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diff --git a/modern_physics_by_Satish_K._Gupta/chap5.ipynb b/modern_physics_by_Satish_K._Gupta/chap5.ipynb deleted file mode 100755 index 84950cb9..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap5.ipynb +++ /dev/null @@ -1,1167 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:59a10421d0b18543bcaaf15fad8dcc2fa1ef98c5fe857c6feab5eddfb8fae6cd"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 5 Capacitor"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.1 Page no 108"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "r=6.4*10**6 #m\n",
- "t=9*10**9\n",
- "\n",
- "#Calculation\n",
- "C=r/t\n",
- "\n",
- "#Result\n",
- "print\"The capacitance is\",round(C*10**6,0),\"F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The capacitance is 711.0 F\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "Example 5.2 Page no 108"
- ],
- "language": "python",
- "metadata": {},
- "outputs": []
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "r=0.01 #m\n",
- "q=1 #C\n",
- "d=9.0*10**9\n",
- "\n",
- "#Calculation\n",
- "V=(q*d)/r\n",
- "\n",
- "#Result\n",
- "print\"V=\",V,\"V\"\n",
- "print\"The given metal sphere will not be able to hold charge of 1 C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "V= 9e+11 V\n",
- "The given metal sphere will not be able to hold charge of 1 C\n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.3 Page no 109"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=3\n",
- "Q=27\n",
- "q=4*220\n",
- "\n",
- "#Calculation\n",
- "d=(Q*q)/(4*R)\n",
- "\n",
- "#Result\n",
- "print\"The potential of the bigger drop is\",d,\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The potential of the bigger drop is 1980 V\n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "Example 5.4 Page no 109"
- ],
- "language": "python",
- "metadata": {},
- "outputs": []
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C=2 #F\n",
- "d=0.5*10**-2 #m\n",
- "a=8.854*10**-12\n",
- "\n",
- "#Calculation\n",
- "Q=(C*d)/a\n",
- "\n",
- "#Result\n",
- "print\"Area of the plate is\", round(Q*10**-9,2),\"*10**9 m**2\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Area of the plate is 1.13 *10**9 m**2\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.5 Page no 109"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "A=10**-2 #m**2\n",
- "d=10**-3 #m\n",
- "q=0.12*10**-6\n",
- "V=120.0\n",
- "e=8.85*10**-12\n",
- "\n",
- "#Calculation\n",
- "C=q/V\n",
- "K=C*d/(e*A)\n",
- "\n",
- "#Result\n",
- "print\"Dielectric constant of the material is\", round(K,1)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Dielectric constant of the material is 11.3\n"
- ]
- }
- ],
- "prompt_number": 40
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.6 Page no 109"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "A1=100.0 #cm**2\n",
- "A2=500 #cm**2\n",
- "d1=0.05 #cm\n",
- "\n",
- "#Calculation\n",
- "d2=(A2*d1)/A1\n",
- "\n",
- "#Result\n",
- "print\"Difference between the plates of second capacitor is\", d2,\"cm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Difference between the plates of second capacitor is 0.25 cm\n"
- ]
- }
- ],
- "prompt_number": 43
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.7 Page no 109"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=6.45*10**6 #m\n",
- "b=6.4*10**6 #m\n",
- "m=9*10**9\n",
- "\n",
- "#Calculation\n",
- "C=(a*b)/(m*(a-b))\n",
- "\n",
- "#Result\n",
- "print\"Capacitance of the spherical capacitor is\",round(C,3),\"F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance of the spherical capacitor is 0.092 F\n"
- ]
- }
- ],
- "prompt_number": 48
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.8 Page no 109"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=12*10**-2 #m\n",
- "b=13*10**-2 #m\n",
- "q=2.5*10**-6 #C\n",
- "K=32\n",
- "m=9.0*10**9\n",
- "\n",
