From 1c1ea29e3e213559fef5f928df109b7d17c21f24 Mon Sep 17 00:00:00 2001
From: hardythe1
Date: Fri, 25 Jul 2014 13:33:31 +0530
Subject: removing unwanted and adding book
---
.../chapter_09-checkpoint.ipynb | 759 ---------------------
1 file changed, 759 deletions(-)
delete mode 100755 Electrical_Circuit_Theory_And_Technology/chapter_09-checkpoint.ipynb
(limited to 'Electrical_Circuit_Theory_And_Technology/chapter_09-checkpoint.ipynb')
diff --git a/Electrical_Circuit_Theory_And_Technology/chapter_09-checkpoint.ipynb b/Electrical_Circuit_Theory_And_Technology/chapter_09-checkpoint.ipynb
deleted file mode 100755
index 02f3e6f4..00000000
--- a/Electrical_Circuit_Theory_And_Technology/chapter_09-checkpoint.ipynb
+++ /dev/null
@@ -1,759 +0,0 @@
-{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Chapter 9: Electromagnetic induction
"
- ]
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 1, page no. 102
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine the current flowing in the conductor when \n",
- "#(a) its ends are open-circuited, \n",
- "#(b) its ends are connected to a load of 20 ohm resistance.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "l = 0.3;# in m\n",
- "v = 4;# in m/s\n",
- "B = 1.25;# in Tesla\n",
- "R = 20;# in ohms\n",
- "u0 = 4*math.pi*1E-7;\n",
- "\n",
- "#calculation:\n",
- "E = B*l*v\n",
- "I2 = E/R\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n (a)If the ends of the conductor are open circuited \"\n",
- "print \"no current will flow even though \",E,\" V has been induced.\\n\"\n",
- "print \"\\n (b)From Ohms law, I = \",I2,\" Ampere\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " (a)If the ends of the conductor are open circuited no current will flow even though 1.5 V has been induced.\n",
- "\n",
- "\n",
- " (b)From Ohms law, I = 0.075 Ampere"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 2, page no. 103
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#At what velocity must a conductor 75 mm long cut a magnetic field of flux density 0.6 T\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "l = 0.075;# in m\n",
- "E = 9;# in Volts\n",
- "B = 0.6;# in Tesla\n",
- "R = 20;# in ohms\n",
- "u0 = 4*math.pi*1E-7;\n",
- "\n",
- "#calculation:\n",
- "v = E/(B*l)\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n velocity v = \",v,\" m/s\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " velocity v = 200.0 m/s"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 3, page no. 103
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#find the magnitude of the induced e.m.f. in each case.\n",
- "from __future__ import division\n",
- "import math\n",
- "\n",
- "#initializing the variables:\n",
- "l = 0.02;# in m\n",
- "b = 0.02;# in m\n",
- "v = 15;# in m/s\n",
- "R = 20;# in ohms\n",
- "Phi = 5E-6;# in Wb\n",
- "u0 = 4*math.pi*1E-7;\n",
- "a1 = 90;# in degrees\n",
- "a2 = 60;# in degrees\n",
- "a3 = 30;# in degrees\n",
- "\n",
- "#calculation:\n",
- "A = l*b\n",
- "B = Phi/A\n",
- "E90 = B*l*v*math.sin(a1*math.pi/180)\n",
- "E60 = B*l*v*math.sin(a2*math.pi/180)\n",
- "E30 = B*l*v*math.sin(a3*math.pi/180)\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n Induced e.m.f. at angles 90\u00b0, 60\u00b0, 30\u00b0 are \",(E90/1E-3),\" V, \",round((E60/1E-3),2),\" V, \"\n",
- "print \"(E30/1E-3),\" V respectively\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " Induced e.m.f. at angles 90\u00c2\u00b0, 60\u00c2\u00b0, 30\u00c2\u00b0 are 3.75 V, 3.25 V, 1.875 V respectively"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 4, page no. 103
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#determine the e.m.f. induced between its wing tips\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "s = 36;# in m\n",
- "v = 400;# in km/h\n",
- "u0 = 4*math.pi*1E-7;\n",
- "B = 40E-6;# in Tesla\n",
- "\n",
- "#calculation:\n",
- "v0 = v*5/18\n",
- "E = B*s*v0\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n Induced e.m.f. = \",E,\" V\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " Induced e.m.f. = 0.16 V"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 6, page no. 105
