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diff --git a/modern_physics_by_Satish_K._Gupta/chap34.ipynb b/modern_physics_by_Satish_K._Gupta/chap34.ipynb deleted file mode 100755 index 9aea6687..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap34.ipynb +++ /dev/null @@ -1,621 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:13c8f6846e205753ae8bd963e82228c66a5cc1ec104d777be242a6767f4586d5"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 34 Semiconductor devices"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.1 Page no 932"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=3 #V\n",
- "Vd=0.7\n",
- "R=100.0\n",
- "\n",
- "#Calculation\n",
- "V=E-Vd\n",
- "I=V/R\n",
- "\n",
- "#Result\n",
- "print\"Current in the circuit is\",I*10**3,\"mA\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current in the circuit is 23.0 mA\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.2 Page no 932"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=1.5 #V\n",
- "Vd=0.5\n",
- "P=0.1 #W\n",
- "\n",
- "#Calculation\n",
- "I=P/Vd\n",
- "V=E-Vd\n",
- "R=V/I\n",
- "\n",
- "#Result\n",
- "print\"Value of resistance is\",R,\"ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Value of resistance is 5.0 ohm\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.3 Page no 932"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=9 #V\n",
- "Vz=6 #V\n",
- "Rl=1000.0 #ohm\n",
- "R=100.0 #ohm\n",
- "\n",
- "#Calculation\n",
- "V=E-Vz\n",
- "I=V/R\n",
- "Il=Vz/Rl\n",
- "Iz=I-Il\n",
- "Pz=Vz*Iz\n",
- "\n",
- "#Result\n",
- "print\"Power dissipated in zener diode is\",Pz,\"watt\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Power dissipated in zener diode is 0.144 watt\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.4 Page no 932"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E0=50 #V\n",
- "S=2.0\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "E1=50/math.sqrt(S) #V\n",
- "V=math.sqrt(E1**2/S)\n",
- "V1=(S*E0/math.pi)/S\n",
- "\n",
- "#Result\n",
- "print\"(a) The r.m.s. voltage across Rl is\",V,\"V\"\n",
- "print\"(b) Reading of a d.c voltametre connected across Rl is\",round(V1,2),\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The r.m.s. voltage across Rl is 25.0 V\n",
- "(b) Reading of a d.c voltametre connected across Rl is 15.92 V\n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.5 Page no 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "A=0.96\n",
- "Ie=7.2 #mA\n",
- "\n",
- "#Calculation\n",
- "Ic=A*Ie\n",
- "Ib=Ie-Ic\n",
- "\n",
- "#Result\n",
- "print\"The base current is\",round(Ib,2),\"mA\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The base current is 0.29 mA\n"
- ]
- }
- ],
- "prompt_number": 27
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.6 Page no 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "B=70\n",
- "Ie=8.8 #mA\n",
- "Ib=1.0\n",
- "Ic=70.0\n",
- "\n",
- "#Calculation\n",
- "Ib1=Ie/(Ic+Ib)\n",
- "Ic1=Ic*Ib1\n",
- "A=Ic/(Ic+Ib)\n",
- "\n",
- "#Result\n",
- "print\"The collector current is\",round(Ib1,3),\"mA\"\n",
- "print\"The base current is\",round(Ic1,2),\"mA\"\n",
- "print\"Current gain is\",round(A,3)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The collector current is 0.124 mA\n",