- "#Calculation\n",
- "C=(K*a*b)/(m*(b-a))\n",
- "V=q/C\n",
- "C1=a/m\n",
- "C2=C/C1\n",
- "\n",
- "#Result\n",
- "print\"(a) Capacitance of the capacitor is\", round(C*10**9,3)*10**-9,\"F\"\n",
- "print\"(b) Potential of the inner sphere is\", round(V,1),\"V\"\n",
- "print\"(c) Capacitance of the capacitor is\",C2"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Capacitance of the capacitor is 5.547e-09 F\n",
- "(b) Potential of the inner sphere is 450.7 V\n",
- "(c) Capacitance of the capacitor is 416.0\n"
- ]
- }
- ],
- "prompt_number": 61
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.9 Page no 110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=1.4*10**-2 #m\n",
- "b=1.5*10**-2 #m\n",
- "q=3.5*10**-6 #C\n",
- "e=8.854*10**-12\n",
- "l=15*10**-2\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "C=(2*math.pi*e*l)/(2.303*math.log10(b/a))\n",
- "V=q/C\n",
- "\n",
- "#Result\n",
- "print\"Capacitance of the system is\", round(C*10**10,2)*10**-8,\"F\"\n",
- "print\"Potential of the inner cylinder is\", round(V*10**-4,2),\"*10**4 V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance of the system is 1.21e-08 F\n",
- "Potential of the inner cylinder is 2.89 *10**4 V\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.10 Page no 110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C=9.0*10**-12 #F\n",
- "V=120 #V\n",
- "\n",
- "#Calculation\n",
- "C1=1/(3/C)\n",
- "q=(V*C)/3.0\n",
- "V1=q/C\n",
- "\n",
- "#Result\n",
- "print\"(a) Total capacitance is\",C1,\"F\"\n",
- "print\"(b) Potential difference across each capacitor is\",V1,\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Total capacitance is 3e-12 F\n",
- "(b) Potential difference across each capacitor is 40.0 V\n"
- ]
- }
- ],
- "prompt_number": 17
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.11 Page no 110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C1=2*10**-12 #F\n",
- "C2=3*10**-12\n",
- "C3=4*10**-12\n",
- "V=100 #Volts\n",
- "\n",
- "#Calculation\n",
- "C=C1+C2+C3\n",
- "q1=C1*V\n",
- "q2=C2*V\n",
- "q3=C3*V\n",
- "\n",
- "#Result\n",
- "print\"(a) Total capacitamce of the parallel combination is\",C,\"F\"\n",
- "print\"(b) Charge on q1 is\",q1,\"C\"\n",
- "print\"(c) Charge on q2 is\",q2,\"C\"\n",
- "print\"(d) Charge on q3 is\",q3,\"C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Total capacitamce of the parallel combination is 9e-12 F\n",
- "(b) Charge on q1 is 2e-10 C\n",
- "(c) Charge on q2 is 3e-10 C\n",
- "(d) Charge on q3 is 4e-10 C\n"
- ]
- }
- ],
- "prompt_number": 26
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.12 Page no 110"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "c1=5.0 #micro F\n",
- "c2=4.0\n",
- "c3=3.0\n",
- "\n",
- "#Calculation\n",
- "C=1/(1/c1+1/c2)\n",
- "c11=C+c3\n",
- "\n",
- "#Result\n",
- "print\"Capacitance of the combination is\",round(c11,2),\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance of the combination is 5.22 micro F\n"
- ]
- }
- ],
- "prompt_number": 31
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.13 Page no 111"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "cs=3 #micro F\n",
- "cp=16\n",
- "c1=12\n",
- "\n",
- "#Calculation\n",
- "C=cs*cp\n",
- "c2=cp-c1\n",
- "\n",
- "#Result\n",
- "print\"Capacitance of each capacitor is\",c2,\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance of each capacitor is 4 micro F\n"
- ]
- }
- ],
- "prompt_number": 35
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.14 Page no 111"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "c2=6.0 #micro F\n",
- "c3=6.0\n",
- "c1=12.0\n",
- "c4=12.0\n",
- "\n",
- "#Calculation\n",
- "c23=c2+c3\n",
- "C=1/(1/c1+1/c23+1/c4)\n",
- "\n",
- "#Result\n",
- "print\"resultant of capacitance is\",C,\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "resultant of capacitance is 4.0 micro F\n"
- ]
- }
- ],
- "prompt_number": 39
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.15 Page no 111"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "c1=3.0 #pico F\n",
- "c2=2.0\n",
- "\n",
- "#Calculation\n",
- "C=1/(1/c1+1/c2+1/c1)\n",
- "c11=C+c2\n",
- "C11=1/(1/c1+1/c11+1/c1)\n",
- "\n",
- "#Result \n",
- "print\"Resultant capacitance is\",round(C11,0),\"pF\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resultant capacitance is 1.0 pF\n"
- ]
- }
- ],
- "prompt_number": 43
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.16 Page no 111"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C2=2\n",
- "C3=2\n",
- "C1=1 #micro F\n",
- "C4=2\n",
- "C5=1\n",
- "\n",
- "#Calculation\n",
- "C23=C2*C3/(C2+C3)\n",
- "C123=C1+C23\n",
- "C1234=C123*C4/(C123+C4)\n",
- "C=C1234+C5\n",
- "\n",
- "#Ressult\n",
- "print\"Equivalent capacitance is\", C,\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Equivalent capacitance is 2 micro F\n"
- ]
- }
- ],
- "prompt_number": 49
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.17 Page no 112"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C5=10*10**-6 #micro F\n",
- "C6=10*10**-6\n",
- "C2=60.0*10**-6\n",
- "C3=60.0*10**-6\n",
- "C4=60.0*10**-6\n",
- "C1=40*10**-6\n",
- "V=100 #V\n",
- "\n",
- "#Calculation\n",
- "C56=(C5+C6)\n",
- "C234=1/(1/C2+1/C3+1/C4)\n",
- "C=C56+C234\n",
- "C11=(C1*C)/(C1+C)\n",
- "q=C56*V\n",
- "\n",
- "#Result\n",
- "print\"Total charge is\",q*10**3,\"*10**-3 C\"\n",
- "print\"Equivalent capacitance is\",C11*10**6,\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Total charge is 2.0 *10**-3 C\n",
- "Equivalent capacitance is 20.0 micro F\n"
- ]
- }
- ],
- "prompt_number": 75
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.19 Page no 113"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C1=5.0*10**-6 #F\n",
- "C2=10.0*10**-6\n",
- "C3=2.0*10**-6\n",
- "C4=4.0*10**-6\n",
- "\n",
- "#Calculation\n",
- "C12=1/(1/C1+1/C2)\n",
- "C34=1/(1/C3+1/C4)\n",
- "C=C12+C34\n",
- "\n",
- "#Result\n",
- "print\"Effective capacitance is\", round(C*10**6,2),\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Effective capacitance is 4.67 micro F\n"
- ]
- }
- ],
- "prompt_number": 81
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.20 Page no 113"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "n=3\n",
- "C1=1.0\n",
- "C2=1.0\n",
- "C3=1.0\n",
- "C=2 #micro F\n",
- "\n",
- "#Calculation\n",
- "C11=1/(1/C1+1/C2+1/C3)\n",
- "m=C/C11\n",
- "\n",
- "#Result\n",
- "print\"Capacitance required is\", m"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Capacitance required is 6.0\n"
- ]
- }
- ],
- "prompt_number": 84
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.21 Page no 113"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C1=4\n",
- "V=6\n",
- "C2=6\n",
- "\n",
- "#Calculation\n",
- "q1=C1*V\n",
- "q2=C2*V\n",
- "\n",
- "#Result\n",
- "print\"Charge on C1 is\",q1,\"micro C\"\n",
- "print\"Charge on C2 is\",q2,\"micro C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Charge on C1 is 24 micro C\n",
- "Charge on C2 is 36 micro C\n"
- ]
- }
- ],
- "prompt_number": 88
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.22 Page no 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C2=5 #micro F\n",
- "C3=5 \n",
- "a=6\n",
- "C1=10\n",
- "V=3\n",
- "\n",
- "#Calculation\n",
- "C23=C2+C3\n",
- "V1=a/2.0\n",
- "q1=C1*V\n",
- "q23=C23*V\n",
- "q3=q23/2.0\n",
- "\n",
- "#Result\n",
- "print\"Charge on capacitor C1 is\",q1,\"micro F\"\n",
- "print\"Charge on capacitor C2 is\",q23,\"micro F\"\n",
- "print\"Charge on capacitor C3 is\",q3,\"micro F\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Charge on capacitor C1 is 30 micro F\n",
- "Charge on capacitor C2 is 30 micro F\n",
- "Charge on capacitor C3 is 15.0 micro F\n"
- ]
- }
- ],
- "prompt_number": 94
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.23 Page no 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C1=4*10**-6 #F\n",
