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Diffstat (limited to 'electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb')
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1 files changed, 0 insertions, 247 deletions
diff --git a/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb b/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb deleted file mode 100755 index f4f36010..00000000 --- a/electronic_instrumentation_by_H_S_Kalsi/chap5.ipynb +++ /dev/null @@ -1,247 +0,0 @@ -{
- "metadata": {
- "name": "",
- "signature": "sha256:2471290ece4efb00967c01c588e1982987585cc7ba4f2523bc3d651b33c25fb9"
- },
- "nbformat": 3,
- "nbformat_minor": 0,
- "worksheets": [
- {
- "cells": [
- {
- "cell_type": "heading",
- "level": 1,
- "metadata": {},
- "source": [
- "Chapter 5 Digital voltmeters"
- ]
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.1 Page no 134"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=100.0*10**3 #ohm\n",
- "C=1.0*10**-6 #Farad\n",
- "ei=1\n",
- "t1=1 #second \n",
- "\n",
- "#Calculation\n",
- "E=(ei*t1)/(R*C)\n",
- "\n",
- "#Result\n",
- "print\"Voltage present at the output of the integrator after 1s is \", E,\"V\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Voltage present at the output of the integrator after 1s is 10.0 V\n"
- ]
- }
- ],
- "prompt_number": 6
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.2 Page no 134"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "e1=1\n",
- "er=5.0 #Volts\n",
- "t1=1 #Second\n",
- "\n",
- "#Calculation\n",
- "t2=ei*t1/er\n",
- "\n",
- "#Result\n",
- "print\"Time interval of t2 is \", t2,\"s\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Time interval of t2 is 0.2 s\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.3 Page no 134"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "R=100.0*10**3 #ohm\n",
- "C=2.0*10**-6 #farad\n",
- "e1=2 #volts\n",
- "t1=2 #S\n",
- "\n",
- "#Calculation\n",
- "e0=(e1*t1)/(R*C)\n",
- "\n",
- "#Result\n",
- "print\"The output of the integrator is \", e0,\"Volts\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The output of the integrator is 20.0 Volts\n"
- ]
- }
- ],
- "prompt_number": 5
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.4 Page no 134"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given\n",
- "e1=2 #Volts\n",
- "t1=2 #second\n",
- "e2=10.0 #Volts\n",
- "\n",
- "t2=(e1*t1)/e2\n",
- "print\"Time interval is \",t2,\"second\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "Time interval is 0.4 second\n"
- ]
- }
- ],
- "prompt_number": 8
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.5 Page no 141"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#given\n",
- "n=3\n",
- "\n",
- "#Calculation\n",
- "R=1/10.0**n\n",
- "\n",
- "#Result\n",
- "print\"The resolution is \", R"
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "The resolution is 0.001\n"
- ]
- }
- ],
- "prompt_number": 3
- },
- {
- "cell_type": "heading",
- "level": 2,
- "metadata": {},
- "source": [
- "Example 5.6 Page no 141"
- ]
- },
- {
- "cell_type": "code",
- "collapsed": false,
- "input": [
- "#Given \n",
- "n=5\n",
- "V=12.98 #Volts\n",
- "V1=1 #Volts\n",
- "V2=10 #volts\n",
- "\n",
- "#Calculation\n",
- "R=1/10.0**n\n",
- "R1=V1*R\n",
- "R2=V2*R\n",
- "\n",
- "#Result\n",
- "print\"(i) Resolution is \", R\n",
- "print\"(ii) Any reading upto 4th decimal can be displayed. \\n Hence this will be displayed as 0.6973\"\n",
- "print\"(iii) Resolution is \",R2,\"\\n Hence decimal upto 3rd decimal place can be displayed\"\n",
- "print\"therefore on a 10 V range, the reading will be 0.697 instead of 0.6973\""
- ],
- "language": "python",
- "metadata": {},
- "outputs": [
- {
- "output_type": "stream",
- "stream": "stdout",
- "text": [
- "(i) Resolution is 1e-05\n",
- "(ii) Any reading upto 4th decimal can be displayed. \n",
- " Hence this will be displayed as 0.6973\n",
- "(iii) Resolution is 0.0001 \n",
- " Hence decimal upto 3rd decimal place can be displayed\n",
- "therefore on a 10 V range, the reading will be 0.697 instead of 0.6973\n"
- ]
- }
- ],
- "prompt_number": 13
- }
- ],
- "metadata": {}
- }
- ]
-}
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