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Diffstat (limited to 'modern_physics_by_Satish_K._Gupta/chap26.ipynb')
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diff --git a/modern_physics_by_Satish_K._Gupta/chap26.ipynb b/modern_physics_by_Satish_K._Gupta/chap26.ipynb new file mode 100644 index 00000000..26f66f05 --- /dev/null +++ b/modern_physics_by_Satish_K._Gupta/chap26.ipynb @@ -0,0 +1,239 @@ +{
+ "metadata": {
+ "name": "",
+ "signature": "sha256:010c48e259f2faa6331c5ac2dae668d950f9fc1e120bf60a20ed01cae899383a"
+ },
+ "nbformat": 3,
+ "nbformat_minor": 0,
+ "worksheets": [
+ {
+ "cells": [
+ {
+ "cell_type": "heading",
+ "level": 1,
+ "metadata": {},
+ "source": [
+ "Chapter 26 Diffraction of light"
+ ]
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 26.1 Page no 747"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "a=0.5*10**-3 #m\n",
+ "l=6000*10**-10 \n",
+ "D=2\n",
+ "\n",
+ "#Calculation\n",
+ "d=2*D*l/a\n",
+ "\n",
+ "#Result\n",
+ "print\"Distance between the two dark bands is\",d*10**3,\"mm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Distance between the two dark bands is 4.8 mm\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 26.2 Page no 747"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "l=5900*10**-10 #m\n",
+ "a=11.8*10**-7\n",
+ "\n",
+ "#Calculation\n",
+ "import math\n",
+ "a=l/a\n",
+ "A=math.asin(a)*180/3.14\n",
+ "A1=2*A\n",
+ "\n",
+ "#Result\n",
+ "print\"Angular position is\",round(A1,0),\"degree\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Angular position is 60.0 degree\n"
+ ]
+ }
+ ],
+ "prompt_number": 10
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 26.3 Page no 747 "
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "l=650*10**-9\n",
+ "a1=30 #degree\n",
+ "\n",
+ "#Calculation\n",
+ "a=l/math.sin(a1*3.14/180.0)\n",
+ "a2=3*l/math.sin(a1*3.14/180.0)\n",
+ "\n",
+ "#Result\n",
+ "print\"(a) Value of a when the 1st min. falls at 30 degree is\",round(a*10**6,1)*10**-6,\"m\"\n",
+ "print\"(b) Value of a when the 1st max. falls at 30 degree is\",round(a2*10**6,2)*10**-6,\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "(a) Value of a when the 1st min. falls at 30 degree is 1.3e-06 m\n",
+ "(b) Value of a when the 1st max. falls at 30 degree is 3.9e-06 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 3
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 26.4 Page no 747"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "l=600.0*10**-9 #m\n",
+ "a=2*10**-3 \n",
+ "\n",
+ "#Calculation\n",
+ "Z=a**2/l\n",
+ "\n",
+ "#Result\n",
+ "print\"Distance is\",round(Z,2),\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Distance is 6.67 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 19
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 26.5 Page no 747"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "d=4.6*10**-6 #rad\n",
+ "l=5460*10**-10 #m\n",
+ "\n",
+ "#Calculation\n",
+ "D=1.22*l/d\n",
+ "\n",
+ "#Result\n",
+ "print\"Aperture of the objective of the telescope is\",round(D,4),\"m\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Aperture of the objective of the telescope is 0.1448 m\n"
+ ]
+ }
+ ],
+ "prompt_number": 24
+ },
+ {
+ "cell_type": "heading",
+ "level": 2,
+ "metadata": {},
+ "source": [
+ "Example 26.6 Page no 748"
+ ]
+ },
+ {
+ "cell_type": "code",
+ "collapsed": false,
+ "input": [
+ "#Given\n",
+ "lr=660\n",
+ "\n",
+ "#Calculation\n",
+ "l1=2*lr/3.0\n",
+ "\n",
+ "#Result\n",
+ "print\"Value of lembda is\",l1,\"nm\""
+ ],
+ "language": "python",
+ "metadata": {},
+ "outputs": [
+ {
+ "output_type": "stream",
+ "stream": "stdout",
+ "text": [
+ "Value of lembda is 440.0 nm\n"
+ ]
+ }
+ ],
+ "prompt_number": 26
+ }
+ ],
+ "metadata": {}
+ }
+ ]
+}
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