From 0b1a653f0e747217168115df15670d47f67101bb Mon Sep 17 00:00:00 2001 From: Trupti Kini Date: Tue, 4 Oct 2016 23:31:13 +0600 Subject: Added(A)/Deleted(D) following books A f_by_df/README.txt A f_by_df/abhishek_2.ipynb A f_by_df/screenshots/anshul_1.png A f_by_df/screenshots/anshul_2.png A f_by_df/screenshots/array_factor.png A mathematics_by_df/aditya.ipynb A mathematics_by_df/screenshots/anshul.png A mathematics_by_df/screenshots/array_factor.png A mathematics_by_df/screenshots/array_factor_1.png A testing_by_df/README.txt --- f_by_df/README.txt | 10 + f_by_df/abhishek_2.ipynb | 112 +++++++++ f_by_df/screenshots/anshul_1.png | Bin 0 -> 75019 bytes f_by_df/screenshots/anshul_2.png | Bin 0 -> 75019 bytes f_by_df/screenshots/array_factor.png | Bin 0 -> 24790 bytes mathematics_by_df/aditya.ipynb | 279 +++++++++++++++++++++++ mathematics_by_df/screenshots/anshul.png | Bin 0 -> 75019 bytes mathematics_by_df/screenshots/array_factor.png | Bin 0 -> 24790 bytes mathematics_by_df/screenshots/array_factor_1.png | Bin 0 -> 24790 bytes testing_by_df/README.txt | 10 + 10 files changed, 411 insertions(+) create mode 100644 f_by_df/README.txt create mode 100644 f_by_df/abhishek_2.ipynb create mode 100644 f_by_df/screenshots/anshul_1.png create mode 100644 f_by_df/screenshots/anshul_2.png create mode 100644 f_by_df/screenshots/array_factor.png create mode 100644 mathematics_by_df/aditya.ipynb create mode 100644 mathematics_by_df/screenshots/anshul.png create mode 100644 mathematics_by_df/screenshots/array_factor.png create mode 100644 mathematics_by_df/screenshots/array_factor_1.png create mode 100644 testing_by_df/README.txt diff --git a/f_by_df/README.txt b/f_by_df/README.txt new file mode 100644 index 00000000..e0c5014c --- /dev/null +++ b/f_by_df/README.txt @@ -0,0 +1,10 @@ +Contributed By: Jeevan Lal +Course: me +College/Institute/Organization: MPBtech. ECE, 6th SemVNIT Nagpur +Department/Designation: MPBtech. ECE, 6th SemVNIT Nagpur +Book Title: f +Author: df +Publisher: 5 +Year of publication: 2 +Isbn: 3 +Edition: 3 \ No newline at end of file diff --git a/f_by_df/abhishek_2.ipynb b/f_by_df/abhishek_2.ipynb new file mode 100644 index 00000000..3f7271ea --- /dev/null +++ b/f_by_df/abhishek_2.ipynb @@ -0,0 +1,112 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:cda4775b9259e49c042e3120b0a25eb239766f3373696622080f812fe1f53fa9" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "heading", + "level": 1, + "metadata": {}, + "source": [ + "Chapter 01:Introduction" + ] + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex1.1:pg-20" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "# Given Data\n", + "d_r = 13640 # Density of mercury in kg/m^3\n", + "g = 9.79 # Acceleration due to gravity in m/s^2\n", + "z = 562e-03 # Difference in height in m\n", + "z0 = 761e-03 # Reading of barometer in m\n", + "P = (d_r*g*(z+z0))*(0.987/1e05) # Gas Pressure in atm\n", + "\n", + "print \"\\n Example 1.1\\n\"\n", + "print \"\\n Gas Pressure is \",round(P,2),\" atm\"\n", + "#The answers vary due to round off error\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + " Example 1.1\n", + "\n", + "\n", + " Gas Pressure is 1.74 atm\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "heading", + "level": 2, + "metadata": {}, + "source": [ + "Ex1.2:pg-21" + ] + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#Given Data\n", + "d_r = 13.6e03 # Density of mercury in kg/m^3\n", + "g = 9.81 # Acceleration due to gravity in m/s^2\n", + "z = 710e-03 # Steam flow pressure in m\n", + "z0 = 772e-03 # Reading of barometer in m\n", + "P = 1.4e06 # Gauge pressure of applied steam in Pa\n", + "P0 = d_r*g*z0 # Atmospheric pressure in Pa\n", + "Pi = P+P0 # Inlet steam pressure in Pa\n", + "Pc = d_r*g*(z0-z) # Condenser pressure in Pa\n", + "\n", + "print \"\\n Example 1.2\\n\"\n", + "print \"\\n Inlet steam pressure is\",round(Pi/1e6,2),\" MPa\"\n", + "print \"\\n Condenser pressure is\",round(Pc/1e3,2),\" kPa\"\n", + "#The answers vary due to round off error\n", + "\n", + "\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "\n", + " Example 1.2\n", + "\n", + "\n", + " Inlet steam pressure is 1.5 MPa\n", + "\n", + " Condenser pressure is 8.27 kPa\n" + ] + } + ], + "prompt_number": 5 + } + ], + "metadata": {} + } + ] +} \ No newline at end of file diff --git a/f_by_df/screenshots/anshul_1.png b/f_by_df/screenshots/anshul_1.png new file mode 100644 index 00000000..a8cec645 Binary files /dev/null and b/f_by_df/screenshots/anshul_1.png differ diff --git a/f_by_df/screenshots/anshul_2.png b/f_by_df/screenshots/anshul_2.png new file mode 100644 index 00000000..a8cec645 Binary files /dev/null and b/f_by_df/screenshots/anshul_2.png differ diff --git a/f_by_df/screenshots/array_factor.png b/f_by_df/screenshots/array_factor.png new file mode 100644 index 00000000..9e294010 Binary files /dev/null and b/f_by_df/screenshots/array_factor.png differ diff --git a/mathematics_by_df/aditya.ipynb b/mathematics_by_df/aditya.ipynb new file mode 100644 index 00000000..a77ec491 --- /dev/null +++ b/mathematics_by_df/aditya.ipynb @@ -0,0 +1,279 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 5 General Case of Forces in a plane" + ] + }, + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "# Example 5.2 Equations of equilibrium" + ] + }, + { + "cell_type": "code", + "execution_count": 7, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "('The reaction at P is', 5656.85424949238, 'N')\n", + "('The reaction at Q is ', 4000.0, 'N')\n" + ] + } + ], + "source": [ + "import math\n", + "\n", + "#Initialization of Variables\n", + "W=2000 #N\n", + "Lab=2 #m #length of the member from the vertical to the 1st load of 2000 N\n", + "Lac=5 #m #length of the member from the vertical to the 2nd load of 2000 N\n", + "Lpq=3.5 #m\n", + "\n", + "#Calculations\n", + "Rq=((W*Lab)+(W*Lac))/Lpq #N #take moment abt. pt P\n", + "Xp=Rq #N #sum Fx=0\n", + "Yp=2*W #N #sum Fy=0\n", + "Rp=math.sqrt(Xp**2+Yp**2) #N\n", + "\n", + "#Resuts\n", + "print('The reaction at P is' ,Rp ,'N')\n", + "print('The reaction at Q is ',Rq ,'N')" + ] + }, + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "# Example 5.3 Equations of equilibrium" + ] + }, + { + "cell_type": "code", + "execution_count": 6, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "('The reaction at A i.e Ra is ', matrix([[ 120.27406887]]), 'N')\n", + "('The reaction at B i.e Rb is ', matrix([[ 35.13703443]]), 'N')\n", + "('The required tension in the string is ', matrix([[ 40.57275258]]), 'N')\n" + ] + } + ], + "source": [ + "import math,numpy\n", + "#Initilization