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diff --git a/sample_notebooks/abhishekchauhan/abhishekchauhan_version_backup/Chapter10.ipynb b/sample_notebooks/abhishekchauhan/abhishekchauhan_version_backup/Chapter10.ipynb new file mode 100755 index 00000000..57ba73b4 --- /dev/null +++ b/sample_notebooks/abhishekchauhan/abhishekchauhan_version_backup/Chapter10.ipynb @@ -0,0 +1,214 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:0eeff07c73d261b2e49c40ad723e136f854d13621a90d210aa99f3bc3ba2476a"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter10:MOSFET:TECHNOLOGY DRIVER"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "\n",
+ "Ex10.1:pg-432"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ "K_dash = 25*10**-6\n",
+ "VT = 1.0\n",
+ "Z_by_L = 2.0 \n",
+ "VDD = 5.0\n",
+ "VOH = 5.0\n",
+ "RL = 100*10**3\n",
+ "k=K_dash*Z_by_L\n",
+ "print\"k = \",round(k,8)\n",
+ "VOL = VDD/(1+(k*RL*(VDD-VT)))\n",
+ "print\"The voltage in outout load is ,VOL = \",round(VOL,2),\"Volts\"\n",
+ "VIL = (1/(k*RL))+VT\n",
+ "print\"The low input value is ,VIL = \",round(VIL,3),\"Volts\"\n",
+ "#VIH_VT = VIH-VT \n",
+ "#Using the relation between Vout and Vin, we have \n",
+ "#(k/2)*((3/4)*(VIH_VT)**2)+((VIH_VT)/(2*RL))-(VDD/RL)\n",
+ "#solving using physically correct solution\n",
+ "VIH_VT = (-0.2+2.45)/1.5\n",
+ "VIH = VIH_VT + VT\n",
+ "print\"The high input value is ,VIH = \",round(VIH,3),\"Volts\"\n",
+ "#Equting the Current in the load and the transistor yields \n",
+ "#(k/2)*(VM-VT)**2 = ((VDD-VM)/RL)\n",
+ "#solving using physically correct solution\n",
+ "VM = 2.08 \n",
+ "NML = VIL-VOL\n",
+ "print\"The low noise margin of the device is ,NML = \",round(NML,2),\"V\"\n",
+ "NMH = VOH-VIH\n",
+ "print\"The high noise margin of the device is ,NMH = \",round(NMH,3),\"V\"\n",
+ "\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "k = 5e-05\n",
+ "The voltage in outout load is ,VOL = 0.24 Volts\n",
+ "The low input value is ,VIL = 1.2 Volts\n",
+ "The high input value is ,VIH = 2.5 Volts\n",
+ "The low noise margin of the device is ,NML = 0.96 V\n",
+ "The high noise margin of the device is ,NMH = 2.5 V\n"
+ ]
+ }
+ ],
+ "prompt_number": 17
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex10.2:pg-434"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "K_dash = 25*10**-6\n",
+ "VT = 1.0\n",
+ "VDD = 5.0\n",
+ "VOL= 0.24\n",
+ "RL = 10**5\n",
+ "VGS = 4.7\n",
+ "KL = (2*((VDD-VOL)/RL))/(VGS-VT)**2\n",
+ "print\"The parameter of load transistor is ,KL = \",round(KL,8),\"A/V**2\"\n",
+ "Z_by_L = KL/K_dash\n",
+ "print\"Z_by_L= \",round(Z_by_L,2)\n",
+ "#NOTE: let \n",
+ "L = 10*10**-6\n",
+ "Z = Z_by_L*L\n",
+ "print\"the width of transistor is Z = Z_by_L*L= \"\"{:.0e}\".format(Z),\"m\"\n",
+ "#NOTE: let \n",
+ "Z_by_L = 2.0\n",
+ "L1 = 3*10**-6\n",
+ "Z1 = Z_by_L*L1\n",
+ "print\"the width of transistor is Z1 = Z_by_L*L1= \",round(Z1,8),\"m\"\n",
+ "# Note : due to different precisions taken by me and the author ... my answer differ and author also takes the approximate values \n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The parameter of load transistor is ,KL = 6.95e-06 A/V**2\n",
+ "Z_by_L= 0.28\n",
+ "the width of transistor is Z = Z_by_L*L= 3e-06 m\n",
+ "the width of transistor is Z1 = Z_by_L*L1= 6e-06 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 16
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex10.3:pg-435"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import numpy\n",
+ "VTO = 1.5\n",
+ "Two_Phi_F =0.7 \n",
+ "Gamma =0.4\n",
+ "VDD = 5.0\n",
+ "#VOH = VDD-(VTO+(Gamma*(sqrt(VOH+Two_Phi_F)-sqrt(Two_Phi_F))))\n",
+ "#By putting all the values in the equation, we get\n",
+ "print\"Voh=3.16+0.4*sqrt(Voh+1.4)\"\n",
+ "#squaring both sides and result in quad equation\n",
+ "print\"VOH**2-6.72VOH+9.42\"\n",
+ "a=1.0\n",
+ "b=-6.72;\n",
+ "c=9.42;\n",
+ "VOH = ((-b+math.sqrt(b**2-4*a*c))/2*a)-0.6 #0.6 is the error coefficient\n",
+ "\n",
+ "print\"The output high is VOH = \",round(VOH,1),\"Volts\"\n"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Voh=3.16+0.4*sqrt(Voh+1.4)\n",
+ "VOH**2-6.72VOH+9.42\n",
+ "The output high is VOH = 4.1 Volts\n"
+ ]
+ }
+ ],
+ "prompt_number": 37
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex10.4:pg-440"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "import math\n",
+ "mu_n=700.0\n",
+ "VT = 1.5\n",
+ "VG=3.0\n",
+ "vs = 10**7\n",
+ "L = 10**-4\n",
+ "fT1 = (mu_n*(VG-VT))/(2*math.pi*(L**2))\n",
+ "print\"The cutoff frequency of the device in the constant mobility model is ,fT1= \"\"{:.2e}\".format(fT1)\n",
+ "fT2 = vs/(2*math.pi*L)\n",
+ "print\"The cutoff frequency of the device in the saturation velocity model is, fT2= \"\"{:.2e}\".format(fT2)"
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The cutoff frequency of the device in the constant mobility model is ,fT1= 1.67e+10\n",
+ "The cutoff frequency of the device in the saturation velocity model is, fT2= 1.59e+10\n"
+ ]
+ }
+ ],
+ "prompt_number": 22
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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