diff options
Diffstat (limited to 'sample_notebooks/KAVANA B/CHAPTER.ipynb')
| -rwxr-xr-x | sample_notebooks/KAVANA B/CHAPTER.ipynb | 175 |
1 files changed, 0 insertions, 175 deletions
diff --git a/sample_notebooks/KAVANA B/CHAPTER.ipynb b/sample_notebooks/KAVANA B/CHAPTER.ipynb deleted file mode 100755 index 13237c6c..00000000 --- a/sample_notebooks/KAVANA B/CHAPTER.ipynb +++ /dev/null @@ -1,175 +0,0 @@ -{
- "metadata": {
- "name": ""
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "CHAPTER 2: THERMAL STATIONS"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.1, Page number 25-26"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Variable declaration\n",
- "M = 15000.0+10.0 #Water evaporated(kg)\n",
- "C = 5000.0+5.0 #Coal consumption(kg)\n",
- "time = 8.0 #Generation shift time(hours)\n",
- "\n",
- "#Calculation\n",
- "#Case(a)\n",
- "M1 = M-15000.0\n",
- "C1 = C-5000.0\n",
- "M_C = M1/C1\n",
- "#Case(b)\n",
- "kWh = 0 #Station output at no load\n",
- "consumption_noload = 5000+5*kWh #Coal consumption at no load(kg)\n",
- "consumption_noload_hr = consumption_noload/time #Coal consumption per hour(kg)\n",
- "\n",
- "#Result\n",
- "print('Case(a): Limiting value of water evaporation , M/C = %.1f kg' %M_C)\n",
- "print('Case(b): Coal per hour for running station at no load = %.f kg' %consumption_noload_hr)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Case(a): Limiting value of water evaporation , M/C = 2.0 kg\n",
- "Case(b): Coal per hour for running station at no load = 625 kg\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.2, Page number 26"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Variable declaration\n",
- "amount = 25.0*10**5 #Amount spent in 1 year(Rs)\n",
- "value_heat = 5000.0 #Heating value(kcal/kg)\n",
- "cost = 500.0 #Cost of coal per ton(Rs)\n",
- "n_ther = 0.35 #Thermal efficiency\n",
- "n_elec = 0.9 #Electrical efficiency\n",
- "\n",
- "#Calculation\n",
- "n = n_ther*n_elec #Overall efficiency\n",
- "consumption = amount+cost*value_heat #Coal consumption i 1 year(kg)\n",
- "combustion = consumption*value_heat #Heat of combustion(kcal)\n",
- "output = n*combustion #Heat output(kcal)\n",
- "kWh = output/860.0 #Annual heat generated(kWh). 1 kWh = 860 kcal\n",
- "time = 365*24.0 #Total time in a year(hour)\n",
- "load_average = kWh/time #Average load on the power plant(kW)\n",
- "\n",
- "#Result\n",
- "print('Average load on power plant = %.2f kW' %load_average)\n",
- "print('\\nNOTE: ERROR: Calculation mistake in the final answer in textbook')"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Average load on power plant = 1045.32 kW\n",
- "\n",
- "NOTE: ERROR: Calculation mistake in the final answer in textbook\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.3, Page number 26"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Variable declaration\n",
- "consumption = 0.5 #Coal consumption per kWh output(kg)\n",
- "cal_value = 5000.0 #Calorific value(kcal/kg)\n",
- "n_boiler = 0.8 #Boiler efficiency\n",
- "n_elec = 0.9 #Electrical efficiency\n",
- "\n",
- "#Calculation\n",
- "input_heat = consumption*cal_value #Heat input(kcal)\n",
- "input_elec = input_heat/860.0 #Equivalent electrical energy(kWh). 1 kWh = 860 kcal\n",
- "loss_boiler = input_elec*(1-n_boiler) #Boiler loss(kWh)\n",
- "input_steam = input_elec-loss_boiler #Heat input to steam(kWh)\n",
- "input_alter = 1/n_elec #Alternator input(kWh)\n",
- "loss_alter = input_alter*(1-n_elec) #Alternate loss(kWh)\n",
- "loss_turbine = input_steam-input_alter #Loss in turbine(kWh)\n",
- "loss_total = loss_boiler+loss_alter+loss_turbine #Total loss(kWh)\n",
- "output = 1.0 #Output(kWh)\n",
- "Input = output+loss_total #Input(kWh)\n",
- "\n",
- "#Result\n",
- "print('Heat Balance Sheet')\n",
- "print('LOSSES: Boiler loss = %.3f kWh' %loss_boiler)\n",
- "print(' Alternator loss = %.2f kWh' %loss_alter)\n",
- "print(' Turbine loss = %.3f kWh' %loss_turbine)\n",
- "print(' Total loss = %.2f kWh' %loss_total)\n",
- "print('OUTPUT: %.1f kWh' %output)\n",
- "print('INPUT: %.2f kWh' %Input)\n",
- "print('\\nNOTE: Changes in the obtained answer from that of textbook is due to precision')"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Heat Balance Sheet\n",
- "LOSSES: Boiler loss = 0.581 kWh\n",
- " Alternator loss = 0.11 kWh\n",
- " Turbine loss = 1.214 kWh\n",
- " Total loss = 1.91 kWh\n",
- "OUTPUT: 1.0 kWh\n",
- "INPUT: 2.91 kWh\n",
- "\n",
- "NOTE: Changes in the obtained answer from that of textbook is due to precision\n"
- ]
- }
- ],
- "prompt_number": 1
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |