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Diffstat (limited to 'modern_physics_by_Satish_K._Gupta/chap2.ipynb')
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diff --git a/modern_physics_by_Satish_K._Gupta/chap2.ipynb b/modern_physics_by_Satish_K._Gupta/chap2.ipynb deleted file mode 100755 index efbea0a7..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap2.ipynb +++ /dev/null @@ -1,534 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:1e2d45d8326c66f64e42e0f8f482f41d5aabf3a1eabc7e50f07a0c18121fe999"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 2 Electric field"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.1 Page no 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=10**-7 #Kg\n",
- "q=1.6*10**-19 #C\n",
- "g=9.8\n",
- "\n",
- "#Calculation\n",
- "E=(m*g)/q\n",
- "\n",
- "#Result\n",
- "print\"Electric field strength required is\", E"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electric field strenght required is 6.125e+12\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.2 Page no 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=10.0**-3 #Kg\n",
- "q=5*10**-6 #C\n",
- "u=20 #m/s\n",
- "E=2*10**5 #N/C\n",
- "\n",
- "#Calculation\n",
- "F=q*E\n",
- "a=-F/m\n",
- "S=-u**2/(2.0*a)\n",
- "\n",
- "#Result\n",
- "print\"Distance travelled is\", S,\"m\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Distance travelled is 0.2 m\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.3 Page no 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=2.55*10**4 #V/m\n",
- "a=1.26*10**3 #Kg/m**4\n",
- "g=9.81 #m/s**2\n",
- "e=1.6*10**-19\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "q=12*e\n",
- "Fe=q*E\n",
- "r=((3*Fe)/(4.0*math.pi*a*g))**0.333\n",
- "\n",
- "#Result\n",
- "print\"The radius of the drop is\", round(r*10**4,5)*10**3,\"*10**-4 mm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The radius of the drop is 9.95 *10**-4 mm\n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.4 Page no 39"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=80.0*10**-6 #Kg\n",
- "q=2*10**-8 #C\n",
- "E=20000 #V/m\n",
- "g=9.8\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "a=(q*E)/(m*g)\n",
- "a1=math.atan(a)*180/3.14\n",
- "T=(q*E)/(math.sin(a1*3.14/180.0))\n",
- "\n",
- "#Result\n",
- "print\"Tension in the thread of the pendulum is\", round(T*10**4,1),\"*10**-4 N\"\n",
- "print\"Angle it make with the vertical is\",round(a1,2),\"Degree C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Tension in the thread of the pendulum is 8.8 *10**-4 N\n",
- "Angle it make with the vertical is 27.04 Degree C\n"
- ]
- }
- ],
- "prompt_number": 41
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.5 Page no 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "q1=2.0*10**-7 #C\n",
- "q2=1.0*10**-7 #C\n",
- "r=10.0**-2 #m\n",
- "m=9*10**9\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "E1=(m*q1)/r**2\n",
- "E2=(m*q2)/r**2\n",
- "\n",
- "#Result\n",
- "print\"Magnitude of field E1 is\", E1*10**-7,\"*10**7 N/C\"\n",
- "print\"Magnitude of field E2 is\", E2*10**-6,\"*10**6 N/C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Magnitude of field E1 is 1.8 *10**7 N/C\n",
- "Magnitude of field E2 is 9.0 *10**6 N/C\n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.6 Page no 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "q1=5.0*10**-19 #c\n",
- "q2=20*10**-19\n",
- "r=2.0 #m\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "x=-math.sqrt(q2/q1)\n",
- "x1=math.sqrt(q2/(q1*3))\n",
- "\n",
- "#Result\n",
- "print\"The point on the line joining is\", round(x,1),\"m and \",round(x1,1),\"m\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The point on the line joining is -2.0 m and 1.2 m\n"
- ]
- }
- ],
- "prompt_number": 60
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.7 Page no 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "r=0.2\n",
- "m=9*10**9\n",
- "qa=3*10**-6\n",
- "q=1.5*10**-9\n",
- "\n",
- "#Calculation\n",
- "a=r/2.0\n",
- "Ea=(m*qa)/a**2\n",
- "Eb=(m*qa)/a**2\n",
- "E=Ea+Eb\n",
- "F=q*E\n",
- "\n",
- "#Result\n",
- "print\"(a) Electric field at the mid point is\", E*10**-6,\"*10**6 N/C (along OB)\"\n",
- "print\"(b) Force experienced by the test charge is\",F*10**3,\"*10**-3 N (along OA)\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Electric field at the mid point is 5.4 *10**6 N/C (along OB)\n",
- "(b) Force experienced by the test charge is 8.1 *10**-3 N (along OA)\n"
- ]
- }
- ],
- "prompt_number": 71
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.8 Page no 40"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "qa=16*10**-6 #c\n",
- "qb=-9.0*10**-6 #C\n",
- "r=0.08 #m\n",
- "\n",
- "#Calculation\n",
- "x=-(qa/qb)*r\n",
- "\n",
- "#Result\n",
- "print\"Position of the point is\", round(x,2),\"m\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Position of the point is 0.14 m\n"
- ]
- }
- ],
- "prompt_number": 82
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.9 Page no 41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "m=9*10**9\n",
- "qa=4*10**-6\n",
- "r=2.0*10**-2\n",
- "r1=10**-2\n",
- "qb=2*10**-6\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Ea=(m*qa)/r**2\n",
- "Eb=(m*qb)/r1**2\n",
- "a=r1/r\n",
- "E=math.sqrt(Ea**2+Eb**2+(2*Ea*Eb*a))\n",
- "a11=Ea*(math.sin(60)*180/3.14)/(Ea+Eb*(math.cos(60)*180/3.14))\n",
- "\n",
- "#Result\n",
- "print\"Position is\", round(a11,2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Position is 0.16\n"
- ]
- }
- ],
- "prompt_number": 33
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.10 Page no 41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "q=500*10**-6\n",
- "r=0.1 #m\n",
- "d=0.2\n",
- "m=9*10**9\n",
- "\n",
- "#Calculation\n",
- "p=q*r\n",
- "a=r/2.0\n",
- "R=d+a\n",
- "E=(m*2*p*R)/((R**2-a**2)**2)\n",
- "\n",
- "#Result\n",
- "print\"Electric dipole moment of the dipole is\", p,\"Cm\"\n",
- "print\"Electric field due to dipole is\",E*10**-7,\"*10**7 N/C\"\n"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electric dipole moment of the dipole is 5e-05 Cm\n",
- "Electric field due to dipole is 6.25 *10**7 N/C\n"
- ]
- }
- ],
- "prompt_number": 21
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.11 Page no 41"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "q=0.2*10**-12 #C\n",
- "w=10**-8 #m\n",
- "r=0.1 #m\n",
- "e=9*10**9\n",
- "\n",
- "#Calculation\n",
- "p=q*w\n",
- "E=(e*2*p)/r**3\n",
- "\n",
- "#Result\n",
- "print\"The electric field at an axical point at a distance of 10cm from there mid point is\", E*10**8,\"*10**-8 N/C\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The electric field at an axical point at a distance of 10cm from there mid point is 3.6 *10**-8 N/C\n"
- ]
- }
- ],
- "prompt_number": 1
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.13 Page no 42"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=10.0**4\n",
- "t=9*10**-26 #Nm\n",
- "\n",
- "#Calculation\n",
- "import math \n",
- "p=t/(E*math.sin(30*3.14/180.0))\n",
- "\n",
- "#Result\n",
- "print\"Dipole moment of the dipole is\", round(p*10**29,1),\"*10**-19 Cm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Dipole moment of the dipole is 1.8 *10**-19 Cm\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 2.17 Page no 43"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "p=-10**-7 #Cm\n",
- "i=10**5\n",
- "\n",
- "#Calculation\n",
- "F=p*i\n",
- "\n",
- "#Result\n",
- "print\"Force is given by\", F,\"N\"\n",
- "print\"Torque is zero\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Force is given by -0.01 N\n",
- "Torque is zero\n"
- ]
- }
- ],
- "prompt_number": 15
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |