From d883118364a7a13fa6e139a7dab6fc9a34980a8a Mon Sep 17 00:00:00 2001 From: hardythe1 Date: Wed, 6 Aug 2014 16:41:00 +0530 Subject: adding books --- Chemical_Reaction_Engineering/ch14.ipynb | 232 +++++++++++++++++++++++++++++++ 1 file changed, 232 insertions(+) create mode 100755 Chemical_Reaction_Engineering/ch14.ipynb (limited to 'Chemical_Reaction_Engineering/ch14.ipynb') diff --git a/Chemical_Reaction_Engineering/ch14.ipynb b/Chemical_Reaction_Engineering/ch14.ipynb new file mode 100755 index 00000000..5eb6f664 --- /dev/null +++ b/Chemical_Reaction_Engineering/ch14.ipynb @@ -0,0 +1,232 @@ +{ + "metadata": { + "name": "" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 14 The Tanks-in-Series Model" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.1 pageno : 329" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "#Original and new length(m)\n", + "import math \n", + "\n", + "# Variables\n", + "L1 = 32. # diameter pipe\n", + "L2 = 50. # pipeline length \n", + "sigma1 = 8. # bottles \n", + "\n", + "# Calculations\n", + "# For small deviaqtion from plug flow,sigma_sqr is directly proportional to L\n", + "sigma2 = sigma1*math.sqrt(L2/L1);\n", + "\n", + "# Results\n", + "print \" No of bottles of rose expected is %.f\"%(sigma2)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " No of bottles of rose expected is 10\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.2 pageno : 330" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "sigma1 = 14. # hours\n", + "sigma2 = 10.5; # hours\n", + "L1 = 119. # ohio miles apart\n", + "\n", + "# Calculations\n", + "#spread of curve is directly proportional to sqrt of distance from origin\n", + "L = sigma1**2*L1/(sigma1**2-sigma2**2);\n", + "\n", + "# Results\n", + "print \" The dumping of toxic phenol must have occured within %.f miles upstream of cincinnati\"%(L)\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The dumping of toxic phenol must have occured within 272 miles upstream of cincinnati\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.3 pageno : 332" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "# Variables\n", + "# from figure\n", + "vo = 1.; \n", + "t1 = 1./6;\n", + "t2 = 1.;\n", + "t3 = 11./6;\n", + "w = 1./10;\n", + "\n", + "# Calculations\n", + "A2_by_A1 = 0.5;\n", + "R = A2_by_A1/(1-A2_by_A1);\n", + "#From the location of 1st peak\n", + "V1 = (R+1)*vo*t1;\n", + "#From the time between peaks\n", + "V2 = (R*vo)*((t2-t1)-(t1));\n", + "#From fig 14.3\n", + "N = 1+(2*(t1/w))**2;\n", + "\n", + "# Results\n", + "print \" The reflux ratio is %.f\"%(R)\n", + "print \" The volume of 1st tank is %.3f\"%( V1)\n", + "print \" The volume of 2nd tank is %.3f\"%(V2)\n", + "print \" The number of tanks are %.f \"%(N)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + " The reflux ratio is 1\n", + " The volume of 1st tank is 0.333\n", + " The volume of 2nd tank is 0.667\n", + " The number of tanks are 12 \n" + ] + } + ], + "prompt_number": 4 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Example 14.4 page no :333" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "\n", + "\n", + "%pylab inline\n", + "\n", + "from matplotlib.pyplot import *\n", + "import math \n", + "from numpy import *\n", + "\n", + "# Variables\n", + "# from figure E14.4a\n", + "t2 = 280.\n", + "t1 = 220.\n", + "sigma1_sqr = 100.\n", + "sigma2_sqr = 1000.\n", + "\n", + "# Calculations\n", + "dt = t2-t1;\n", + "dsigma_sqr = sigma2_sqr-sigma1_sqr;\n", + "N = dt**2/dsigma_sqr;\n", + "\n", + "E = zeros(200)\n", + "\n", + "for t in range(200):\n", + " E[t] = ((t**(N-1))*(N**N)*math.exp(-t*N/dt))/((math.factorial(N-1))*(dt**N));\n", + "\n", + "t = zeros(200) \n", + "for i in range(200):\n", + " t[i] = i;\n", + "\n", + "# Results\n", + "plot(t,E)\n", + "xlabel(\"t, s\")\n", + "ylabel(\"E, s**-1\")\n", + "show()\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Populating the interactive namespace from numpy and matplotlib\n" + ] + }, + { + "metadata": {}, + "output_type": "display_data", + "png": 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