From 5571c8f5bda1334edf8ef9d8c69928d46cc9f163 Mon Sep 17 00:00:00 2001 From: hardythe1 Date: Fri, 25 Jul 2014 13:33:31 +0530 Subject: removing unwanted and adding book --- .../chapter_10.ipynb | 1059 ++++++++++++++++++++ 1 file changed, 1059 insertions(+) create mode 100644 Electrical_Circuit_Theory_And_Technology/chapter_10.ipynb (limited to 'Electrical_Circuit_Theory_And_Technology/chapter_10.ipynb') diff --git a/Electrical_Circuit_Theory_And_Technology/chapter_10.ipynb b/Electrical_Circuit_Theory_And_Technology/chapter_10.ipynb new file mode 100644 index 00000000..443b9513 --- /dev/null +++ b/Electrical_Circuit_Theory_And_Technology/chapter_10.ipynb @@ -0,0 +1,1059 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:c6970542ad51432c833f98812d08f1e8865158ee25a859a74fb18804672e045b" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Chapter 10: Electrical measuring instruments and measurements

" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 1, page no. 116

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "Ia = 0.040;# in Amperes\n", + "I = 50;# in Amperes\n", + "ra = 25;# in ohms\n", + "\n", + "#calculation:\n", + "Is = I - Ia\n", + "V = Ia*ra\n", + "Rs = V/Is\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n value of the shunt to be connected in parallel = \", round((Rs/1E-3),2),\" mohms\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " value of the shunt to be connected in parallel = 20.02 mohms" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 2, page no. 116

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "V = 100;# in volts\n", + "I = 0.008;# in Amperes\n", + "ra = 10;# in ohms\n", + "\n", + "#calculation:\n", + "Rm = (V/I) - ra\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n value of the multiplier to be connected in series = \", (Rm/1E3),\" kohms\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " value of the multiplier to be connected in series = 12.49 kohms" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 3, page no. 119

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "fsd = 200;# in volts\n", + "R1 = 250;# in ohms\n", + "R2 = 2E6;# in ohms\n", + "sensitivity = 10000;# in ohms/V\n", + "V = 100; # in volts\n", + "\n", + "#calculation:\n", + "Rv = sensitivity*fsd\n", + "Iv = V/Rv\n", + "Pv = V*Iv\n", + "I1 = V/R1\n", + "P1 = V*I1\n", + "I2 = V/R2\n", + "P2 = V*I2\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)the power dissipated by the voltmeter = \", (Pv/1E-3),\" mW\\n\"\n", + "print \"\\n (b)the power dissipated by resistor 250 ohm = \", P1,\" W\\n\"\n", + "print \"\\n (c)the power dissipated by resistor 2 Mohm = \", (P2/1E-3),\" mW\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)the power dissipated by the voltmeter = 5.0 mW\n", + "\n", + "\n", + " (b)the power dissipated by resistor 250 ohm = 40.0 W\n", + "\n", + "\n", + " (c)the power dissipated by resistor 2 Mohm = 5.0 mW" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 4, page no. 119

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "V = 10;# in volts\n", + "fsd = 0.1;# in Amperes\n", + "ra = 50;# in ohms\n", + "R = 500;# in ohms\n", + "\n", + "#calculation:\n", + "Ie = V/R\n", + "Ia = V/(R + ra)\n", + "Pa = Ia*Ia*ra\n", + "PR = Ia*Ia*R\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)expected ammeter reading = \", (Ie/1E-3),\" mA\\n\"\n", + "print \"\\n (b)Actual ammeter reading = \",round((Ia/1E-3),2),\" mA\\n\"\n", + "print \"\\n (c)Power dissipated in the ammeter = \",round((Pa/1E-3),2),\" mW\\n\"\n", + "print \"\\n (d)Power dissipated in the load resistor = \", round((PR/1E-3),2),\" mW\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)expected ammeter reading = 20.0 mA\n", + "\n", + "\n", + " (b)Actual ammeter reading = 18.18 mA\n", + "\n", + "\n", + " (c)Power dissipated in the ammeter = 16.53 mW\n", + "\n", + "\n", + " (d)Power dissipated in the load resistor = 165.29 mW" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 5, page no. 120