of vaiables\n", + "W=25 #N # self weight of the ladder\n", + "M=75 #N # weight of the man standing o the ladder\n", + "theta=63.43 #degree # angle which the ladder makes with the horizontal\n", + "alpha=30 #degree # angle made by the string with the horizontal\n", + "Loa=2 #m # spacing between the wall and the ladder\n", + "Lob=4 #m #length from the horizontal to the top of the ladder touching the wall(vertical)\n", + "\n", + "#Calculations\n", + "#Using matrix to solve the simultaneous eqn's 3 & 4\n", + "A=numpy.matrix('2 -4; 1 -0.577')\n", + "B=numpy.matrix('100;100')\n", + "C=numpy.linalg.inv(A)*B\n", + "\n", + "#Results\n", + "print('The reaction at A i.e Ra is ',C[0] ,'N')\n", + "print('The reaction at B i.e Rb is ',C[1] ,'N')\n", + "\n", + "#Calculations\n", + "T=C[1]/math.cos(math.radians(alpha)) #N # from (eqn 1)\n", + "\n", + "#Results\n", + "print('The required tension in the string is ',T, 'N')" + ] + }, + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "# Example 5.4 Equations of Equilibrium" + ] + }, + { + "cell_type": "code", + "execution_count": 4, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "('The reaction at B i.e Rb is ', 25.0, 'N')\n", + "('The horizontal reaction at A i.e Xa is ', 21.650635094610966, 'N')\n", + "('The vertical reaction at A i.e Ya is ', 112.5, 'N')\n" + ] + } + ], + "source": [ + "import math\n", + "#Initilization of variables\n", + "W=100 #N\n", + "theta=60 #degree angle made by the ladder with the horizontal\n", + "alpha=30 #degree angle made by the ladder with the vertical wall\n", + "Lob=4 #m length from the horizontal to the top of the ladder touching the wall(vertical)\n", + "Lcd=2 #m length from the horizontal to the centre of the ladder where the man stands\n", + "\n", + "#Calculations\n", + "Lab=Lob*(1/math.cos(math.radians(alpha))) #m length of the ladder\n", + "Lad=Lcd*math.tan(math.radians(alpha)) #m\n", + "Rb=(W*Lad)/Lab #N take moment at A\n", + "Xa=Rb*math.sin(math.radians(theta)) #N From eq'n 1\n", + "Ya=W+Rb*math.cos(math.radians(theta)) #N From eq'n 2\n", + "\n", + "#Results\n", + "print('The reaction at B i.e Rb is ',Rb, 'N')\n", + "print('The horizontal reaction at A i.e Xa is ',Xa, 'N')\n", + "print('The vertical reaction at A i.e Ya is ',Ya,'N')\n" + ] + }, + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "# Example 5.5 Equations of Equilibrium" + ] + }, + { + "cell_type": "code", + "execution_count": 3, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "('The horizontal reaction at A i.e Xa is ', 28.867513459481287, 'N')\n", + "('The vertical reaction at A i.e Ya is ', 100, 'N')\n", + "('The reaction at B i.e Rb is ', 28.867513459481287, 'N')\n" + ] + } + ], + "source": [ + "import math\n", + "#Initilization of variables\n", + "W=100 #N self weight of the man\n", + "alpha=30 #degree angle made by the ladder with the wall\n", + "Lob=4 #m length from the horizontal to the top of the ladder touching the wall(vertical)\n", + "Lcd=2 #m\n", + "\n", + "#Calculations\n", + "# using the equiblirium equations\n", + "Ya=W #N From eq'n 2\n", + "Lad=Lcd*math.tan(math.radians(alpha)) #m Lad is the distance fom pt A to the point where the line from the cg intersects the horizontal\n", + "Rb=(W*Lad)/Lob #N Taking sum of moment abt A\n", + "Xa=Rb #N From eq'n 1\n", + "\n", + "#Results\n", + "print('The horizontal reaction at A i.e Xa is ',Xa, 'N')\n", + "print('The vertical reaction at A i.e Ya is ',Ya,'N' )\n", + "print('The reaction at B i.e Rb is ',Rb ,'N')\n" + ] + }, + { + "cell_type": "markdown", + "metadata": { + "collapsed": true + }, + "source": [ + "# Example 5.6 Equations of Equilibrium" + ] + }, + { + "cell_type": "code", + "execution_count": 2, + "metadata": { + "collapsed": false + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "('The horizontal reaction at A i.e Xa is ', 3.84, 'N')\n", + "('The vertical reaction at A i.e Ya is ', 7.12, 'N')\n", + "('Therefore the reaction at A i.e Ra is ', 8.089499366462674, 'N')\n", + "('The reaction at D i.e Rd is ', 4.8, 'N')\n" + ] + } + ], + "source": [ + "import math\n", + "#Initilization of variables\n", + "d=0.09 #m diametre of the right circular cylinder\n", + "h=0.12 #m height of the cyinder\n", + "W=10 #N self weight of the bar\n", + "l=0.24 #m length of the bar\n", + "\n", + "#Calculations\n", + "theta=math.degrees(math.atan(h/d)) #angle which the bar makes with the horizontal\n", + "Lad=math.sqrt(d**2+h**2) #m Lad is the length of the bar from point A to point B\n", + "Rd=(W*h*(math.cos(theta*math.pi/180)))/Lad #N Taking moment at A\n", + "Xa=Rd*(math.sin(theta*math.pi/180)) #N sum Fx=0.... From eq'n 1\n", + "Ya=W-(Rd*(math.cos(theta*math.pi/180))) #N sum Fy=0..... From eq'n 2\n", + "Ra=math.sqrt(Xa**2+Ya**2) #resultant of Xa & Ya\n", + "\n", + "#Results\n", + "print('The horizontal reaction at A i.e Xa is ',Xa, 'N')\n", + "print('The vertical reaction at A i.e Ya is ',Ya, 'N')\n", + "print('Therefore the reaction at A i.e Ra is ',Ra,'N')\n", + "print('The reaction at D i.e Rd is ',Rd,'N')" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python [Root]", + "language": "python", + "name": "Python [Root]" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 2 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython2", + "version": "2.7.12" + }, + "widgets": { + "state": {}, + "version": "1.1.2" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} diff --git a/mathematics_by_df/screenshots/anshul.png b/mathematics_by_df/screenshots/anshul.png new file mode 100644 index 00000000..a8cec645 Binary files /dev/null and b/mathematics_by_df/screenshots/anshul.png differ diff --git a/mathematics_by_df/screenshots/array_factor.png b/mathematics_by_df/screenshots/array_factor.png new file mode 100644 index 00000000..9e294010 Binary files /dev/null and b/mathematics_by_df/screenshots/array_factor.png differ diff --git a/mathematics_by_df/screenshots/array_factor_1.png b/mathematics_by_df/screenshots/array_factor_1.png new file mode 100644 index 00000000..9e294010 Binary files /dev/null and b/mathematics_by_df/screenshots/array_factor_1.png differ diff --git a/testing_by_df/README.txt b/testing_by_df/README.txt new file mode 100644 index 00000000..b56d70bc --- /dev/null +++ b/testing_by_df/README.txt @@ -0,0 +1,10 @@ +Contributed By: Jeevan Lal +Course: me +College/Institute/Organization: MPBtech. ECE, 6th SemVNIT Nagpur +Department/Designation: MPBtech. ECE, 6th SemVNIT Nagpur +Book Title: testing +Author: df +Publisher: sdf +Year of publication: 3 +Isbn: 543 +Edition: 9 \ No newline at end of file -- cgit