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Diffstat (limited to 'modern_physics_by_Satish_K._Gupta/chap26.ipynb')
| -rwxr-xr-x | modern_physics_by_Satish_K._Gupta/chap26.ipynb | 239 |
1 files changed, 0 insertions, 239 deletions
diff --git a/modern_physics_by_Satish_K._Gupta/chap26.ipynb b/modern_physics_by_Satish_K._Gupta/chap26.ipynb deleted file mode 100755 index 26f66f05..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap26.ipynb +++ /dev/null @@ -1,239 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:010c48e259f2faa6331c5ac2dae668d950f9fc1e120bf60a20ed01cae899383a"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 26 Diffraction of light"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 26.1 Page no 747"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=0.5*10**-3 #m\n",
- "l=6000*10**-10 \n",
- "D=2\n",
- "\n",
- "#Calculation\n",
- "d=2*D*l/a\n",
- "\n",
- "#Result\n",
- "print\"Distance between the two dark bands is\",d*10**3,\"mm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Distance between the two dark bands is 4.8 mm\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 26.2 Page no 747"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "l=5900*10**-10 #m\n",
- "a=11.8*10**-7\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "a=l/a\n",
- "A=math.asin(a)*180/3.14\n",
- "A1=2*A\n",
- "\n",
- "#Result\n",
- "print\"Angular position is\",round(A1,0),\"degree\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Angular position is 60.0 degree\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 26.3 Page no 747 "
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "l=650*10**-9\n",
- "a1=30 #degree\n",
- "\n",
- "#Calculation\n",
- "a=l/math.sin(a1*3.14/180.0)\n",
- "a2=3*l/math.sin(a1*3.14/180.0)\n",
- "\n",
- "#Result\n",
- "print\"(a) Value of a when the 1st min. falls at 30 degree is\",round(a*10**6,1)*10**-6,\"m\"\n",
- "print\"(b) Value of a when the 1st max. falls at 30 degree is\",round(a2*10**6,2)*10**-6,\"m\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Value of a when the 1st min. falls at 30 degree is 1.3e-06 m\n",
- "(b) Value of a when the 1st max. falls at 30 degree is 3.9e-06 m\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 26.4 Page no 747"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "l=600.0*10**-9 #m\n",
- "a=2*10**-3 \n",
- "\n",
- "#Calculation\n",
- "Z=a**2/l\n",
- "\n",
- "#Result\n",
- "print\"Distance is\",round(Z,2),\"m\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Distance is 6.67 m\n"
- ]
- }
- ],
- "prompt_number": 19
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 26.5 Page no 747"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "d=4.6*10**-6 #rad\n",
- "l=5460*10**-10 #m\n",
- "\n",
- "#Calculation\n",
- "D=1.22*l/d\n",
- "\n",
- "#Result\n",
- "print\"Aperture of the objective of the telescope is\",round(D,4),\"m\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Aperture of the objective of the telescope is 0.1448 m\n"
- ]
- }
- ],
- "prompt_number": 24
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 26.6 Page no 748"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "lr=660\n",
- "\n",
- "#Calculation\n",
- "l1=2*lr/3.0\n",
- "\n",
- "#Result\n",
- "print\"Value of lembda is\",l1,\"nm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Value of lembda is 440.0 nm\n"
- ]
- }
- ],
- "prompt_number": 26
- }
- ],
- "metadata": {}
- }
- ]
-}
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