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Diffstat (limited to 'modern_physics_by_Satish_K._Gupta/chap19.ipynb')
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diff --git a/modern_physics_by_Satish_K._Gupta/chap19.ipynb b/modern_physics_by_Satish_K._Gupta/chap19.ipynb deleted file mode 100755 index 6e89d5a2..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap19.ipynb +++ /dev/null @@ -1,640 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:c81057d61d55f846d72bc0a6263de0452d74cd37dd94b021ce01d87a17a0c974"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 19 Electrical machines and devices"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.1 Page no 582"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ep=2300.0 #v\n",
- "Np=4000\n",
- "Es=230 #v\n",
- "\n",
- "#Calculation\n",
- "Ns=Np*(Es/Ep)\n",
- "\n",
- "#Result\n",
- "print\"Number of turns is\", Ns"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Number of turns is 400.0\n"
- ]
- }
- ],
- "prompt_number": 2
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.2 Page no 582"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Ep=220.0 #v\n",
- "Es=110\n",
- "E=550 #watt\n",
- "\n",
- "#Calculation\n",
- "Ip=E/Ep\n",
- "\n",
- "#Result\n",
- "print\"Current drawn is\",Ip,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current drawn is 2.5 A\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.3 Page no 582"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Gien\n",
- "Ep=220.0 #v\n",
- "Es=22 \n",
- "Z=220.0 #ohm\n",
- "\n",
- "#Calculation\n",
- "Is=Es/Z\n",
- "Ip=(Es/Ep)*Is\n",
- "\n",
- "#Result\n",
- "print\"Current drawn is\",Ip,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Current drawn is 0.01 A\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.4 Page no 582"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Np=200.0\n",
- "Ns=1000\n",
- "Ep=200.0 #v\n",
- "E=10**4 #W\n",
- "\n",
- "#Calculation\n",
- "Es=(Ns/Np)*Ep\n",
- "Ip=E/Ep\n",
- "\n",
- "#Result\n",
- "print\"(a) Output voltage is\",Es,\"V\"\n",
- "print\"(b) Current is\",Ip,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Output voltage is 1000.0 V\n",
- "(b) Current is 50.0 A\n"
- ]
- }
- ],
- "prompt_number": 12
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.5 Page no 582"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "ep=120\n",
- "Ip=1.85 #A\n",
- "Is=150*10**-3\n",
- "n=0.95\n",
- "\n",
- "#Calculation\n",
- "es=n*ep*Ip/Is\n",
- "\n",
- "#result\n",
- "print\"Voltage across the secondary is\",es,\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Voltage across the secondary is 1406.0 V\n"
- ]
- }
- ],
- "prompt_number": 14
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.6 Page no 582"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "K=100\n",
- "Np=100\n",
- "e=1100 #watt\n",
- "ep=220.0\n",
- "\n",
- "#Calculation\n",
- "Ns=K*Np\n",
- "ip=e/ep\n",
- "es=K*ep\n",
- "Is=ip*ep/es\n",
- "\n",
- "#Result\n",
- "print\"(i) Number of turns is\",Ns\n",
- "print\"(ii) Current is\",ip,\"A\"\n",
- "print\"(iii) Voltage across the secondary is\",es,\"V\"\n",
- "print\"(iv) Current in the secondaryis\",Is,\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Number of turns is 10000\n",
- "(ii) Current is 5.0 A\n",
- "(iii) Voltage across the secondary is 22000.0 V\n",
- "(iv) Current in the secondaryis 0.05 A\n"
- ]
- }
- ],
- "prompt_number": 23
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.7 Page no 583"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "e=11000 #W\n",
- "es=220.0 #V\n",
- "es1=22000.0\n",
- "\n",
- "#Calculation\n",
- "Is=e/es\n",
- "V=Is**2\n",
- "Is1=e/es1\n",
- "P=Is1**2\n",
- "\n",
- "#Result\n",
- "print\"(i) Electrical energy dissipated when power is transmitted at es=220 V is\",V,\"R watt\"\n",
- "print\"(ii)Electrical energy dissipated when power is transmitted at es=22000 V is\",P,\"R watt\"\n",
- "print\"Transmission should be done at 22000 V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Electrical energy dissipated when power is transmitted at es=220 V is 2500.0 R watt\n",
- "(ii)Electrical energy dissipated when power is transmitted at es=22000 V is 0.25 R watt\n",
- "Transmission should be done at 22000 V\n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.8 Page no 583"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "B=0.1 #T\n",
- "n=2000\n",
- "A=0.05 #m**2\n",
- "w=2100 #r.p.m.\n",
- "\n",
- "#calculation\n",
- "import math\n",
- "A1=2*math.pi*w/60.0\n",
- "e0=w*B*A*A1\n",
- "e=e0*math.sin(60*3.14/180.0)\n",
- "\n",
- "#Result\n",
- "print\"Maximum e.m.f is\", round(e0,0),\"V\"\n",
- "print\"Instantaneous e.m.f is\",round(e,0),\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Maximum e.m.f is 2309.0 V\n",
- "Instantaneous e.m.f is 1999.0 V\n"
- ]
- }
- ],
- "prompt_number": 50
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.9 Page no 583"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "n=100\n",
- "A=3 #m**2\n",
- "w=60 #rad/s\n",
- "B=0.04\n",
- "R=500.0\n",
- "\n",
- "#Calculation\n",
- "e0=n*B*A*w\n",
- "I0=e0/R\n",
- "P=e0*I0\n",
- "\n",
- "#Result\n",
- "print\"(a) Maximum current is\",I0,\"A\"\n",
- "print\"(b) Maximum power is\",P,\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Maximum current is 1.44 A\n",
- "(b) Maximum power is 1036.8 W\n"
- ]
- }
- ],
- "prompt_number": 56
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.10 Page no 583"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "n=50\n",
- "A=2.5 #m**2\n",
- "w=60 #rad/s\n",
- "B=0.30\n",
- "R=500.0\n",
- "\n",
- "#Calculation\n",
- "e0=n*B*A*w\n",
- "I0=e0/R\n",
- "\n",
- "#Result\n",
- "print\"(a) The maximum current is\",I0,\"A\"\n",
- "print\"(b) Current is zero when coil is vertical and flux is maximum.On the other hand current is maximum when coil is horizontal,flux is minimum\"\n",
- "print\"(c) Yes,there should be relative motion between the magnetic field and coil\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) The maximum current is 4.5 A\n",
- "(b) Current is zero when coil is vertical and flux is maximum.On the other hand current is maximum when coil is horizontal,flux is minimum\n",
- "(c) Yes,there should be relative motion between the magnetic field and coil\n"
- ]
- }
- ],
- "prompt_number": 60
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.11 Page no 583"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "E=220\n",
- "e=200.0\n",
- "P=5000\n",
- "\n",
- "#Calculation\n",
- "I=P/e\n",
- "R=(E-e)/I\n",
- "\n",
- "#Result\n",
- "print\"Armature current is\",I,\"A\"\n",
- "print\"Motor resistance is\",R,\"ohm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Armature current is 25.0 A\n",
- "Motor resistance is 0.8 ohm\n"
- ]
- }
- ],
- "prompt_number": 65
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.12 Page no 583"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=8.5\n",
- "E=200\n",
- "I=5\n",
- "\n",
- "#Calculation\n",
- "e=E-(I*R)\n",
- "Pi=E*I\n",
- "Po=E*I-(I**2*R)\n",
- "n=Po/Pi\n",
- "\n",
- "#Result\n",
- "print\"Back e.m.f of the motor is\", e,\"V\"\n",
- "print\"Power input is\",Pi,\"W\"\n",
- "print\"Power output is\",Po,\"W\"\n",
- "print\"Efficiencyis\",n*10**2,\"%\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Back e.m.f of the motor is 157.5 V\n",
- "Power input is 1000 W\n",
- "Power output is 787.5 W\n",
- "Efficiencyis 78.75 %\n"
- ]
- }
- ],
- "prompt_number": 78
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.13 Page no 584"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "h=300\n",
- "g=9.8 #m/s**2\n",
- "a=1000\n",
- "A=100.0\n",
- "n=60\n",
- "\n",
- "#Calculation\n",
- "m=A*a\n",
- "E=m*g*h\n",
- "P=E*n/A\n",
- "\n",
- "#Result\n",
- "print\"Electric power is\", P*10**-6,\"MW\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Electric power is 176.4 MW\n"
- ]
- }
- ],
- "prompt_number": 84
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.14 Page no 584"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "L=30 #km\n",
- "R=15 #ohm\n",
- "V=4000.0 #V\n",
- "P=8*10**5 #W\n",
- "\n",
- "#Calculation\n",
- "Is=P/V\n",
- "P1=Is**2*R\n",
- "P2=P+P1\n",
- "V1=R*Is\n",
- "A=440-(V+V1)\n",
- "\n",
- "#Result\n",
- "print\"(a) Line power loss is\",P1*10**-3,\"KW\"\n",
- "print\"(b) Supplied power is\",P2*10**-3,\"KW\"\n",
- "print\"(c) Step up transformer at the plane is\",A"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Line power loss is 600.0 KW\n",
- "(b) Supplied power is 1400.0 KW\n",
- "(c) Step up transformer at the plane is -6560.0\n"
- ]
- }
- ],
- "prompt_number": 94
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 19.15 Page no 584"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "r=8*10**-2\n",
- "n=20\n",
- "w=50 #rad/s\n",
- "B=3*10**-2 #T\n",
- "A=64*math.pi*10**-4 #m**2\n",
- "Eav=0\n",
- "R=10 #ohm\n",
- "\n",
- "#Calculation\n",
- "math.pi\n",
- "e0=n*B*A*w\n",
- "Pav=e0**2/(2*R)\n",
- "\n",
- "#Result\n",
- "print\" Maximum e.m.f. is\",round(e0,4),\"V\"\n",
- "print\" Average e.m.f. is zero\"\n",
- "print\" Dissipated power is\",round(Pav,4),\"W\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- " Maximum e.m.f. is 0.6032 V\n",
- " Average e.m.f. is zero\n",
- " Dissipated power is 0.0182 W\n"
- ]
- }
- ],
- "prompt_number": 103
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |