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-{
- "metadata": {
- "name": "",
- "signature": "sha256:64e0a844a3ba33dead720cfb202f40f7dab27e1a9fab7ab4975bb30624a36195"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 31 Radioactivity"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.1 Page no 855"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "T=138.0 #days\n",
- "E=0.693\n",
- "N=12.5\n",
- "N0=100\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "L=E/T\n",
- "N1=N/N0\n",
- "t=(2.303*math.log10(8))/L\n",
- "\n",
- "#Result\n",
- "print\"Time is\",round(t,2),\"days\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Time is 414.16 days\n"
- ]
- }
- ],
- "prompt_number": 71
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.2 Page no 855"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "T=1.42*10**17 #s\n",
- "A=6.02*10**23 #mol**-1\n",
- "E=0.693\n",
- "L=238.0\n",
- "\n",
- "#Calculation\n",
- "N=A/L\n",
- "L1=E/T\n",
- "Z=L1*N\n",
- "\n",
- "#Result\n",
- "print\"Disintegrations per second occur in 1g of U**238 is\",round(Z*10**-4,3),\"*10**4 s**-1\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Disintegrations per second occur in 1g of U**238 is 1.234 *10**4 s**-1\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.3 Page no 855"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "K=-40 #Cl\n",
- "M=0.075 #kg mole**-1\n",
- "m=1.2*10**-6 #kg\n",
- "A=6.0*10**23\n",
- "D=170 #s**-1\n",
- "E=0.693\n",
- "\n",
- "#Calculation\n",
- "N=(A/M)*m\n",
- "L=D/N\n",
- "T=(E/L)\n",
- "O=T/31536000.0\n",
- "\n",
- "#Result\n",
- "print\"Half life of K40 atom is\",round(O*10**-9,3),\"*10**9 years\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Half life of K40 atom is 1.241 *10**9 years\n"
- ]
- }
- ],
- "prompt_number": 81
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.4 Page no 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "T=6.0 #hours\n",
- "E=0.693\n",
- "A=6.025*10**23\n",
- "W=99.0\n",
- "S=10**-12\n",
- "t=1 #hours\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "L=E/T\n",
- "N0=(A/W)*S\n",
- "R0=L*N0\n",
- "N=N0*math.exp(-L)\n",
- "R=L*N\n",
- "R1=L*N\n",
- "\n",
- "#Result\n",
- "print\"Activity at beginning is\", round(R0*10**-8,2),\"*10**8 /h\"\n",
- "print\"Activity at the end is\",round(R1*10**-8,3),\"*10**8 /h\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Activity at beginning is 7.03 *10**8 /h\n",
- "Activity at the end is 6.262 *10**8 /h\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.5 Page no 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "t=30.0 #years\n",
- "a=16\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "l=(2.3026*math.log10(a))/t\n",
- "T=0.693/l\n",
- "\n",
- "#Result\n",
- "print\"Half life period is\", round(T,1),\"years\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Half life period is 7.5 years\n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.6 Page no 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m1=238.05081\n",
- "m2=234.04363\n",
- "m3=4.00260\n",
- "A=931.5 #Mev\n",
- "\n",
- "#Calculation\n",
- "Ea=(m1-m2-m3)*A\n",
- "\n",
- "#Result\n",
- "print\"Kinetic energy is\",round(Ea,2),\"Mev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Kinetic energy is 4.27 Mev\n"
- ]
- }
- ],
- "prompt_number": 25
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.7 Page no 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m1=22.994466\n",
- "m2=22.989770\n",
- "A=931.5\n",
- "\n",
- "#Calculation\n",
- "Eb=(m1-m2)*A\n",
- "\n",
- "#Result\n",
- "print\"Maximum kinetic energy is\",round(Eb,3),\"Mev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum kinetic energy is 4.374 Mev\n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.8 Page no 856"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E1=0\n",
- "E2=0.412*1.6*10**-13\n",
- "E3=1.088*1.6*10**-13\n",
- "h=6.62*10**-34\n",
- "m1=197.968233\n",
- "m2=197.966760\n",
- "a=931.5\n",
- "A=1.088\n",
- "A1=0.412\n",
- "\n",
- "#Calculation\n",
- "v1=(E3-E1)/h\n",
- "v2=(E2-E1)/h\n",
- "v3=(E3-E2)/h\n",
- "Eb1=((m1-m2)*a)-A\n",
- "Eb2=((m1-m2)*a)-A1\n",
- "\n",
- "#Result\n",
- "print\"Radiation frequencies are\",round(v1*10**-20,2)*10**20,\",\",round(v2*10**-20,3)*10**20,\"and\",round(v3*10**-20,2)*10**20\n",
- "print\"Maximum kinetic energies are\",round(Eb1,3),\"Mev and \",round(Eb2,3),\"Mev\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Radiation frequencies are 2.63e+20 , 9.96e+19 and 1.63e+20\n",
- "Maximum kinetic energies are 0.284 Mev and 0.96 Mev\n"
- ]
- }
- ],
- "prompt_number": 42
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 31.9 Page no 857"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=15\n",
- "b=9.0\n",
- "T=5730\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "A=a/b\n",
- "l=2.303*math.log10(A)\n",
- "t=(l*T)/0.693\n",
- "\n",
- "#Result\n",
- "print\"Approximation age of the indus valley civilization is\",round(t,2),\"years\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Approximation age of the indus valley civilization is 4224.47 years\n"
- ]
- }
- ],
- "prompt_number": 46
- }
- ],
- "metadata": {}
- }
- ]
-} \ No newline at end of file