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Diffstat (limited to 'modern_physics_by_Satish_K._Gupta/chap14.ipynb')
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diff --git a/modern_physics_by_Satish_K._Gupta/chap14.ipynb b/modern_physics_by_Satish_K._Gupta/chap14.ipynb deleted file mode 100755 index 9106ddd9..00000000 --- a/modern_physics_by_Satish_K._Gupta/chap14.ipynb +++ /dev/null @@ -1,635 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:04d8806c560b3bd07d87813351e39839b8f2c2b391de8dcf1afa3dc83f2be11d"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 14 Earths magnetism"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.3 Page no 433"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=60 #Degree\n",
- "Bh=0.16 #G\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "B=Bh/cos(a*3.14/180.0)\n",
- "\n",
- "#Result\n",
- "print\"Magnitude of earth's field is\", round(B,2),\"G\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Magnitude of earth's field is 0.32 G\n"
- ]
- }
- ],
- "prompt_number": 4
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.4 Page no 434"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a=60\n",
- "a2=45\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "a1=math.tan(a2*3.14/180.0)/math.cos(a*3.14/180.0)\n",
- "a3=math.atan(a1)*180/3.14\n",
- "\n",
- "#Result\n",
- "print\"Apparent value of the dip is\", round(a3,1),\"degree\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Apparent value of the dip is 63.4 degree\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.6 Page no 434"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "l=30 #cm\n",
- "l=0.15 #m\n",
- "r=0.30 #m\n",
- "Bh=0.34*10**-4 #T\n",
- "u=10**-7\n",
- "\n",
- "#Calculation\n",
- "M=Bh*(r**2-l**2)**2/(2*u*r)\n",
- "m=M/(2*l)\n",
- "\n",
- "#Result\n",
- "print\"Pole strength of the magnet is\",m,\"Am\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Pole strength of the magnet is 8.60625 Am\n"
- ]
- }
- ],
- "prompt_number": 16
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.7 Page no 434"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "M=0.4 #Am**2\n",
- "r=0.1 #m\n",
- "l=0.05 #m\n",
- "u=10**-7\n",
- "\n",
- "#Calculation\n",
- "Bh=u*M/((r**2+l**2)**1.5)\n",
- "\n",
- "#Result\n",
- "print\"Horizontal component of earth's magnetic field is\", round(Bh*10**4,3)*10**-4,\"T\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Horizontal component of earth's magnetic field is 2.86e-05 T\n"
- ]
- }
- ],
- "prompt_number": 22
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.8 Page no 435"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "B=0.33\n",
- "a=0\n",
- "u=10**-7\n",
- "I=2.5 #A\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Bh=B/math.cos(a*3.14/180.0)\n",
- "a=u*2*I/(Bh*10**-4)\n",
- "\n",
- "#Result\n",
- "print\"Neutral point is\", round(a*10**2,1),\"cm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Neutral point is 1.5 cm\n"
- ]
- }
- ],
- "prompt_number": 28
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.9 Page no 435"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "Bh=0.32 #G\n",
- "B=0.48 \n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "a=B/Bh\n",
- "a1=math.atan(a)*180/3.14\n",
- "\n",
- "#Result\n",
- "print\"New stable equilibrium is\", round(a1,1),\"degree\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "New stable equilibrium is 56.3 degree\n"
- ]
- }
- ],
- "prompt_number": 32
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 4.10 Page no 435"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "n=22\n",
- "a=0.1 #m\n",
- "Bh=0.3*10**-4 #T\n",
- "u=10**-7\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "K=2*a*Bh/(n*4*math.pi*u)\n",
- "\n",
- "#Result\n",
- "print\"Reduction factor is\", round(K,3),\"A\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Reduction factor is 0.217 A\n"
- ]
- }
- ],
- "prompt_number": 36
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.11 Page no 435"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "n=40\n",
- "a=0.12\n",
- "I=0.15\n",
- "a1=45 #degree\n",
- "u=10**-7\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Bh=(n*u*4*math.pi*I)/(2.0*a*math.tan(a1*3.14/180.0))\n",
- "\n",
- "#Result\n",
- "print\"Strength of horizontal component is\", round(Bh*10**4,3),\"*10**-4 T\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Strength of horizontal component is 0.314 *10**-4 T\n"
- ]
- }
- ],
- "prompt_number": 51
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.12 Page no 435"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a1=30\n",
- "a2=45 #degree\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "n=2*math.tan(a1*3.14/180.0)/(math.tan(a2*3.14/180.0))\n",
- "\n",
- "#Result\n",
- "print\"Ratio of number of turns is\", round(n,3)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Ratio of number of turns is 1.155\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.13 Page no 436"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "n=16\n",
- "a=0.1 #m\n",
- "i=0.75 #A\n",
- "Bh=5*10**-2 #T\n",
- "v=2 #/s\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "M=n*i*math.pi*a**2\n",
- "I=M*Bh/(4*math.pi**2*v**2)\n",
- "\n",
- "#Result\n",
- "print\"Moment of inertia is\",round(I*10**4,3),\"*10**-4 Kg m**2\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Moment of inertia is 1.194 *10**-4 Kg m**2\n"
- ]
- }
- ],
- "prompt_number": 10
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.14 Page no 436"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "T1=2.5\n",
- "T2=4.5\n",
- "M2=1.5\n",
- "\n",
- "#Calculation\n",
- "M=T2**2/(M2*T1**2)\n",
- "\n",
- "#Result\n",
- "print\"Ratio of magnetic moment is\",M"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Ratio of magnetic moment is 2.16\n"
- ]
- }
- ],
- "prompt_number": 11
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.15 Page no 436"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "T1=3.0\n",
- "T2=4.0\n",
- "\n",
- "#Calculation\n",
- "M=(T2**2+T1**2)/(T2**2-T1**2)\n",
- "\n",
- "#Result\n",
- "print\"Ratio of magnetic moments is\",round(M,2)"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Ratio of magnetic moments is 3.57\n"
- ]
- }
- ],
- "prompt_number": 15
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.16 Page no 436"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "a1=35 #Degree\n",
- "B=0.39\n",
- "I=1 #A\n",
- "a=4.0*10**-2\n",
- "u=10**-7\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Bh=B*math.cos(a1*3.14/180.0)\n",
- "Bv=B*math.sin(a1*3.14/180.0)\n",
- "B1=(u*2*I*4/a)*10**4\n",
- "Rh=Bh-B1\n",
- "R=math.sqrt(Rh**2+Bv**2)\n",
- "Rh1=Bh+B1\n",
- "R3=math.sqrt(Rh1**2+Bv**2)\n",
- "\n",
- "#Result\n",
- "print\"Resultant magnetic field is\", round(R3,3),\"G\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Resultant magnetic field is 0.566 G\n"
- ]
- }
- ],
- "prompt_number": 39
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.17 Page no 436"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "M=5.25*10**-2 #J/T\n",
- "Bh=0.42*10**-4 #T\n",
- "u=10**-7\n",
- "\n",
- "#Calculation\n",
- "r=(u*M/Bh)**0.333\n",
- "r1=(u*2*M/Bh)**0.333\n",
- "\n",
- "#Result\n",
- "print\"(a) Distance from the centre of the magnet on its normal bisector is\", round(r*10**2,1),\"cm\"\n",
- "print\"(b) Distance from the centre of the magnet on its axis is\",round(r1*10**2,1),\"cm\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Distance from the centre of the magnet on its normal bisector is 5.0 cm\n",
- "(b) Distance from the centre of the magnet on its axis is 6.3 cm\n"
- ]
- }
- ],
- "prompt_number": 51
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.18 Page no 437"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "I=0.35 #A\n",
- "n=30\n",
- "a=12.0*10**-2\n",
- "u=10**-7\n",
- "\n",
- "#Calculation\n",
- "import math\n",
- "Bh=u*2*math.pi*n*I*0.707/a\n",
- "\n",
- "#Result\n",
- "print\"(a) Horizontal component of the earth's magnetic field is\", round(Bh*10**4,2),\"G\"\n",
- "print\"(b) The needle will reverse its original direction i.e. it will point east to west.\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(a) Horizontal component of the earth's magnetic field is 0.39 G\n",
- "(b) The needle will reverse its original direction i.e. it will point east to west.\n"
- ]
- }
- ],
- "prompt_number": 60
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 14.19 Page no 437"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#given\n",
- "t1=9 #S\n",
- "t2=4.5\n",
- "Bh=0.34*10**-4 #T\n",
- "u=10**-7\n",
- "r=0.1 #m\n",
- "\n",
- "#Calculation\n",
- "Baxial=Bh*((t1**2/t2**2)-1)\n",
- "M2=Baxial*r**2/(2*u)\n",
- "\n",
- "#Result\n",
- "print\"Magnetic moment is\", M2*10**-1,\"A m**2\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Magnetic moment is 0.51 A m**2\n"
- ]
- }
- ],
- "prompt_number": 66
- }
- ],
- "metadata": {}
- }
- ]
-}
\ No newline at end of file |