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Determine the e.m.f. induced in a coil\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "N = 200;# no. of turns\n",
- "dt = 0.050;# change of time in sec\n",
- "u0 = 4*math.pi*1E-7;\n",
- "dPhi = 0.025;# change of flux in Wb\n",
- "\n",
- "#calculation:\n",
- "E = -1*N*dPhi/dt\n",
- "\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n Induced e.m.f. = \",E,\" V\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " Induced e.m.f. = -100.0 V"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 7, page no. 105
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Find the average e.m.f. induced.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "N = 150;# no. of turns\n",
- "dt = 0.040;# change of time in sec\n",
- "u0 = 4*math.pi*1E-7;\n",
- "dPhi = 800E-6;# change of flux in Wb\n",
- "\n",
- "#calculation:\n",
- "#Since the flux reverses, the flux changes from C400 \u03bcWb to \u0003400 \u03bcWb, a total change of flux of 800 \u03bcWb\n",
- "E = -1*N*dPhi/dt\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n Induced e.m.f. = \",E,\" V\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " Induced e.m.f. = -3.0 V"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 8, page no. 105
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate the e.m.f. induced in a coil\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "L = 12;# in Henry\n",
- "u0 = 4*math.pi*1E-7;\n",
- "dIdt = 4;# change of current with change in time in A/s\n",
- "\n",
- "#calculation:\n",
- "E = -1*L*dIdt\n",
- "\n",
- "\n",
- "#Results\n",
- "print \"\\n\\nResult\\n\\n\"\n",
- "print \"\\n Induced e.m.f. = \",E,\" V\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- "Result\n",
- "\n",
- "\n",
- "\n",
- " Induced e.m.f. = -48 V"
- ]
- }
- ],
- "prompt_number": 7
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 9, page no. 106
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#find inductance of the coil.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "E = 1500;# in Volts\n",
- "dt = 0.008;# Change of time in sec\n",
- "dI = 4;# change of current in A/s\n",
- "\n",
- "#calculation:\n",
- "L = abs(E)*dt/dI\n",
- "\n",
- "#Results\n",
- "print \"\\n\\n Result \\n\\n\"\n",
- "print \"\\n Inductance L= \",L,\" H\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- " Result \n",
- "\n",
- "\n",
- "\n",
- " Inductance L= 3.0 H"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 10, page no. 107
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#How much energy is stored in the magnetic field of the inductor?\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "L = 8;# in Henry\n",
- "I = 3;# in Amperes\n",
- "\n",
- "#calculation:\n",
- "W = L*I*I/2\n",
- "\n",
- "#Results\n",
- "print \"\\n\\n Result \\n\\n\"\n",
- "print \"\\n Energy stored, W = \",W,\" J\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- " Result \n",
- "\n",
- "\n",
- "\n",
- " Energy stored, W = 36.0 J"
- ]
- }
- ],
- "prompt_number": 9
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 11, page no. 107
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate the coil inductance\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "I = 4;# in Amperes\n",
- "N = 800;#turns\n",
- "Phi = 0.005;# in Wb\n",
- "\n",
- "#calculation:\n",
- "L = N*Phi/I\n",
- "\n",
- "#Results\n",
- "print \"\\n\\n Result \\n\\n\"\n",
- "print \"\\n Inductance L = \",L,\" H\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- " Result \n",
- "\n",
- "\n",
- "\n",
- " Inductance L = 1.0 H"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 12, page no. 107
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate (a) the inductance of the coil, \n",
- "#(b) the energy stored in the magnetic field, and \n",
- "#(c) the average e.m.f. induced if the current falls to zero in 150 ms.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "I1 = 3;# in Amperes\n",
- "I2 = 0;# in Amperes\n",
- "dt = 0.150;# in secs\n",
- "N = 1500;#turns\n",
- "Phi = 0.025;# in Wb\n",
- "\n",
- "#calculation:\n",
- "L = N*Phi/I1\n",
- "W = L*I1*I1/2\n",
- "dI = I1 - I2\n",
- "E = -1*L*dI/dt\n",
- "\n",
- "#Results\n",
- "print \"\\n\\n Result \\n\\n\"\n",
- "print \"\\n (a)Inductance L = \",L,\" H\\n\"\n",
- "print \"\\n (b)energy stored W = \",W,\" J\\n\"\n",
- "print \"\\n (c)e.m.f. induced = \",E,\" V\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- " Result \n",
- "\n",
- "\n",
- "\n",
- " (a)Inductance L = 12.5 H\n",
- "\n",
- "\n",
- " (b)energy stored W = 56.25 J\n",
- "\n",
- "\n",
- " (c)e.m.f. induced = -250.0 V"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 13, page no. 108
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate the flux linking the coil and the e.m.f. induced in the coil when the current collapses to zero in 20 ms\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "I1 = 2;# in Amperes\n",
- "I2 = 0;# in Amperes\n",
- "dt = 0.020;# in secs\n",
- "N = 750;#turns\n",
- "L = 3;# in Henry\n",
- "\n",
- "#calculation:\n",
- "Phi = L*I1/N\n",
- "dI = I1 - I2\n",
- "E = -1*L*dI/dt\n",
- "\n",
- "#Results\n",
- "print \"\\n\\n Result \\n\\n\"\n",
- "print \"\\n (a)Flux = \",Phi,\" Wb\\n\"\n",
- "print \"\\n (b)e.m.f. induced = \",E,\" V\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- " Result \n",
- "\n",
- "\n",
- "\n",
- " (a)Flux = 0.008 Wb\n",
- "\n",
- "\n",
- " (b)e.m.f. induced = -300.0 V"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 14, page no. 108
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate the mutual inductance between two coils\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "dI1dt = 200;# change of current with change in time in A/s\n",
- "N = 2;# no. of coils\n",
- "E2 = 1.5;# in Volts\n",
- "\n",
- "#calculation:\n",
- "M = abs(E2)/dI1dt\n",
- "\n",
- "\n",
- "#Results\n",
- "print \"\\n\\n Result \\n\\n\"\n",
- "print \"\\n mutual inductance, M = \", M,\" H\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- " Result \n",
- "\n",
- "\n",
- "\n",
- " mutual inductance, M = 0.0075 H"
- ]
- }
- ],
- "prompt_number": 13
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 15, page no. 109
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Calculate the steady rate of change of current in one coil to induce an e.m.f. of 0.72 V in the other.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "M = 0.018;# in Henry\n",
- "N = 2;# no. of coils\n",
- "E2 = 0.72;# in Volts\n",
- "\n",
- "#calculation:\n",
- "dI1dt = abs(E2)/M\n",
- "\n",
- "#Results\n",
- "print \"\\n\\n Result \\n\\n\"\n",
- "print \"\\n rate of change of current dI1/dt = \", dI1dt,\" A/s\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- " Result \n",
- "\n",
- "\n",
- "\n",
- " rate of change of current dI1/dt = 40.0 A/s"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "markdown",
- "metadata": {},
- "source": [
- "Example 16, page no. 109
"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#calculate (a) the average induced e.m.f. in the second coil, \n",
- "#(b) the change of flux linked with the second coil if it is wound with 500 turns.\n",
- "from __future__ import division\n",
- "import math\n",
- "#initializing the variables:\n",
- "M = 0.2;# in Henry\n",
- "I1 = 10;# in Amperes\n",
- "I2 = 4;# in Amperes\n",
- "dt = 0.010;# in secs\n",
- "N = 500;# turns\n",
- "\n",
- "#calculation:\n",
- "dI1dt = (I1 -I2)/dt \n",
- "E2 = -1*dI1dt*M\n",
- "dPhi = abs(E2)*dt/N\n",
- "\n",
- "#Results\n",
- "print \"\\n\\n Result \\n\\n\"\n",
- "print \"\\n (a)Induced e.m.f. E2 = \", E2,\" V\\n\"\n",
- "print \"\\n (b)change of flux = \", dPhi,\" Wb\\n\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "\n",
- "\n",
- " Result \n",
- "\n",
- "\n",
- "\n",
- " (a)Induced e.m.f. E2 = -120.0 V\n",
- "\n",
- "\n",
- " (b)change of flux = 0.0024 Wb"
- ]
- }
- ],
- "prompt_number": 15
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file
--
cgit