- "The base current is 8.68 mA\n",
- "Current gain is 0.986\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.7 Page no 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ib=105*10**-6 #A\n",
- "Ic=2.05*10**-3 #A\n",
- "Ib1=27*10**-6 #A\n",
- "Ic1=650*10**-6 #A\n",
- "\n",
- "#Calculation\n",
- "B=Ic/Ib\n",
- "Ie=Ib+Ic\n",
- "A=Ic/Ie\n",
- "Bac=Ic1/Ib1\n",
- "\n",
- "#Result\n",
- "print\"(a) The value of B is\",round(B,1),\",Value of Ie is\",Ie*10**3,\"*10**-3 A\",\"and Value of A is\",round(A,2)\n",
- "print\"(b) The value of Bac is\",round(Bac,2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The value of B is 19.5 ,Value of Ie is 2.155 *10**-3 A and Value of A is 0.95\n",
- "(b) The value of Bac is 24.07\n"
- ]
- }
- ],
- "prompt_number": 29
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.8 Page no 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ie=7.89*10**-3 #A\n",
- "Ic=7.8*10**-3 #A\n",
- "\n",
- "#Calculation\n",
- "A=Ic/Ie\n",
- "B=A/(1-A)\n",
- "Ib=Ic/B\n",
- "\n",
- "#Result\n",
- "print\"change in the base current is\",Ib,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "change in the base current is 9e-05 A\n"
- ]
- }
- ],
- "prompt_number": 39
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.9 Page no 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ib=20.0*10**-6 #A\n",
- "Vbe=0.02 #V\n",
- "Ic=2*10**-3 #A\n",
- "Rl=5000 #ohm\n",
- "\n",
- "#Calculation\n",
- "P=Vbe/Ib\n",
- "B=Ic/Ib\n",
- "Gm=Ic/Vbe\n",
- "Q=(Rl*Ic)/Vbe\n",
- "\n",
- "#Result\n",
- "print\"(a) The input resistance Bac is\",P,\"ohm\",\"and transconductance of the transister is\",Gm,\"ohm**-1\"\n",
- "print\"(b) The voltage gain of the amplifier is\",Q"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The input resistance Bac is 1000.0 ohm and transconductance of the transister is 0.1 ohm**-1\n",
- "(b) The voltage gain of the amplifier is 500.0\n"
- ]
- }
- ],
- "prompt_number": 47
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.10 Page no 933"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ib=15*10**-6 #A\n",
- "Ic=2*10**-3 #A\n",
- "R=665.0 #ohm\n",
- "Rl=5*10**3 #ohm\n",
- "\n",
- "#Calculation\n",
- "B=Ic/Ib\n",
- "Gm=B/R\n",
- "Av=Gm*Rl\n",
- "\n",
- "#Result \n",
- "print\"(i) Current gain is\",round(B,1)\n",
- "print\"(ii) Transconductance is\",round(Gm,1),\"ohm**-1\"\n",
- "print\"(iii) Voltage gain Av of the amplifier is\",round(Av,0)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Current gain is 133.3\n",
- "(ii) Transconductance is 0.2 ohm**-1\n",
- "(iii) Voltage gain Av of the amplifier is 1003.0\n"
- ]
- }
- ],
- "prompt_number": 41
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.11 Page no 934"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "B=100.0\n",
- "Vcc=24 #V\n",
- "Ic=1.5*10**-3 #A\n",
- "Rc=4.7*10**3\n",
- "Rb=220*10**3\n",
- "\n",
- "#Calculation\n",
- "Ib=Ic/B\n",
- "Vce=Vcc-(Ic*Rc)\n",
- "Vbe=Vcc-(Ib*Rb)\n",
- "Vbc=(Ic*Rc)-(Ib*Rb)\n",
- "\n",
- "#Result\n",
- "print\"The value of Ib is\",Ib,\"A\"\n",
- "print\"The value of Vce is\",Vce,\"V\"\n",
- "print\"The value of Vbe is\",Vbe,\"V\"\n",
- "print\"The value of Vbc is\",Vbc,\"V\"\n",
- "print\"The transistor is in saturation state\" "