- "V1=400 #V\n",
- "C2=2*10**-6\n",
- "q2=0\n",
- "\n",
- "#Calculation\n",
- "q1=C1*V1\n",
- "C=C1+C2\n",
- "q=q1+q2\n",
- "V=q/C\n",
- "\n",
- "#Result\n",
- "print\"Common potential is\", round(V,2),\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Common potential is 266.67 V\n"
- ]
- }
- ],
- "prompt_number": 101
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.24 Page no 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=12\n",
- "C1=8 #micro F\n",
- "C2=4\n",
- "\n",
- "#Calculation\n",
- "Va=V-C2\n",
- "Vb=V-C1\n",
- "V1=Va-Vb\n",
- "\n",
- "#Result\n",
- "print\"Potential difference is\", V1,\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Potential difference is 4 V\n"
- ]
- }
- ],
- "prompt_number": 105
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.25 Page no 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "A=90*10**-4 #m**2\n",
- "d=2.5*10**-3 #m\n",
- "V=400 #Volts\n",
- "e=8.854*10**-12\n",
- "\n",
- "#Calculation\n",
- "C=(e*A)/d\n",
- "W=(C*V**2)/2.0\n",
- "\n",
- "#Result\n",
- "print\"Electrostatic energy is\", round(W*10**6,2)*10**-6,\"J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electrostatic energy is 2.55e-06 J\n"
- ]
- }
- ],
- "prompt_number": 112
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.26 Page no 114"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C=2000*10**-6 \n",
- "V=1.5 #V\n",
- "t=10.0**-4 #s\n",
- "\n",
- "#Calculation\n",
- "U=(C*V**2)/2.0\n",
- "P=U/t\n",
- "\n",
- "#Result\n",
- "print\"Energy stored in the capacitor is\", U*10**3,\"*10**-3 J\"\n",
- "print\"Power of the flash is\",P,\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Energy stored in the capacitor is 2.25 *10**-3 J\n",
- "Power of the flash is 22.5 W\n"
- ]
- }
- ],
- "prompt_number": 119
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.27 Page no 115"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "C1=4*10**-6\n",
- "V1=200 #V\n",
- "C2=2*10**-6 # F\n",
- "\n",
- "#Calculation\n",
- "U1=(C1*V1**2)/2.0\n",
- "q=C1*V1\n",
- "C=C1+C2\n",
- "V=q/C\n",
- "U2=(C*V**2)/2.0\n",
- "U=U1-U2\n",
- "\n",
- "#Result\n",
- "print\"Electrostatic energy is\",round(U*10**2,2),\"*10**-2 J\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electrostatic energy is 2.67 *10**-2 J\n"
- ]
- }
- ],
- "prompt_number": 129
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.28 Page no 115"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "K=6.0\n",
- "C=17.7*10**-12 #F\n",
- "V=100\n",
- "\n",
- "#Calculation\n",
- "C1=K*C\n",
- "q=C1*V\n",
- "V1=V/K\n",
- "q1=C1*V1\n",
- "\n",
- "#Result\n",
- "print\"(a) Charge on capacitor is\", q,\"C\"\n",
- "print\"(b) Charge on capacitor is\", q1,\"C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Charge on capacitor is 1.062e-08 C\n",
- "(b) Charge on capacitor is 1.77e-09 C\n"
- ]
- }
- ],
- "prompt_number": 135
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.29 Page no 115"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "K=3\n",
- "e=8.854*10**-12 #C**2/N/m**2\n",
- "C=50*10**-12 #F\n",
- "a=10**7 #V/m\n",
- "b=10\n",
- "V=10**3\n",
- "\n",
- "#Calculation\n",
- "E=(a*b)/100.0\n",
- "q=C*V\n",
- "A=q/(e*K*E)\n",
- "\n",
- "#Result\n",
- "print\"Minimum area is\", round(A*10**4,1),\"cm**2\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Minimum area is 18.8 cm**2\n"
- ]
- }
- ],
- "prompt_number": 140
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.30 Page no 115"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "V=15*10**5 #V\n",
- "E=5.0*10**7 #V/m\n",
- "\n",
- "#Calculation\n",
- "r=V/E\n",
- "\n",
- "#Result\n",
- "print\"Minimum radius of the spherical shell is\", r*10**2,\"cm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Minimum radius of the spherical shell is 3.0 cm\n"
- ]
- }
- ],
- "prompt_number": 144
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |