Calculation\n", + "#thermonuclear reaction in hydrogen bomb explosion \n", + "#2H1 + 3H1 -> 4He2 + 1n0\n", + "Mreac=M2H1+M3H1; #mass of reactants(amu)\n", + "Mprod=M4He2+M1n0; #mass of products(amu)\n", + "Q=Mreac-Mprod; #amount of energy released per reaction(J)\n", + "Q=Q*931; #amount of energy released per reaction(MeV)\n", + "\n", + "#Result\n", + "print \"amount of energy released per reaction is\",round(Q,3),\"MeV\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "amount of energy released per reaction is 17.572 MeV\n" + ] + } + ], + "prompt_number": 15 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example number 12.6, Page number 353" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#importing modules\n", + "import math\n", + "from __future__ import division\n", + "\n", + "#Variable declaration\n", + "M7Li3=7.01818; #mass of Li atom(amu)\n", + "M1H1=1.0081; #mass of H atom(amu)\n", + "M1n0=1.009; #mass of neutron(amu)\n", + "\n", + "#Calculation\n", + "BEpernu=(1/7)*((3*M1H1)+(4*M1n0)-M7Li3); #binding energy per nucleon(J)\n", + "BEpernu=BEpernu*931; #binding energy per nucleon(MeV)\n", + "\n", + "#Result\n", + "print \"binding energy per nucleon is\",BEpernu,\"MeV\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "binding energy per nucleon is 5.60196 MeV\n" + ] + } + ], + "prompt_number": 16 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example number 12.7, Page number 353" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#importing modules\n", + "import math\n", + "from __future__ import division\n", + "\n", + "#Variable declaration\n", + "m=10*10**3; #mass of U235(gm)\n", + "N=6.02*10**23; #avagadro number\n", + "Eperfi=200*10**6; #energy per fission(eV)\n", + "A=235;\n", + "\n", + "#Calculation\n", + "E=Eperfi*1.6*10**-19; #energy(J)\n", + "T=24*60*60; #time(s)\n", + "P=((m*N)/A)*(E/T); #power output(Watt)\n", + "\n", + "#Result\n", + "print \"power output is\",round(P/10**9,3),\"*10**9 Watt\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "power output is 9.488 *10**9 Watt\n" + ] + } + ], + "prompt_number": 19 + } + ], + "metadata": {} + } + ] +} \ No newline at end of file diff --git a/Engineering_Physics_by_Uma_Mukherji/Chapter12.ipynb.bkup b/Engineering_Physics_by_Uma_Mukherji/Chapter12.ipynb.bkup deleted file mode 100755 index 0efc0c8d..00000000 --- a/Engineering_Physics_by_Uma_Mukherji/Chapter12.ipynb.bkup +++ /dev/null @@ -1,287 +0,0 @@ -{ - "metadata": { - "name": "", - "signature": "sha256:0e9faaea32136a2f476b53b6ab2d5d2eb5330fb68ebd80aaad9bbe7ed1328c93" - }, - "nbformat": 3, - "nbformat_minor": 0, - "worksheets": [ - { - "cells": [ - { - "cell_type": "heading", - "level": 1, - "metadata": {}, - "source": [ - "12: Radioactivity" - ] - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 12.1, Page number 351" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "M7Li3=7.018232; #mass of 7li3(amu)\n", - "Malpha=4.003874; #mass of alpha particle(amu)\n", - "Mpr=1.008145; #mass of proton(amu)\n", - "Ey=9.15; #K.E energy of product nucleus\n", - "\n", - "#Calculation\n", - "#xMy -> x-mass no., M-element, y-atomic no.\n", - "#reaction:- 7li3 + 1H1-> 4He2 + 4He2\n", - "deltaM=M7Li3+Mpr-2*Malpha; #mass defect(amu)\n", - "Q=deltaM*931; #mass defect(MeV)\n", - "Ex=2*Ey-Q; #K.E of incident particle(MeV)\n", - "\n", - "#Result\n", - "print \"kinetic energy of incident proton is\",round(Ex,4),\"MeV\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "kinetic energy of incident proton is 0.9564 MeV\n" - ] - } - ], - "prompt_number": 2 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 12.2, Page number 351" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "M235U=235; #atomic mass of 235U\n", - "m=10**-3; #mass of fissions(gm)\n", - "N=6.023*10**23; #avagadro number\n", - "Eperfi=200*10**6; #energy per fission(eV)\n", - "T=10**-6; #time(s)\n", - "\n", - "#Calculation\n", - "E=Eperfi*1.6*10**-19; #energy per fission(J)\n", - "A=M235U; \n", - "P=((m*N)/A)*(E/T); #power explosion(Watt)\n", - "\n", - "#Result\n", - "print \"power of explosion is\",P,\"Watt\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "power of explosion is 8.20153191489e+13 Watt\n" - ] - } - ], - "prompt_number": 3 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 12.4, Page number 352" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "n=0.4; #efficiency\n", - "N=6.06*10**26; #avagadro number\n", - "Eperfi=200*10**6; #energy per fission(eV)\n", - "P=100*10**6; #electric power(W)\n", - "A=235;\n", - "\n", - "#Calculation\n", - "E=Eperfi*1.6*10**-19; #energy per fission(J)\n", - "T=24*60*60; #time(sec)\n", - "N235=P*T/(E*n); #number of atoms in 235 kg of U235\n", - "m=(A*N235)/N; #mass of 235U consumed/day(kg)\n", - "\n", - "#Result\n", - "print \"mass of 235U consumed/day is\",int(m*10**3),\"g\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "mass of 235U consumed/day is 261 g\n" - ] - } - ], - "prompt_number": 13 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 12.5, Page number 352" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "M2H1=2.01474; #mass of M2H1(amu)\n", - "M3H1=3.01700; #mass of M3H1(amu)\n", - "M1n0=1.008986; #mass of M1n0(amu)\n", - "M4He2=4.003880; #mass of M4He2(amu)\n", - "\n", - "#Calculation\n", - "#thermonuclear reaction in hydrogen bomb explosion \n", - "#2H1 + 3H1 -> 4He2 + 1n0\n", - "Mreac=M2H1+M3H1; #mass of reactants(amu)\n", - "Mprod=M4He2+M1n0; #mass of products(amu)\n", - "Q=Mreac-Mprod; #amount of energy released per reaction(J)\n", - "Q=Q*931; #amount of energy released per reaction(MeV)\n", - "\n", - "#Result\n", - "print \"amount of energy released per reaction is\",round(Q,3),\"MeV\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "amount of energy released per reaction is 17.572 MeV\n" - ] - } - ], - "prompt_number": 15 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 12.6, Page number 353" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "M7Li3=7.01818; #mass of Li atom(amu)\n", - "M1H1=1.0081; #mass of H atom(amu)\n", - "M1n0=1.009; #mass of neutron(amu)\n", - "\n", - "#Calculation\n", - "BEpernu=(1/7)*((3*M1H1)+(4*M1n0)-M7Li3); #binding energy per nucleon(J)\n", - "BEpernu=BEpernu*931; #binding energy per nucleon(MeV)\n", - "\n", - "#Result\n", - "print \"binding energy per nucleon is\",BEpernu,\"MeV\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "binding energy per nucleon is 5.60196 MeV\n" - ] - } - ], - "prompt_number": 16 - }, - { - "cell_type": "heading", - "level": 2, - "metadata": {}, - "source": [ - "Example number 12.7, Page number 353" - ] - }, - { - "cell_type": "code", - "collapsed": false, - "input": [ - "#importing modules\n", - "import math\n", - "from __future__ import division\n", - "\n", - "#Variable declaration\n", - "m=10*10**3; #mass of U235(gm)\n", - "N=6.02*10**23; #avagadro number\n", - "Eperfi=200*10**6; #energy per fission(eV)\n", - "A=235;\n", - "\n", - "#Calculation\n", - "E=Eperfi*1.6*10**-19; #energy(J)\n", - "T=24*60*60; #time(s)\n", - "P=((m*N)/A)*(E/T); #power output(Watt)\n", - "\n", - "#Result\n", - "print \"power output is\",round(P/10**9,3),\"*10**9 Watt\"" - ], - "language": "python", - "metadata": {}, - "outputs": [ - { - "output_type": "stream", - "stream": "stdout", - "text": [ - "power output is 9.488 *10**9 Watt\n" - ] - } - ], - "prompt_number": 19 - } - ], - "metadata": {} - } - ] -} \ No newline at end of file -- cgit