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The value of Ib is 1.5e-05 A\n",
- "The value of Vce is 16.95 V\n",
- "The value of Vbe is 20.7 V\n",
- "The value of Vbc is 3.75 V\n",
- "The transistor is in saturation state\n"
- ]
- }
- ],
- "prompt_number": 84
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.15 Page no 935"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Vb=5 #V\n",
- "I=10**3 #A\n",
- "Q=0.7\n",
- "I1=5*10**-3\n",
- "Vb1=6 #V\n",
- "R0=1000 #ohm\n",
- "I3=10**-3 #A\n",
- "\n",
- "#Calculation\n",
- "R=(Vb-Q)*I\n",
- "R1=(R*10**-3)/I1\n",
- "R3=(Vb1-Q)/I1\n",
- "R4=I1**2*R3\n",
- "R5=Q*I1\n",
- "Vz=(I3*R0)+Q\n",
- "\n",
- "#Result\n",
- "print\"(a) The maximum value of R is\",R*10**-3,\"10**3\",\"ohm\"\n",
- "print\"(b) The value of R is\",R1,\"ohm\"\n",
- "print\"(c) The power dissipated across R is\",R4*10**3,\"10**-3\",\"ohm\",\"and across diode is\",R5*10**3,\"10**-3 W\"\n",
- "print\"(d) The maximum voltage Vb is\",Vz,\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The maximum value of R is 4.3 10**3 ohm\n",
- "(b) The value of R is 860.0 ohm\n",
- "(c) The power dissipated across R is 26.5 10**-3 ohm and across diode is 3.5 10**-3 W\n",
- "(d) The maximum voltage Vb is 1.7 V\n"
- ]
- }
- ],
- "prompt_number": 148
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.16 Page no 935"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "I0=5*10**-12 #A\n",
- "K=8.6*10**-5 #eVK**-1\n",
- "Q=1.6*10**-19 #J K**-1\n",
- "V=0.6 #volts\n",
- "V1=0.7 #volts\n",
- "A=23.256\n",
- "A1=27.132\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "I=-I0*(Q*V/math.exp(K*Q)-1)\n",
- "Z=I*(math.exp(A)-1)\n",
- "I1=-I0*(Q*V1/math.exp(K*Q)-1)\n",
- "Z1=I1*(math.exp(A1)-1)\n",
- "S=Z1-Z\n",
- "V2=V1-V\n",
- "J=V2/S\n",
- "\n",
- "#Result\n",
- "print\"(a) The forward current at a forward voltage is\",round(Z,4),\"A\"\n",
- "print\"(b) The voltage across the diode is\",round(S,4),\"A\"\n",
- "print\"(c) The dynamic resistance is\",round(J,4),\"ohm\"\n",
- "print\"(d) For change in votage from 1V to 2V,the current will remain equal to\",I0,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The forward current at a forward voltage is 0.0629 A\n",
- "(b) The voltage across the diode is 2.9727 A\n",
- "(c) The dynamic resistance is 0.0336 ohm\n",
- "(d) For change in votage from 1V to 2V,the current will remain equal to 5e-12 A\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 34.17 Page no 936"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Vbe=24*10**-3 #V\n",
- "Ib=32*10**-6 #A\n",
- "Ic=3.6*10**-3 #A\n",
- "Rl=4.8*10**3\n",
- "\n",
- "#Calculation\n",
- "B=Ic/Ib\n",
- "Rbe=Vbe/Ib\n",
- "Gm=Ic/Vbe\n",
- "Av=(Rl*Ic)/Vbe\n",
- "\n",
- "#Result\n",
- "print\"(i) The current gain is\",B\n",
- "print\"(ii) The input resistance Rbe is\",Rbe,\"ohm\"\n",
- "print\"(iii) The transconductance Gm is\",Gm,\"S\"\n",
- "print\"(iv) Voltage gain Av is\",Av"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) The current gain is 112.5\n",
- "(ii) The input resistance Rbe is 750.0 ohm\n",
- "(iii) The transconductance Gm is 0.15 S\n",
- "(iv) Voltage gain Av is 720.0\n"
- ]
- }
- ],
- "prompt_number": 28
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |