From c6f0d6aeb95beaf41e4b679e78bb42c4ffe45a40 Mon Sep 17 00:00:00 2001 From: Jovina Dsouza Date: Tue, 17 Jun 2014 19:17:50 +0530 Subject: adding book --- Basic_Electronics_and_Linear_Circuits/ch2.ipynb | 157 ++++++++++++++++++++++++ 1 file changed, 157 insertions(+) create mode 100644 Basic_Electronics_and_Linear_Circuits/ch2.ipynb (limited to 'Basic_Electronics_and_Linear_Circuits/ch2.ipynb') diff --git a/Basic_Electronics_and_Linear_Circuits/ch2.ipynb b/Basic_Electronics_and_Linear_Circuits/ch2.ipynb new file mode 100644 index 00000000..ea7aa645 --- /dev/null +++ b/Basic_Electronics_and_Linear_Circuits/ch2.ipynb @@ -0,0 +1,157 @@ +{ + "metadata": { + "name": "ch2" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 2:Current and Voltage Source" + ] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 2.1 Page no.39" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example 2.1\n", + "# Obtain Equivalent Current Source Representaion from Given Voltage Source Representation in fig 2.16\n", + "\n", + "#Voltage Source or Thevenin's Representaion (Series Voltage Source & Resistor\n", + "Vs=2 #V open circuit voltage\n", + "Rs=1 #ohm . internal impedence\n", + "#Current Source or Norton's Representaion (Parallel Current Source & Resistor\n", + "Is=Vs/Rs #Ampere, short circuit current\n", + "#result\n", + "print \"The Short Circuit Current Value is \",Is,\"A\"\n", + "print \"The Source Impedence Value is \",Rs,\"ohm\"\n", + "print \"The Current Source & Source Impedance are connected in Parallel.\"" + ], + "language": "python", + "metadata": {}, + "outputs": [] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 2.2 Page no.40" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example 2.2\n", + "# Obtain Equivalent Voltage Source Representaion from Given Current Source Representation\n", + "\n", + "#Current Source or Norton's Representaion (Parallel Current Source & Resistor)\n", + "Is=0.2 #Amperes\n", + "Zs=100 #Ohms\n", + "#Voltage Source or Thevenin's Representaion (Series Voltage Source & Resistor)\n", + "Vs=Is*Zs #Volts\n", + "# Results \n", + "print \"The Open Circuit Voltage is \",Vs,\"V\"\n", + "print \"The Source Impedence Value is \",Zs,\"ohm\"\n", + "print \"The Voltage Source & Source Impedance are connected in Series.\"" + ], + "language": "python", + "metadata": {}, + "outputs": [] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 2.3 Page no.40" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example 2.3\n", + "#Program to Calculate Current in a Branch by Using Current Source Representation \n", + "#Verify the Circuit's Result for its equivalence with Voltage Source Representation\n", + "\n", + "#Given Circuit Data\n", + "Is=1.5*10**(-3) #Amperes ,source current\n", + "Zs=2000 #Ohms, resistance connected to the loads\n", + "Z1=10000 #Ohms , load resistance 1\n", + "Z2=40000 #Ohms load resistance 2\n", + "#Calculation for Current Source Representation\n", + "Zl=Z1*Z2/(Z1+Z2)\n", + "I2=Is*Zs/(Zs+Zl)\n", + "I4I=I2*Z1/(Z1+Z2) #Using Current Divider Rule\n", + "\n", + "#Calculation for Current Source Representation\n", + "Vs=Is*Zs #Open Circuit Volatge\n", + "I=Vs/(Zs+Zl)\n", + "I4V=I*Z1/(Z1+Z2) #Using Current Divider Rule\n", + "# Results \n", + "print \"The Load Current using Current Source Representaion is I4I = \",I4I,\"A\"\n", + "print \"The Load Current using Voltage Source Representaion is I4V = \",I4V,\"A\"\n", + "print \"I4I==I4V so\"\n", + "print \" Both Results are same.\"\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [] + }, + { + "cell_type": "heading", + "level": 3, + "metadata": {}, + "source": [ + "Example 2.4 Page no.45" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Example 2.4\n", + "# Obtain Output Voltage Vo from Given A.C. Equivalent of an Amplifier using a Transistor\n", + "\n", + "#Given Circuit Data\n", + "#Input Side\n", + "Vs=0.01 #V ,dc voltage\n", + "Rs=1000 # ohm, resistance\n", + "#Output Side resistance\n", + "Ro1=20000 #ohm, 20 kOhms\n", + "Ro2=2000 # Ohms\n", + "\n", + "#Calculation\n", + "i=Vs/Rs #Input Current\n", + "Io=100*i #Output Current\n", + "Il=Io*Ro1/(Ro1+Ro2) #Using Current Divider Rule\n", + "Vo=Il*Ro2 #Output Volatge\n", + "\n", + "# Result\n", + "print \"The Output Voltage Vo = \",round(Vo,3),\"V\"" + ], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +} \ No newline at end of file -- cgit