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "fsd = 100;# in volts\n", + "R1 = 40E3;# in ohms\n", + "R2 = 60E3;# in ohms\n", + "sensitivity = 1600;# in ohms/V\n", + "\n", + "#calculation:\n", + "V1 = (R1/(R1 + R2))*fsd\n", + "Rv = fsd*sensitivity\n", + "Rep = R1*Rv/(R1 + Rv)\n", + "V1n = (Rep/(Rep + R2))*fsd\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)the value of voltage V1 with the voltmeter6 not connected = \", V1,\" V\\n\"\n", + "print \"\\n (b)the voltage indicated by the voltmeter when connected between A and B = \",round(V1n,2),\" V\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)the value of voltage V1 with the voltmeter6 not connected = 40.0 V\n", + "\n", + "\n", + " (b)the voltage indicated by the voltmeter when connected between A and B = 34.78 V" + ] + } + ], + "prompt_number": 5 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 6, page no. 120

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "I = 20;# in amperes\n", + "R = 2;# in ohms\n", + "Rw = 0.01;# in ohms\n", + "\n", + "#calculation:\n", + "PR = I*I*R\n", + "Rt = R + Rw\n", + "Pw = I*I*Rt\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)the power dissipated in the load = \", PR,\" W\\n\"\n", + "print \"\\n (b)the wattmeter reading. = \",Pw,\" W\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)the power dissipated in the load = 800 W\n", + "\n", + "\n", + " (b)the wattmeter reading. = 804.0 W" + ] + } + ], + "prompt_number": 6 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 8, page no. 122

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "tc = 100E-6;# in s/cm\n", + "Vc = 20;# in V/cm\n", + "w = 5.2;# in cm ( width of one complete cycle )\n", + "h = 3.6; # in cm ( peak-to-peak height of the display )\n", + "\n", + "#calculation:\n", + "T = w*tc\n", + "f = 1/T\n", + "ptpv = h*Vc\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)the periodic time, T = \", (T/1E-3),\" msec\\n\"\n", + "print \"\\n (b)Frequency, f = \",round(f,2),\" Hz\\n\"\n", + "print \"\\n (c)the peak-to-peak voltage = \",ptpv,\" V\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)the periodic time, T = 0.52 msec\n", + "\n", + "\n", + " (b)Frequency, f = 1923.08 Hz\n", + "\n", + "\n", + " (c)the peak-to-peak voltage = 72.0 V" + ] + } + ], + "prompt_number": 7 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 9, page no. 123

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "tc = 50E-3;# in s/cm\n", + "Vc = 0.2;# in V/cm\n", + "w = 3.5;# in cm ( width of one complete cycle )\n", + "h = 3.4; # in cm ( peak-to-peak height of the display )\n", + "\n", + "#calculation:\n", + "T = w*tc\n", + "f = 1/T\n", + "ptpv = h*Vc\n", + "\n", + "#Results \n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)the periodic time, T = \", (T/1E-3),\" msec\\n\"\n", + "print \"\\n (b)Frequency, f = \",round(f,2),\" Hz\\n\"\n", + "print \"\\n (c)the peak-to-peak voltage = \",ptpv,\" V\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)the periodic time, T = 175.0 msec\n", + "\n", + "\n", + " (b)Frequency, f = 5.71 Hz\n", + "\n", + "\n", + " (c)the peak-to-peak voltage = 0.68 V" + ] + } + ], + "prompt_number": 8 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 10, page no. 123

