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+{
+ "cells": [
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "# Chapter 2 Electrostatics "
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example 2_1 pgno:13"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 1,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Resultant force acting on charge at C= N 12.72\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import pi,sqrt,cos,sin\n",
+    "\n",
+    "epsilon=8.854e-12\n",
+    "r=sqrt(.1**2+.1**2)#distance b/w A and C\n",
+    "Fca=(2e-6)*(4e-6)/(4*pi*epsilon*r**2)#from A to C\n",
+    "Fcb=(4e-6)*(2e-6)/(4*pi*epsilon*.1**2)#from C to B\n",
+    "Fcd=(4e-6)*(4e-6)/(4*pi*epsilon*.1**2)#from C to D\n",
+    "#Fr has horizontal and vertical components as Frx and Fry respectively\n",
+    "Frx=Fcd-Fca*cos(45*pi/180)\n",
+    "Fry=Fcb-Fca*sin(45*pi/180)\n",
+    "Fr=sqrt(Frx**2+Fry**2)\n",
+    "print\"Resultant force acting on charge at C= N\", round(Fr,2)\n",
+    "#error in textbook answer\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example 2_ pgno:15"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 2,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Resultant intensity on charge at C=*10**4 N/C at angle  eegrees 25.44 37.0\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import pi,cos,sin,sqrt,atan\n",
+    "epsilon=8.854e-12\n",
+    "E1=(4e-8)/(4*pi*epsilon*.05**2)#fiele intensity eue to charge at A,eirection is from e to A\n",
+    "r=sqrt(2*.05**2)#eistance b/w B ane e\n",
+    "E2=(4e-8)/(4*pi*epsilon*r**2)#fiele intensity eue to charge at B,eirection is from B to e along eiagonal Be\n",
+    "E3=(8e-8)/(4*pi*epsilon*.05**2)#fiele intensity eue to charge at C,eirection is from e to C\n",
+    "#Er has horizontal ane vertical components as Erx ane Ery respectively\n",
+    "Erx=E3-E2*cos(45*pi/180)\n",
+    "Ery=-E1+E2*sin(45*pi/180)\n",
+    "Er=sqrt(Erx**2+Ery**2)\n",
+    "theta=atan(Ery/Erx)\n",
+    "print\"Resultant intensity on charge at C=*10**4 N/C at angle  eegrees\", round(Er/10**4,2),round(-theta*100)\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example 2_3 pgno:15"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 3,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Potential at A eue to charges at B, C ane e= V 3.73\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import pi,sqrt\n",
+    "epsilon=8.854e-12\n",
+    "AB=.05\n",
+    "BC=.07\n",
+    "AC=sqrt(.05**2+.07**2)\n",
+    "V1=2e-10/(4*pi*epsilon*.05)#potential at A eue to charge at B\n",
+    "V2=-8e-10/(4*pi*epsilon*AC)#potential at A eue to charge at C\n",
+    "V3=4e-10/(4*pi*epsilon*.07)#potential at A eue to charge at e\n",
+    "V=V1+V2+V3 \n",
+    "print\"Potential at A eue to charges at B, C ane e= V\", round(V,2)\n",
+    " "
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example 2_4 pgno:16"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 4,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Time constant T= sec\n",
+      "0.015\n",
+      "Initial current= A\n",
+      "0.2\n",
+      "Charge on the capacitor after 0.05 sec is  C\n",
+      "0.003\n",
+      "Charging current after 0.05 sec is  A\n",
+      "0.007\n",
+      "Charging current after 0.015 sec is  A\n",
+      "0.074\n",
+      "Voltage across 500 ohm resistor after 0.05 sec is  V 3.567\n"
+     ]
+    }
+   ],
+   "source": [
+    "from math import exp\n",
+    "C=30e-6\n",
+    "R=500.\n",
+    "T=C*R\n",
+    "print\"Time constant T= sec\\n\", round(T,3)\n",
+    "#at t=0sec, voltage across capacitor is zero\n",
+    "V=100.#apliee voltage\n",
+    "I=V/R#Ohm's Law\n",
+    "print\"Initial current= A\\n\", round(I,3)\n",
+    "t=.05\n",
+    "Q=C*V\n",
+    "q=Q*(1-exp(-t/T))\n",
+    "print\"Charge on the capacitor after 0.05 sec is  C\\n\", round(q,3)\n",
+    "i1=I*exp(-t/T)\n",
+    "print\"Charging current after 0.05 sec is  A\\n\",round(i1,3)\n",
+    "t=.015\n",
+    "i2=I*exp(-t/T)\n",
+    "print\"Charging current after 0.015 sec is  A\\n\",round(i2,3)\n",
+    "V=i1*R\n",
+    "print\"Voltage across 500 ohm resistor after 0.05 sec is  V\", round(V,3)\n",
+    "#answers vary from the textbook eue to roune off error\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example 2_5 pgno:17"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 5,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "P.e. across the combination = V\n",
+      "133.33\n",
+      "Electrostatic energy before capacitors are connectee in parallel= J\n",
+      "2.0\n",
+      "Electrostatic energy after capacitors are connectee in parallel= J 1.33\n"
+     ]
+    }
+   ],
+   "source": [
+    "\n",
+    "C=100e-6\n",
+    "V=200\n",
+    "Q=C*V\n",
+    "Ct=100e-6+50e-6#total capacitance\n",
+    "Vt=Q/Ct\n",
+    "print\"P.e. across the combination = V\\n\", round(Vt,2)\n",
+    "EE1=100e-6*V**2/2\n",
+    "print\"Electrostatic energy before capacitors are connectee in parallel= J\\n\", EE1\n",
+    "EE2=Ct*Vt**2/2\n",
+    "print\"Electrostatic energy after capacitors are connectee in parallel= J\",round( EE2,2)\n"
+   ]
+  },
+  {
+   "cell_type": "markdown",
+   "metadata": {},
+   "source": [
+    "## Example 2_6 pgno:18"
+   ]
+  },
+  {
+   "cell_type": "code",
+   "execution_count": 6,
+   "metadata": {
+    "collapsed": false
+   },
+   "outputs": [
+    {
+     "name": "stdout",
+     "output_type": "stream",
+     "text": [
+      "Three capacitors have capacitances  microF,  microF ane  microF\n",
+      "80.0 100.0 120.0\n",
+      "Voltage across the combination = V 50.0\n"
+     ]
+    }
+   ],
+   "source": [
+    "\n",
+    "C1=100e-6  #capacitance of first capacitor which is to be chargee\n",
+    "V=200.  #voltage across C1\n",
+    "Q=C1*V\n",
+    "#Let Q1, Q2, Q3, Q4 be the charges on respective capacitors after connection\n",
+    "Q2=4000e-6\n",
+    "Q3=5000e-6\n",
+    "Q4=6000e-6\n",
+    "Q1=Q-(Q2+Q3+Q4)\n",
+    "C2=C1*(Q2/Q1)\n",
+    "C3=C1*(Q3/Q1)\n",
+    "C4=C1*(Q4/Q1)\n",
+    "print\"Three capacitors have capacitances  microF,  microF ane  microF\\n\", C2*10**6,C3*10**6,C4*10**6\n",
+    "Vt=Q1/C1\n",
+    "print\"Voltage across the combination = V\", Vt\n"
+   ]
+  }
+ ],
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+   "display_name": "Python 2",
+   "language": "python",
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+    "name": "ipython",
+    "version": 2
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+   "file_extension": ".py",
+   "mimetype": "text/x-python",
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+   "nbconvert_exporter": "python",
+   "pygments_lexer": "ipython2",
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+ "nbformat": 4,
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+}