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diff --git a/sample_notebooks/ABHISHEKAGRAWAL/ABHISHEKAGRAWAL_version_backup/chapter2.ipynb b/sample_notebooks/ABHISHEKAGRAWAL/ABHISHEKAGRAWAL_version_backup/chapter2.ipynb new file mode 100755 index 00000000..1bfa373e --- /dev/null +++ b/sample_notebooks/ABHISHEKAGRAWAL/ABHISHEKAGRAWAL_version_backup/chapter2.ipynb @@ -0,0 +1,149 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:41187fe2c381fd7b42e97b2fb4a9a8ffca57cedad7f414bab15784b2fa882a72"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter2:ELECTROMAGNETIC PLANE WAVES"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex2.6.5:pg-69"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "\n",
+ " \n",
+ "import math \n",
+ "#(a) Program to find gold-film surface resistance \n",
+ " \n",
+ " \n",
+ "t=80*(10**(-10)) #Film Thickness\n",
+ "o=4.1*(10**7) #Bulk conductivity \n",
+ "p=570*(10**(-10)) #Electron mean free path \n",
+ "of=((3*t*o)/(4*p))*(0.4228 + math.log(p/t)) #the gold-film conductivity is of=(3*t*o/4*p)*(0.4228 + ln(p/t)) \n",
+ "\n",
+ "Rs=1/(t*of) #the gold-film surface resistance is given by Rs=1/(t*of) in Ohms per square\n",
+ "\n",
+ "\n",
+ "print\"The gold film surface resistance in Ohms per square is=\",round(Rs,2),\"Ohms/square\"\n",
+ "\n",
+ "\n",
+ "#(b) Program to find the microwave attenuation \n",
+ "\n",
+ "Attenuation=40-20*log10(Rs) #Microwave attenuation \n",
+ "\n",
+ "print\"Microwave Attenuation in db is=\",int(Attenuation),\"db\"\n",
+ "\n",
+ "\n",
+ "#(c)Light transmittance T\n",
+ "\n",
+ "print\"From figure No.2-6-5 of Light transmittance T and light attenuation loss L versus wavelength with film thickness t as parameter for gold film, we find that for given gold film of thickness 80 angstrom ,the LIGHT TRANSMITTANCE T is estimated to be 75%\"\n",
+ "\n",
+ "\n",
+ "#(d)light reflection loss R\n",
+ "\n",
+ "print\"From the same figure the LIGHT REFLECTION LOSS R is about 25%\"\n",
+ " "
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The gold film surface resistance in Ohms per square is= 12.14 Ohms/square\n",
+ "Microwave Attenuation in db is= 18 db\n",
+ "From figure No.2-6-5 of Light transmittance T and light attenuation loss L versus wavelength with film thickness t as parameter for gold film, we find that for given gold film of thickness 80 angstrom ,the LIGHT TRANSMITTANCE T is estimated to be 75%\n",
+ "From the same figure the LIGHT REFLECTION LOSS R is about 25%\n"
+ ]
+ }
+ ],
+ "prompt_number": 1
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Ex2.6.6:pg-74"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ " \n",
+ "import math \n",
+ "#(a) Program to find copper-film surface resistance \n",
+ " \n",
+ " \n",
+ "t=60*(10**(-10)) #Film Thickness\n",
+ "o=5.8*(10**7) #Bulk conductivity \n",
+ "p=420*(10**(-10)) #Electron mean free path \n",
+ "of=((3*t*o)/(4*p))*(0.4228 + math.log(p/t)) #the copper-film conductivity is of=(3*t*o/4*p)*(0.4228 + ln(p/t))\n",
+ "Rs=1/(t*of) #the copper-film surface resistance is given by Rs=1/(t*of) in Ohms per square\n",
+ "\n",
+ "print\"The copper-film surface resistance in Ohms per square is=\",round(Rs,2),\"Ohms/square\"\n",
+ "\n",
+ "\n",
+ "#(b) Program to find the microwave attenuation \n",
+ "\n",
+ "Attenuation=40-20*log10(Rs) #Microwave attenuation \n",
+ "\n",
+ "print\"Microwave Attenuation in db is=\",int(round(Attenuation)),\"db\"\n",
+ "\n",
+ "#(c)Light transmittance T\n",
+ "\n",
+ "print\"From figure No.2-6-11 of Light transmittance T and light attenuation loss L versus wavelength with film thickness t as parameter for copper film, we find that for given copper film of thickness 60 angstrom ,the LIGHT TRANSMITTANCE T is estimated to be 82%\"\n",
+ "\n",
+ "#(d)light reflection loss R\n",
+ "\n",
+ "print\"From the same figure the LIGHT REFLECTION LOSS R is about 18%\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "The copper-film surface resistance in Ohms per square is= 11.32 Ohms/square\n",
+ "Microwave Attenuation in db is= 19 db\n",
+ "From figure No.2-6-11 of Light transmittance T and light attenuation loss L versus wavelength with film thickness t as parameter for copper film, we find that for given copper film of thickness 60 angstrom ,the LIGHT TRANSMITTANCE T is estimated to be 82%\n",
+ "From the same figure the LIGHT REFLECTION LOSS R is about 18%\n"
+ ]
+ }
+ ],
+ "prompt_number": 2
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [],
+ "language": "python",
+ "metadata": {},
+ "outputs": []
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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