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "tc = 500E-6;# in s/cm\n", + "Vc = 5;# in V/cm\n", + "w = 4;# in cm ( width of one complete cycle )\n", + "h = 5; # in cm ( peak-to-peak height of the display )\n", + "\n", + "#calculation:\n", + "T = w*tc\n", + "f = 1/T\n", + "ptpv = h*Vc\n", + "Amp = ptpv/2\n", + "Vrms = Amp/(2**0.5)\n", + "\n", + "#Results \n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)Frequency, f = \",f,\" Hz\\n\"\n", + "print \"\\n (b)the peak-to-peak voltage = \",ptpv,\" V\\n\"\n", + "print \"\\n (c)Amplitude = \",Amp,\" V\\n\"\n", + "print \"\\n (d)r.m.s voltage = \",round(Vrms,2),\" V\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)Frequency, f = 500.0 Hz\n", + "\n", + "\n", + " (b)the peak-to-peak voltage = 25 V\n", + "\n", + "\n", + " (c)Amplitude = 12.5 V\n", + "\n", + "\n", + " (d)r.m.s voltage = 8.84 V" + ] + } + ], + "prompt_number": 9 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 11, page no. 123

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "\n", + "#initializing the variables:\n", + "tc = 100E-6;# in s/cm\n", + "Vc = 2;# in V/cm\n", + "w = 5;# in cm ( width of one complete cycle for both waveform )\n", + "h1 = 2; # in cm ( peak-to-peak height of the display )\n", + "h2 = 2.5; # in cm ( peak-to-peak height of the display\n", + "\n", + "#calculation:\n", + "T = w*tc\n", + "f = 1/T\n", + "ptpv1 = h1*Vc\n", + "Vrms1 = ptpv1/(2**0.5)\n", + "ptpv2 = h2*Vc\n", + "Vrms2 = ptpv2/(2**0.5)\n", + "phi = 0.5*360/w\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)Frequency, f = \",f,\" Hz\\n\"\n", + "print \"\\n (b1)r.m.s voltage of 1st waveform = \",round(Vrms1,2),\" V\\n\"\n", + "print \"\\n (b2)r.m.s voltage of 2nd waveform = \",round(Vrms2,2),\" V\\n\"\n", + "print \"\\n (c)Phase difference = \",phi,\"deg\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)Frequency, f = 2000.0 Hz\n", + "\n", + "\n", + " (b1)r.m.s voltage of 1st waveform = 2.83 V\n", + "\n", + "\n", + " (b2)r.m.s voltage of 2nd waveform = 3.54 V\n", + "\n", + "\n", + " (c)Phase difference = 36.0 deg" + ] + } + ], + "prompt_number": 11 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 12, page no. 127

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "rP1 = 3;# ratio of two powers\n", + "rP2 = 20;# ratio of two powers\n", + "rP3 = 400;# ratio of two powers\n", + "rP4 = 1/20;# ratio of two powers\n", + "\n", + "#calculation:\n", + "X1 = 10*(1/2.303)*math.log(3)\n", + "X2 = 10*(1/2.303)*math.log(20)\n", + "X3 = 10*(1/2.303)*math.log(400)\n", + "X4 = 10*(1/2.303)*math.log(1/20)\n", + "\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n (a)decibel power ratio for power ratio 3 = \",round(X1,2),\" dB\\n\"\n", + "print \"\\n (b)decibel power ratio for power ratio 20 = \",round(X2,2),\" dB\\n\"\n", + "print \"\\n (c)decibel power ratio for power ratio 400 = \",round(X3,2),\" dB\\n\"\n", + "print \"\\n (d)decibel power ratio for power ratio 1/20 = \",round(X4,2),\" dB\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " (a)decibel power ratio for power ratio 3 = 4.77 dB\n", + "\n", + "\n", + " (b)decibel power ratio for power ratio 20 = 13.01 dB\n", + "\n", + "\n", + " (c)decibel power ratio for power ratio 400 = 26.02 dB\n", + "\n", + "\n", + " (d)decibel power ratio for power ratio 1/20 = -13.01 dB" + ] + } + ], + "prompt_number": 12 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 13, page no. 127

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "I2 = 0.020;# in ampere\n", + "I1 = 0.005;# in ampere\n", + "\n", + "#calculation:\n", + "X = 20*math.log10(math.e)*math.log(I2/I1)\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n decibel current ratio = \",round(X,2),\" dB\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " decibel current ratio = 12.04 dB\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 14, page no. 128

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "rP = 0.06;# power ratios rP = P2/P1\n", + "\n", + "#calculation:\n", + "X = 10*math.log10(math.e)*math.log(rP)\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n decibel Power ratios = \",round(X,2),\" dB\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " decibel Power ratios = -12.22 dB\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 15, page no. 128

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "X = 14;# decibal power ratio in dB\n", + "P1 = 0.008;# in Watt\n", + "\n", + "#calculation:\n", + "rP = 10**(X/10)\n", + "P2 = rP*P1\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n output power P2 = \",round(P2,2),\" W\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " output power P2 = 0.2 W" + ] + } + ], + "prompt_number": 15 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 16, page no. 128

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "X = 27;# Voltage gain in decibels\n", + "V2 = 4;# output voltage in Volts\n", + "\n", + "#calculation:\n", + "V1 = V2/(10**(27/20))\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n input Voltage V1 = \",round(V1,2),\" V\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " input Voltage V1 = 0.18 V" + ] + } + ], + "prompt_number": 16 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 17, page no. 129

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "R2 = 100;# in ohms\n", + "R3 = 400;# in ohms\n", + "R4 = 10;# in ohms\n", + "\n", + "#calculation:\n", + "R1 = R2*R3/R4\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n unknown resistance, R1 = \",R1,\" Ohms\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " unknown resistance, R1 = 4000.0 Ohms" + ] + } + ], + "prompt_number": 17 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 18, page no. 130

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "E1 = 1.0186;# in Volts\n", + "l1 = 0.400;# in m\n", + "l2 = 0.650;# in m\n", + "\n", + "#calculation:\n", + "E2 = (l2/l1)*E1\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n the e.m.f. of a dry cell = \",round(E2,2),\" Volts\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " the e.m.f. of a dry cell = 1.66 Volts" + ] + } + ], + "prompt_number": 18 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 19, page no. 132

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "I = 0.0025;# in Amperes\n", + "R = 5000;# in ohms\n", + "e1 = 0.4;# in %\n", + "e2 = 0.5;# in %\n", + "\n", + "#calculation:\n", + "V = I*R\n", + "em = e1 + e2\n", + "Ve = em*V/100\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n voltage V = \",V,\"V(+-)\",Ve,\"V\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " voltage V = 12.5 V(+-) 0.1125 V" + ] + } + ], + "prompt_number": 19 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 20, page no. 132

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "I = 6.25;# in Amperes\n", + "Im = 10;# max in Amperes\n", + "V = 36.5;# in volts\n", + "Vm = 50;# max in volts\n", + "e = 2;# in %\n", + "\n", + "#calculation:\n", + "R = V/I\n", + "Ve = e*Vm/100 \n", + "Ve1 = Ve*100/V# in %\n", + "Ie = e*Im/100\n", + "Ie1 = Ie*100/I# in %\n", + "em = Ve1 + Ie1\n", + "Re = em*R/100\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n Resistance R = \",R,\" ohms(+-)\",Re,\" ohms\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " Resistance R = 5.84 ohms(+-) 0.34688 ohms" + ] + } + ], + "prompt_number": 20 + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "

Example 21, page no. 133

" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "from __future__ import division\n", + "import math\n", + "#initializing the variables:\n", + "R1 = 1000;# in ohms\n", + "R2 = 100;# in ohms\n", + "R3 = 432.5;# in ohms\n", + "e1 = 1;# in %\n", + "e2 = 0.5;# in %\n", + "e3 = 0.2;# in %\n", + "\n", + "#calculation:\n", + "Rx = R2*R3/R1\n", + "em = e1 + e2 + e3\n", + "Re = em*Rx/100\n", + "\n", + "#Results\n", + "print \"\\n\\n Result \\n\\n\"\n", + "print \"\\n Resistance R = \",Rx,\" ohms(+-)\",Re,\" ohms\\n\"" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + "\n", + " Result \n", + "\n", + "\n", + "\n", + " Resistance R = 43.25 ohms(+-) 0.73525 ohms" + ] + } + ], + "prompt_number": 21 + } + ], + "metadata": {} + } + ] +} \ No newline at end of file -- cgit