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diff --git a/sample_notebooks/DeepTrambadia/Untitled0.ipynb b/sample_notebooks/DeepTrambadia/Untitled0.ipynb new file mode 100644 index 00000000..e23c7b5f --- /dev/null +++ b/sample_notebooks/DeepTrambadia/Untitled0.ipynb @@ -0,0 +1,154 @@ +{ + "metadata": { + "name": "", + "signature": "sha256:3090d4f2b3d4de5b787389193d1e9cb10abedd8dbc02a70d6ec597610190cdf7" + }, + "nbformat": 3, + "nbformat_minor": 0, + "worksheets": [ + { + "cells": [ + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#example 2.13 page no.65\n", + "import math\n", + "\n", + "#initialization of variables\n", + "\n", + "E1=20 #supply voltage in V\n", + "E2=4 #second port voltage in V\n", + "Vd=0.7 #thresold voltage\n", + "R=2.2 #R in Kohm\n", + "\n", + "\n", + "#calculation\n", + "\n", + "I = (E1-E2-Vd)/R\n", + "\n", + "print \"Diode D1 turn on and Diode D2 turn off\"\n", + "print \"the resultant current I is %.2fmA\" %(I)\n", + "\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Diode D1 turn on and Diode D2 turn off\n", + "the resultant current I is 6.95mA\n" + ] + } + ], + "prompt_number": 1 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#example 2.14 page no.66\n", + "import math\n", + "\n", + "#initialization of variables\n", + "E=12 #supply Voltage in V\n", + "Vd=0.3 #thresold voltage in V\n", + "\n", + "\n", + "#calculation\n", + "\n", + "V0 = E-Vd\n", + "\n", + "print \"If initially both were 'on,'' the 0.7-V drop across the silicon diode would not match the 0.3 V \"\n", + "print \"across the germanium diode as required by the fact that the voltage across parallel elements must be the same\"\n", + "print \"The silicon diode will never have the opportunity to capture its required 0.7 V and therefore remains in its open-circuit state\"\n", + "print \"the resultant Voltage V0 is %.1fV\" % (V0)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "If initially both were 'on,'' the 0.7-V drop across the silicon diode would not match the 0.3 V \n", + "across the germanium diode as required by the fact that the voltage across parallel elements must be the same\n", + "The silicon diode will never have the opportunity to capture its required 0.7 V and therefore remains in its open-circuit state\n", + "the resultant Voltage V0 is 11.7V\n" + ] + } + ], + "prompt_number": 2 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [ + "#example 2.15 page no.66\n", + "import math\n", + "\n", + "#initialization of variables\n", + "\n", + "E=20 #supply voltage in V\n", + "VT1=0.7 #thresold voltage\n", + "VT2=0.7 #thresold voltage\n", + "R1=3.3 #R in Kohm\n", + "R2=5.6 #R in Kohm\n", + "\n", + "#calculation\n", + "\n", + "print \"Both Diodes will turn 'on'\"\n", + "print \"So diode voltage will appear over the resistance\"\n", + "\n", + "I1 = (VT2)/R1\n", + "\n", + "print \"the resultant current I2 is %.3fmA\" %(I1)\n", + "\n", + "print \"Applying Kirchhoff's voltage law around the indicated loop in the clockwise direction yields\"\n", + "\n", + "V2 = E-VT1-VT2\n", + "I2 = V2/R2\n", + "\n", + "print \"the voltage V2 =%.1fV\" %(V2)\n", + "print \"the current I2 =%.2fmA\"%(I2)\n", + "\n", + "#At hte bottom node (a)\n", + "\n", + "ID2=I2-I1\n", + "\n", + "print \"the current I2 =%.3fmA\" %(ID2)\n" + ], + "language": "python", + "metadata": {}, + "outputs": [ + { + "output_type": "stream", + "stream": "stdout", + "text": [ + "Both Diodes will turn 'on'\n", + "So diode voltage will appear over the resistance\n", + "the resultant current I2 is 0.212mA\n", + "Applying Kirchhoff's voltage law around the indicated loop in the clockwise direction yields\n", + "the voltage V2 =18.6V\n", + "the current I2 =3.32mA\n", + "the current I2 =3.109mA\n" + ] + } + ], + "prompt_number": 3 + }, + { + "cell_type": "code", + "collapsed": false, + "input": [], + "language": "python", + "metadata": {}, + "outputs": [] + } + ], + "metadata": {} + } + ] +}
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